Android M 权限:未调用 onRequestPermissionsResult()
Android M Permissions: onRequestPermissionsResult() not being called
我正在更新我们的应用程序以使用新的 M 运行time 权限系统。
除了 onRequestPermissionsResult() 之外,一切正常。我需要检查按下按钮的权限,如果成功,则发送一条短信。当我授予这样做的权限时,对话框关闭,但它不会触发发送文本,直到我再次按下按钮。
我已经调试并在 onRequestPermissionsResult() 方法中设置了断点,但它从未进入它。
首先调用此方法:
private void askForPermission() {
String[] permissions = new String[]{Manifest.permission.SEND_SMS};
ActivityCompat.requestPermissions(getActivity(), permissions, PERMISSIONS_CODE);
}
然后我的回调看起来像这样:
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
if (requestCode == PERMISSIONS_CODE) {
for (int i = 0; i < permissions.length; i++) {
String permission = permissions[i];
int grantResult = grantResults[i];
if (permission.equals(Manifest.permission.SEND_SMS)) {
if (grantResult == PackageManager.PERMISSION_GRANTED) {
onPPSButtonPress();
} else {
requestPermissions(new String[]{Manifest.permission.SEND_SMS}, PERMISSIONS_CODE);
}
}
}
}
}
有没有人运行遇到过类似的问题?
感谢对此的任何帮助。
谢谢
你可以试试这个:
requestPermissions(permissions, PERMISSIONS_CODE);
如果您从片段调用此代码,它有自己的 requestPermissions 方法。我认为问题在于您正在调用静态方法。
如果您想在片段中使用 onRequestPermissionsResult()
,专业提示:
FragmentCompat.requestPermissions(Fragment fragment, String[] permissions, int requestCode)
您在 FragmentCompat 中为 Marshmallow 之前的设备提供 checkPermissions 功能。
我这样使用:
FragmentCompat.requestPermissions(this, new String[]{Manifest.permission.ACCESS_FINE_LOCATION},
MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION);
我 运行 遇到了同样的问题,我刚刚找到了解决方案。使用支持库时,您必须使用正确的方法调用。例如:
- 在AppCompatActivity时,你应该使用ActivityCompat.requestPermissions;
- 在android.support.v4.app.Fragment时,你应该简单地使用requestPermissions(这是一个实例方法android.support.v4.app.Fragment)
如果您在片段中调用 ActivityCompat.requestPermissions,onRequestPermissionsResult 回调将在 activity 而不是片段中调用。
这个问题实际上是由 NestedFragments 引起的。
基本上,我们扩展了 HostedFragment 的大多数片段又扩展了 CompatFragment。这些嵌套片段导致的问题最终由该项目的另一位开发人员解决。
他正在做一些低级的事情,比如位切换来让它工作,所以我不太确定实际的最终解决方案
如果 activity 和片段中都有 onRequestPermissionsResult
,请确保在 activity 中调用 super.onRequestPermissionsResult
。片段中不需要,但在 activity.
中
如果您在片段中使用 requestPermissions,它接受 2 个参数而不是 3 个。
你应该使用requestPermissions(permissions, PERMISSIONS_CODE);
如果出于某种原因您扩展了位于某些不调用超级库的外部库中的自定义 Activity,您将需要在您的 [=14= 中手动调用片段 super.onRequestPermissionsResult ] onRequestPermissionsResult.
YourActivity extends SomeActivityNotCallingSuperOnRequestPermissionsResult{
Fragment requestingFragment;//the fragment requesting the permission
...
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
if(requestingFragment!=null)
requestingFragment.onRequestPermissionsResult(requestCode, permissions, grantResults);
}
...
这会起作用..
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
}
我发现你调用 android.support.v4.app.Fragment.requestPermissions
的地方很重要。
如果您在 onCreate()
中执行此操作,则永远不会调用 onRequestPermissionsResult()
。
解决方法:在onActivityCreated()
;
中调用
@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
if (ContextCompat.checkSelfPermission(context, Manifest.permission.READ_CONTACTS) == PackageManager.PERMISSION_DENIED)
requestPermissions(new String[]{Manifest.permission.READ_CONTACTS}, 0);
}
/* use the object of your fragment to call the
* onRequestPermissionsResult in fragment after
* in activity and use different request Code for
* both Activity and Fragment */
if (isFragment)
mFragment.requestPermissions(permissions.toArray(new
String[permissions.size()]),requestPermission);
else
ActivityCompat.requestPermissions(mActivity,permissions.toArray(new
String[permissions.size()]),requestPermission);
我也遇到了这个问题。如果您想要 activity 处理不在 history/recents 中的权限,那么您将很想更改您的 AndroidManifest.xml
条目。
如果您设置 activity 调用 requestPermissions
或 AppCompatActivity.requestPermissions
与
android:noHistory="true"
android:excludeFromRecents="true"
在你的 AndroidManifest.xml
中 onRequestPermissionsResult()
将不会被调用。如果您的 Activity 派生自 Activity
或 AppCompatActivity
,则为真。
这可以通过从 'AndroidManifest.xml' 中删除两个标志并用 finishAndRemoveTask()
完成 activity 来解决。
答案已弃用请参考:
https://developer.android.com/training/permissions/requesting
片段内部,需要调用:
FragmentCompat.requestPermissions(permissionsList, RequestCode)
不是:
ActivityCompat.requestPermissions(Activity, permissionsList, RequestCode);
在您根据上述答案检查所有内容之前,请确保您的请求代码不是 0!!!
