使用 Doctrine querybuilder 正确转义 LIKE 查询
Proper escaping of LIKE queries with Doctrine querybuilder
我正在尝试使用 Doctrine QueryBuilder 进行 LIKE 查询。我阅读了其他各种问题和文章,我必须正确地避免这种类型的查询,但我不明白 Doctrine 是否会自己做。以此数据为例:
my_column
ABC
ABCD
A%BCD
及以下输入数据
ABC
ABCD
A
A%
我期望这些结果:
SELECT * FROM my_table WHERE my_column LIKE "%ABC%" => ABC, ABCD
SELECT * FROM my_table WHERE my_column LIKE "%ABCD%" => ABCD
SELECT * FROM my_table WHERE my_column LIKE "%A%" => ABC, ABCD, A, A%
SELECT * FROM my_table WHERE my_column LIKE "%A%%" => A%
我的问题与最新查询(和输入数据)有关。我应该如何正确转义该查询? '%' . addcslashes($input, '%_') . '%'
够吗?
我准备了这个 SQL Fiddle 如果它可以帮助:http://sqlfiddle.com/#!9/35bc8/9
正如 John Kary 在 this gist 中发现的那样,Doctrine 不会转义 LIKE
查询语句。更具体地说,它使用准备好的语句转义参数(像反斜杠或引号这样的字符被正确转义)但是像 %
或 _
这样的字符是 LIKE
语句语法的一部分而不是转义并且输入未被清理。下面链接的要点提供了一个很好的方法来解决这个问题,用 Symfony 2.6 和 Doctrine 2.5 测试它完美地工作。为了确保要点不会被删除,我将代码复制到这里:
<?php
namespace Foo;
/**
* Methods for safe LIKE querying.
*/
trait LikeQueryHelpers
{
/**
* Format a value that can be used as a parameter for a DQL LIKE search.
*
* $qb->where("u.name LIKE (:name) ESCAPE '!'")
* ->setParameter('name', $this->makeLikeParam('john'))
*
* NOTE: You MUST manually specify the `ESCAPE '!'` in your DQL query, AND the
* ! character MUST be wrapped in single quotes, else the Doctrine DQL
* parser will throw an error:
*
* [Syntax Error] line 0, col 127: Error: Expected Doctrine\ORM\Query\Lexer::T_STRING, got '"'
*
* Using the $pattern argument you can change the LIKE pattern your query
* matches again. Default is "%search%". Remember that "%%" in a sprintf
* pattern is an escaped "%".
*
* Common usage:
*
* ->makeLikeParam('foo') == "%foo%"
* ->makeLikeParam('foo', '%s%%') == "foo%"
* ->makeLikeParam('foo', '%s_') == "foo_"
* ->makeLikeParam('foo', '%%%s') == "%foo"
* ->makeLikeParam('foo', '_%s') == "_foo"
*
* Escapes LIKE wildcards using '!' character:
*
* ->makeLikeParam('foo_bar') == "%foo!_bar%"
*
* @param string $search Text to search for LIKE
* @param string $pattern sprintf-compatible substitution pattern
* @return string
*/
protected function makeLikeParam($search, $pattern = '%%%s%%')
{
/**
* Function defined in-line so it doesn't show up for type-hinting on
* classes that implement this trait.
*
* Makes a string safe for use in an SQL LIKE search query by escaping all
* special characters with special meaning when used in a LIKE query.
*
* Uses ! character as default escape character because \ character in
* Doctrine/DQL had trouble accepting it as a single \ and instead kept
* trying to escape it as "\". Resulted in DQL parse errors about "Escape
* character must be 1 character"
*
* % = match 0 or more characters
* _ = match 1 character
*
* Examples:
* gloves_pink becomes gloves!_pink
* gloves%pink becomes gloves!%pink
* glo_ves%pink becomes glo!_ves!%pink
*
* @param string $search
* @return string
*/
$sanitizeLikeValue = function ($search) {
$escapeChar = '!';
$escape = [
'\' . $escapeChar, // Must escape the escape-character for regex
'\%',
'\_',
];
$pattern = sprintf('/([%s])/', implode('', $escape));
return preg_replace($pattern, $escapeChar . '[=10=]', $search);
};
return sprintf($pattern, $sanitizeLikeValue($search));
}
}
它像这个例子一样使用:
<?php
namespace Foo\Entity;
use Doctrine\ORM\EntityRepository;
use Foo\LikeQueryHelpers;
class ProductRepository extends EntityRepository
{
use LikeQueryHelpers;
/**
* Find Product entities containing searched terms
*
* @param string $term
* @return Product[]
*/
public function findInSearchableFields($term)
{
return $this->createQueryBuilder('p')
->where("p.title LIKE :title ESCAPE '!'")
