BETWEEN 运算符 mySQL PHP

Question

全部，

不确定为什么在运行以下查询时出现错误：

SELECT COUNT(R.id) AS total 
                    FROM request as R 
                    INNER JOIN users AS U ON U.uin = R.engineer_uin 
                    WHERE U.gm = 'BVG1'
                    AND R.date_received BETWEEN DATE_FORMAT(R.date_received,'%d %m %Y')='01 04 2014' AND DATE_FORMAT(NOW(),'%d %m %Y')

R.date_received 格式如下：2015-06-01 14:38:46 我只想得到 Now() 和前一年之间的结果。（在英国，我们的财政年度在四月到明年四月之间。

错误是：

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '='01 04 2014' AND DATE_FORMAT(NOW(),'%d %m %Y')
LIMIT 0, 25' at line 5

有什么想法吗？

Answer 1

您要查找的 AND 子句应如下所示：

...
AND R.date_received BETWEEN STR_TO_DATE('01,04,2014','%d,%m,%Y') AND NOW()

BETWEEN 运算符 mySQL PHP

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