查看FragmentActivity.java中onRequestPermissionsResult()的代码:
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions,
@NonNull int[] grantResults) {
int index = (requestCode>>16)&0xffff;
if (index != 0) {
index--;
String who = mPendingFragmentActivityResults.get(index);
mPendingFragmentActivityResults.remove(index);
if (who == null) {
Log.w(TAG, "Activity result delivered for unknown Fragment.");
return;
}
Fragment frag = mFragments.findFragmentByWho(who);
if (frag == null) {
Log.w(TAG, "Activity result no fragment exists for who: " + who);
} else {
frag.onRequestPermissionsResult(requestCode&0xffff, permissions, grantResults);
}
}
}
private void showContacts() {
if (getActivity().checkSelfPermission(Manifest.permission.READ_CONTACTS)
!= PackageManager.PERMISSION_GRANTED) {
requestPermissions(new String[]{Manifest.permission.READ_CONTACTS}, PERMISSIONS_REQUEST_READ_CONTACTS);
} else {
doShowContacts();
}
}
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
if (requestCode == PERMISSIONS_REQUEST_READ_CONTACTS && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
doShowContacts();
}
}
希望一切顺利
对于Activity:
ActivityCompat.requestPermissions(this,permissionsList,REQUEST_CODE);
对于片段:
requestPermissions(permissionsList,REQUEST_CODE);
您可以使用 requestPermissions(PERMISSIONS, MULTIPLE_PERMISSIONS_CODE);
。如果您使用的是 v4,请不要使用 FragmentCompat。
如果您从片段调用此代码,它有自己的 requestPermissions 方法。
所以基本概念是,如果您在 Activity 中,则调用
ActivityCompat.requestPermissions(this,
permissionsList,
permissionscode);
如果在片段中,只需调用
requestPermissions(permissionsList,
permissionscode);
基于解决方案是:
myFragment.this.requestPermissions(....)
更新: 看到其他人关于在 Activity 中调用 super.onRequestPermissionResult()
的回答并且修复了我提到的请求代码问题并调用 片段的onRequestPermissionResult.
忽略这个东西:
对我来说,尽管我调用了 fragment.requestPermission(...)
,它还是调用了 Activity 的 onRequestPermissionResult
,但它返回的结果不正确(111 变成了 65647,为什么???我永远不会知道)。
幸运的是,这是我们在该屏幕上请求的唯一权限,所以我忽略了请求代码(现在没有时间弄清楚为什么它不正确)
我有一个很棒的解决方案来实现这个,制作一个像这样的 BaseActivity。
public class BaseActivity extends AppCompatActivity {
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
// Thread.setDefaultUncaughtExceptionHandler(new MyExceptionHandler(this));
}
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String permissions[], @NonNull int[] grantResults) {
switch (requestCode) {
case 1: {
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED) {
CustomToast.getInstance().setCustomToast("Now you can share the Hack.");
} else {
Toast.makeText(this, "Permission denied to read your External storage", Toast.LENGTH_SHORT).show();
}
}
}
}
}
现在你可以像这样调用代码请求权限
ActivityCompat.requestPermissions(getActivity(), new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE}, 1);
现在每次发生这种情况时,无论是在您的片段中还是在任何 activity 中,都会调用基 activity。
谢谢
详情
- 科特林 1.2.70
- 签入 minSdkVersion 19
- Android 工作室 3.1.4
算法
模块 - 摄像头,位置,....
