Shell 从 JSON 对象获取键值对的脚本

Question

我有一个 JSON 对象

 {
  "Men": [
    "All Clothing",
    "All Clothing",
    "All footwear",
    "All footwear",
    "All Watches",
    "All Watches",
    "All Sunglasses",
    "All Sunglasses"
  ],
  "Electronics": [
    "Mobiles",
    "Tablets",
    "Wearable Smart Devices",
    "Mobile Accessories",
    "Headphones and headsets",
    "Tablet Accessories",
    "Computer Accessories",
    "Televisions",
    "Large Appliances",
    "Small Appliances",
    "Kitchen Appliances",
    "Personal Care",
    "Audio and video",
    "Laptop"
  ],
  "Women": [
    "Ethnic wear",
    "Western wear",
    "Lingerie & Sleep Wear",
    "All Bags, Belts & Wallets",
    "All jewellery",
    "All Perfumes",
    "Spectacle Frames",
    "Beauty & Personal Care",
    "The International Beauty Shop"
  ]
}

我想使用 jq 过滤器从此 object.m 获取键值对，但它不起作用。

keys=`jq 'keys' $categories`

$categories 是json对象的变量名。欢迎提出建议。

Answer 1

不太清楚你在问什么。如果 $categories 包含您的 JSON 数据，那么您需要以某种方式将其通过管道传输到 jq。对于 Bash，您可以使用此处的字符串：

jq keys <<<"$categories"

或更传统（且便携）的管道：

printf '%s\n' "$categories" | jq keys

要将键的值捕获到变量中，请使用命令替换：

keys=$(jq 'keys' <<<"$categories")

（或 `backticks` 就像您的尝试；但现代符号更可取）；

或者更好的是，以与您首先分配 categories 相同的方式获取此值。

Shell 从 JSON 对象获取键值对的脚本

Shell script to get key value pair from JSON object

bash

shell

json

jq