->setParameter('title', $this->makeLikeParam($term))
->getQuery()
->execute();
}
}
我正在尝试使用 Doctrine QueryBuilder 进行 LIKE 查询。我阅读了其他各种问题和文章,我必须正确地避免这种类型的查询,但我不明白 Doctrine 是否会自己做。以此数据为例:
my_column
ABC
ABCD
A%BCD
及以下输入数据
ABC
ABCD
A
A%
我期望这些结果:
SELECT * FROM my_table WHERE my_column LIKE "%ABC%" => ABC, ABCD
SELECT * FROM my_table WHERE my_column LIKE "%ABCD%" => ABCD
SELECT * FROM my_table WHERE my_column LIKE "%A%" => ABC, ABCD, A, A%
SELECT * FROM my_table WHERE my_column LIKE "%A%%" => A%
我的问题与最新查询(和输入数据)有关。我应该如何正确转义该查询? '%' . addcslashes($input, '%_') . '%'
够吗?
我准备了这个 SQL Fiddle 如果它可以帮助:http://sqlfiddle.com/#!9/35bc8/9
正如 John Kary 在 this gist 中发现的那样,Doctrine 不会转义 LIKE
查询语句。更具体地说,它使用准备好的语句转义参数(像反斜杠或引号这样的字符被正确转义)但是像 %
或 _
这样的字符是 LIKE
语句语法的一部分而不是转义并且输入未被清理。下面链接的要点提供了一个很好的方法来解决这个问题,用 Symfony 2.6 和 Doctrine 2.5 测试它完美地工作。为了确保要点不会被删除,我将代码复制到这里:
<?php
namespace Foo;
/**
* Methods for safe LIKE querying.
*/
trait LikeQueryHelpers
{
/**
* Format a value that can be used as a parameter for a DQL LIKE search.
*
* $qb->where("u.name LIKE (:name) ESCAPE '!'")
* ->setParameter('name', $this->makeLikeParam('john'))
*
* NOTE: You MUST manually specify the `ESCAPE '!'` in your DQL query, AND the
* ! character MUST be wrapped in single quotes, else the Doctrine DQL
* parser will throw an error:
*
* [Syntax Error] line 0, col 127: Error: Expected Doctrine\ORM\Query\Lexer::T_STRING, got '"'
*
* Using the $pattern argument you can change the LIKE pattern your query
* matches again. Default is "%search%". Remember that "%%" in a sprintf
* pattern is an escaped "%".
*
* Common usage:
*
* ->makeLikeParam('foo') == "%foo%"
* ->makeLikeParam('foo', '%s%%') == "foo%"
* ->makeLikeParam('foo', '%s_') == "foo_"
* ->makeLikeParam('foo', '%%%s') == "%foo"
* ->makeLikeParam('foo', '_%s') == "_foo"
*
* Escapes LIKE wildcards using '!' character:
*
* ->makeLikeParam('foo_bar') == "%foo!_bar%"
*
* @param string $search Text to search for LIKE
* @param string $pattern sprintf-compatible substitution pattern
* @return string
*/
protected function makeLikeParam($search, $pattern = '%%%s%%')
{
/**
* Function defined in-line so it doesn't show up for type-hinting on
* classes that implement this trait.
*
* Makes a string safe for use in an SQL LIKE search query by escaping all
* special characters with special meaning when used in a LIKE query.
*
* Uses ! character as default escape character because \ character in
* Doctrine/DQL had trouble accepting it as a single \ and instead kept
* trying to escape it as "\". Resulted in DQL parse errors about "Escape
* character must be 1 character"
*
* % = match 0 or more characters
* _ = match 1 character
*
* Examples:
* gloves_pink becomes gloves!_pink
* gloves%pink becomes gloves!%pink
* glo_ves%pink becomes glo!_ves!%pink
*
* @param string $search
* @return string
*/
$sanitizeLikeValue = function ($search) {
$escapeChar = '!';
$escape = [
'\' . $escapeChar, // Must escape the escape-character for regex
'\%',
'\_',
];
$pattern = sprintf('/([%s])/', implode('', $escape));
return preg_replace($pattern, $escapeChar . '[=10=]', $search);
};
return sprintf($pattern, $sanitizeLikeValue($search));
}
}
它像这个例子一样使用:
<?php
namespace Foo\Entity;
use Doctrine\ORM\EntityRepository;
use Foo\LikeQueryHelpers;
class ProductRepository extends EntityRepository
{
use LikeQueryHelpers;
/**
* Find Product entities containing searched terms
*
* @param string $term
* @return Product[]
*/
public function findInSearchableFields($term)
{
return $this->createQueryBuilder('p')
->where("p.title LIKE :title ESCAPE '!'")
->setParameter('title', $this->makeLikeParam($term))
->getQuery()
->execute();
}
}