- 检查是否有系统特征(如果模块存在于phone)
- 检查用户是否有权访问 模块
- 发送权限请求(要求用户允许模块使用)
特点
- 使用 Activity 和 Fragments
- 只有一个结果响应
- 可以在一个请求中检查多个模块
解决方案
class PermissionType(val manifest_permission: String, val packageManager: String) {
object Defined {
val camera = PermissionType(Manifest.permission.CAMERA, PackageManager.FEATURE_CAMERA)
val currentLocation = PermissionType(Manifest.permission.ACCESS_FINE_LOCATION, PackageManager.FEATURE_LOCATION_GPS)
}
}
class Permission {
enum class PermissionResult {
ACCESS_ALLOWED, ACCESS_DENIED, NO_SYSTEM_FEATURE;
}
interface ManagerDelegate {
fun permissionManagerDelegate(result: Array<Pair<String, PermissionResult>>)
}
class Manager internal constructor(private val delegate: ManagerDelegate?) {
private var context: Context? = null
private var fragment: Fragment? = null
private var activity: AppCompatActivity? = null
private var permissionTypes: Array<PermissionType> = arrayOf()
private val REQUEST_CODE = 999
private val semaphore = Semaphore(1, true)
private var result: Array<Pair<String, PermissionResult>> = arrayOf()
constructor(permissionType: PermissionType, delegate: ManagerDelegate?): this(delegate) {
permissionTypes = arrayOf(permissionType)
}
constructor(permissionTypes: Array<PermissionType>, delegate: ManagerDelegate?): this(delegate) {
this.permissionTypes = permissionTypes
}
init {
when (delegate) {
is Fragment -> {
this.fragment = delegate
this.context = delegate.context
}
is AppCompatActivity -> {
this.activity = delegate
this.context = delegate
}
}
}
private fun hasSystemFeature(permissionType: PermissionType) : Boolean {
return context?.packageManager?.hasSystemFeature(permissionType.packageManager) ?: false
}
private fun hasAccess(permissionType: PermissionType) : Boolean {
return if (Build.VERSION.SDK_INT < 23) true else {
context?.checkSelfPermission(permissionType.manifest_permission) == PackageManager.PERMISSION_GRANTED
}
}
private fun sendRequest(permissionTypes: Array<String>) {
if (fragment != null) {
fragment?.requestPermissions(permissionTypes, REQUEST_CODE)
return
}
if (activity != null){
ActivityCompat.requestPermissions(activity!!, permissionTypes, REQUEST_CODE)
}
}
fun check() {
semaphore.acquire()
AsyncTask.execute {
var permissionsForSendingRequest: Array<String> = arrayOf()
this.result = arrayOf()
for (it in permissionTypes) {
if (!hasSystemFeature(it)) {
result += Pair(it.manifest_permission, PermissionResult.NO_SYSTEM_FEATURE)
continue
}
if (hasAccess(it)) {
result += Pair(it.manifest_permission, PermissionResult.ACCESS_ALLOWED)
} else {
permissionsForSendingRequest += it.manifest_permission
}
}
if (permissionsForSendingRequest.isNotEmpty()) {
sendRequest(permissionsForSendingRequest)
} else {
delegate?.permissionManagerDelegate(result)
}
}
}
fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
when (requestCode) {
REQUEST_CODE -> {
if (grantResults.isEmpty()) {
return
}
for ((i,permission) in permissions.withIndex()) {
for (item in this.permissionTypes) {
if (permission == item.manifest_permission && i < grantResults.size) {
result += if (grantResults[i] == PackageManager.PERMISSION_GRANTED) {
Pair(item.manifest_permission, PermissionResult.ACCESS_ALLOWED)
} else {
Pair(item.manifest_permission, PermissionResult.ACCESS_DENIED)
}
break
}
}
}
delegate?.permissionManagerDelegate(result)
}
}
semaphore.release()
}
}
}
Activity中的用法(在片段中相同)
class BaseActivity : AppCompatActivity(), Permission.ManagerDelegate {
private lateinit var permissionManager: Permission.Manager
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.base_activity)
permissionManager = Permission.Manager(arrayOf(PermissionType.Defined.camera, PermissionType.Defined.currentLocation), this)
permissionManager.check()
}
override fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults)
permissionManager.onRequestPermissionsResult(requestCode, permissions, grantResults)
}
override fun permissionManagerDelegate(result: Array<Pair<String, Permission.PermissionResult>>) {
result.forEach {
println("!!! ${it.first} ${it.second}")
// when (it.second) {
// Permission.PermissionResult.NO_SYSTEM_FEATURE -> {
// }
//
// Permission.PermissionResult.ACCESS_DENIED -> {
// }
//
// Permission.PermissionResult.ACCESS_ALLOWED -> {
// }
// }
}
}
}
