RSA-2048 解密不工作 - PKCS1_OAEP "Incorrect decryption."

Question

该代码应该设置一个服务来侦听来自投票网站的连接。它是一个服务器，用于侦听来自外部（客户端）的连接。当客户端连接时，客户端等待发送版本号。一旦我的 server/listener 发送了版本号，客户端就会响应一个 256 字节的块，该块使用我提供的 public 密钥进行 RSA 2048 位加密。然后必须对该块进行解码，然后（稍后）我将读取内容。我陷入无法解密的困境：

我明白了：

starting connection...

connection from ('50.28.6.244', 35338)

sending version number...

receiving encrypted block

Traceback (most recent call last):

File "voteListener.py", line 97, in

Main(private_key)

File "voteListener.py", line 49, in Main

decodedfile = decode_msg(data, privatekey)

File "voteListener.py", line 58, in decode_msg

ciphertext = cipher.decrypt(msg)

File "C:\Python27\lib\site-packages\Crypto\Cipher\PKCS1_OAEP.py", line 227, in decrypt

raise ValueError("Incorrect decryption.")

ValueError: Incorrect decryption.

C:\Users\STEXAS\Desktop\vote>pause

Press any key to continue . . .

我的代码：

import socket
from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_OAEP
from os import path


def Main(privatekey):
    host = "0.0.0.0"
    port = 8192
    version = "VOTIFIER 1.9"
    print("starting connection...")
    while True:
        s = socket.socket()
        s.bind((host, port))
        s.listen(1)
        c, addr = s.accept()
        print("connection from %s" % str(addr))
        print("sending version number...")
        c.send(version)
        c.send('\n')

        print("receiving encrypted block")
        data = c.recv(256)
        c.close()
        s.close()
        decodedfile = decode_msg(data, privatekey)

        with open("votes.txt", 'wb') as f:
            f.write(decodedfile)
        print("File writen")


def decode_msg(ciphertext, priv_key):
    cipher = PKCS1_OAEP.new(priv_key)
    msg = cipher.decrypt(ciphertext)
    return msg


def read_private_key():
    with open("keys\mykey.pem", 'rb') as f:
        data = f.read()
    key = RSA.importKey(data)
    return key


def generate_key_pair():
    """Generates a 2048 bit RSA key pair and saves the keys to disk"""
    pair = RSA.generate(2048)

    f = open("keys\mykey.pem", "wb")  # private key
    f.write(pair.exportKey('PEM'))
    f.close()

    pub_key = pair.publickey().exportKey(format='PEM')
    keytext = str(pub_key).strip("-----BEGIN PUBLIC KEY-----").strip("-----END PUBLIC KEY-----").replace('\n', "")
    with open("keys\public.txt", 'wb') as f:  # the plain text public key for providing to server list
        f.write(keytext)
    with open("keys\public.pem", 'wb') as f:  # public key
        f.write(pub_key)


if __name__ == "__main__":
    private_key = None

    if not path.exists("keys\mykey.pem"):
        generate_key_pair()

    if path.exists("keys\mykey.pem"):
        private_key = read_private_key()

    if private_key is not None:
        Main(private_key)
    else:
        print("Error with Keys... no key was generated or found!")

Answer 1

客户（我想 Votifier 的 Java 版本）正在使用 RSAES PKCS1 v1.5。添加了使用该方案解码的方法并更改了对该方法的调用：

在 Main() 中：

decodedfile = decode_msg_v1_5(data, privatekey)

新方法：

def decode_msg_v1_5(ciphertext, privateKey):
    """  Should consider using the more robust PKCS1 OAEP. """
    sentinel = Random.new().read(256)      # data length is 256
    cipher = PKCS1_v1_5.new(privateKey)
    messagereceived = cipher.decrypt(ciphertext, sentinel)
    return messagereceived

RSA-2048 解密不工作 - PKCS1_OAEP "Incorrect decryption."

RSA-2048 decrypt not working - PKCS1_OAEP "Incorrect decryption."

python-2.7

rsa

pycrypto