嵌套for循环中的跟踪计数器

Question

我目前正在为学校做一个小作业。

我需要打印当前火车所在的车站和列表中剩下的车站。

我使用了嵌套的 for 循环，但我无法使内部 for 循环正常工作。我需要用 +=1 创建一个变量吗？

我的代码：

train_station=['Amsterdam-Central','Amsterdam-Amstel','Utrecht']

for x in train_station:
    print("Current station is: "+x)
    print("Stations to go: ")

    begin=0


    for y in range(begin,3,1):
        print(train_stations[y])

我的输出：

Current station is: Amsterdam-Central
Stations to go: 
Amsterdam-Central
Amsterdam-Amstel
Utrecht

Current station is: Amsterdam-Amstel
Stations to go:
Amsterdam-Central
Amsterdam-Amstel
Utrecht

Current station is: Utrecht
Stations to go:
Amsterdam-Central
Amsterdam-Amstel
Utrecht

Answer 1

您几乎完成了，您只需要在每次迭代时递增 begin。

train_station=['Amsterdam-Central','Amsterdam-Amstel','Utrecht']
begin = 0

for x in train_station:
    print("Current station is: "+x)
    print("Stations to go: ")

    begin += 1

    for y in range(begin, 3, 1):
        print(train_station[y])

还有一个更 pythonic 的解决方案：

for i, x in enumerate(train_station, 1):
    print("Current station is: "+x)
    print("Stations to go: ")

    for y in train_station[i:]:
        print(y)

嵌套for循环中的跟踪计数器

Tracking counter in nested for loop

python

list

nested-loops