++增量运算符的等价物是什么？

Question

我正试图在 Python 中找到正确的方法来完成以下任务（这与写的不一样）：

myList = ["a", "b", "c"]
myCounter = 5

for item in myList:
  print("""Really long text 
in which I need to put the next iteration of myCounter (""", myCounter++, """) followed 
by a lot more text with many line breaks
followed by the next iteration of myCounter (""", myCounter++, """) followed by even
more long text until finally we get to the next
iteration of the for loop.""", sep='')

不幸的是（至少对我而言），Python 中不存在 ++ 运算符或语句作为将变量递增 1 的方法，而是使用

myCounter += 1

当我想打印变量并同时递增它时，它的位置似乎也不起作用。我希望它第一次通过 for 循环打印 5 和 6，然后下一次打印 7 和 8，最后一次打印 9 和 10。在 Python 3 中应该如何完成？

Answer 1

我可能会考虑使用 itertools.count:

import itertools

myCounter = itertools.count(5)
for item in myList:
    print("la la la.", next(myCounter), "foo foo foo", next(myCounter))

如果您希望避免导入，您也可以很容易地编写自己的生成器来执行此类操作：

def counter(val=0):
    while True:
        yield val
        val += 1

Answer 2

我会简单地在 print 语句中使用 myCounter + 1 和 myCounter + 2，然后在它外面将 myCounter 递增 2。示例 -

myList = ["a", "b", "c"]
myCounter = 5

for item in myList:
  print("""Really long text 
in which I need to put the next iteration of myCounter (""", myCounter + 1, """) followed 
by a lot more text with many line breaks
followed by the next iteration of myCounter (""", myCounter + 2, """) followed by even
more long text until finally we get to the next
iteration of the for loop.""", sep='')
  myCounter += 2

++增量运算符的等价物是什么？

What is the equivalent of the ++ increment operator?

python

iterator

increment