我有一个类似的问题,除了我按下一个按钮来拨打电话,这会触发 callIntent。我先检查权限,如果没有被授予我请求权限和 onRequestPermissionResult 我调用检查权限并再次调用。
@Override
public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
switch (requestCode) {
case Constants.PERMISSIONS_REQUEST_CALL_PHONE: {
if ( grantResults[0] == PackageManager.PERMISSION_GRANTED) {
checkPermissionsAndCall();
}
}
}
}
public void checkPermissionsAndCall(){
if (Build.VERSION.SDK_INT > 22) {
if(ContextCompat.checkSelfPermission(getContext(),
Manifest.permission.CALL_PHONE)
!= PackageManager.PERMISSION_GRANTED){
requestPermissions( new String[]{Manifest.permission.CALL_PHONE}, Constants.PERMISSIONS_REQUEST_CALL_PHONE);
}
else{
callIntent();
}
}
}
在这里,我想展示我的代码是如何做到这一点的。
public class CheckPermission {
public Context context;
public static final int PERMISSION_REQUEST_CODE = 200;
public CheckPermission(Context context){
this.context = context;
}
public boolean isPermissionGranted(){
int read_contact = ContextCompat.checkSelfPermission(context.getApplicationContext() , READ_CONTACTS);
int phone = ContextCompat.checkSelfPermission(context.getApplicationContext() , CALL_PHONE);
return read_contact == PackageManager.PERMISSION_GRANTED && phone == PackageManager.PERMISSION_GRANTED;
}
}
在此 class 我想检查是否授予权限。不是那么我会从我的 MainActivity 中调用许可,比如
public void requestForPermission() {
ActivityCompat.requestPermissions(MainActivity.this, new String[] {READ_CONTACTS, CALL_PHONE}, PERMISSION_REQUEST_CODE);
}
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
switch (requestCode) {
case PERMISSION_REQUEST_CODE:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (shouldShowRequestPermissionRationale(ACCESS_FINE_LOCATION)) {
showMessageOKCancel("You need to allow access to both the permissions",
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
requestPermissions(new String[]{Manifest.permission.READ_CONTACTS, Manifest.permission.CALL_PHONE},
PERMISSION_REQUEST_CODE);
}
}
});
return;
}
}
}
}
现在您需要在 onCreate 方法中调用 requestForPermission() 函数。
那是 it.Also 您可以一次请求多个权限。
我也遇到了一个问题,即使你调用了正确的requestPermissions,你仍然会遇到这个问题。问题是父 activity 可能会在不调用 super 的情况下覆盖此方法。加super就可以解决了
对于 kotlin 用户,这里是我的扩展程序,用于检查和验证权限而不覆盖 onRequestPermissionResult
* @param permissionToValidate (request and check currently permission)
*
* @return recursive boolean validation callback (no need OnRequestPermissionResult)
*
* */
internal fun Activity.validatePermission(
permissionToValidate: String,
recursiveCall: (() -> Boolean) = { false }
): Boolean {
val permission = ContextCompat.checkSelfPermission(
this,
permissionToValidate
)
if (permission != PackageManager.PERMISSION_GRANTED) {
if (recursiveCall()) {
return false
}
ActivityCompat.requestPermissions(
this,
arrayOf(permissionToValidate),
110
)
return this.validatePermission(permissionToValidate) { true }
}
return true
}
我正在更新我们的应用程序以使用新的 M 运行time 权限系统。 除了 onRequestPermissionsResult() 之外,一切正常。我需要检查按下按钮的权限,如果成功,则发送一条短信。当我授予这样做的权限时,对话框关闭,但它不会触发发送文本,直到我再次按下按钮。
我已经调试并在 onRequestPermissionsResult() 方法中设置了断点,但它从未进入它。
首先调用此方法:
private void askForPermission() {
String[] permissions = new String[]{Manifest.permission.SEND_SMS};
ActivityCompat.requestPermissions(getActivity(), permissions, PERMISSIONS_CODE);
}
然后我的回调看起来像这样:
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
if (requestCode == PERMISSIONS_CODE) {
for (int i = 0; i < permissions.length; i++) {
String permission = permissions[i];
int grantResult = grantResults[i];
if (permission.equals(Manifest.permission.SEND_SMS)) {
if (grantResult == PackageManager.PERMISSION_GRANTED) {
onPPSButtonPress();
} else {
requestPermissions(new String[]{Manifest.permission.SEND_SMS}, PERMISSIONS_CODE);
}
}
}
}
}
有没有人运行遇到过类似的问题? 感谢对此的任何帮助。 谢谢
你可以试试这个:
requestPermissions(permissions, PERMISSIONS_CODE);
如果您从片段调用此代码,它有自己的 requestPermissions 方法。我认为问题在于您正在调用静态方法。
如果您想在片段中使用 onRequestPermissionsResult()
,专业提示:
FragmentCompat.requestPermissions(Fragment fragment, String[] permissions, int requestCode)
您在 FragmentCompat 中为 Marshmallow 之前的设备提供 checkPermissions 功能。 我这样使用:
FragmentCompat.requestPermissions(this, new String[]{Manifest.permission.ACCESS_FINE_LOCATION},
MY_PERMISSIONS_REQUEST_ACCESS_FINE_LOCATION);
我 运行 遇到了同样的问题,我刚刚找到了解决方案。使用支持库时,您必须使用正确的方法调用。例如:
- 在AppCompatActivity时,你应该使用ActivityCompat.requestPermissions;
- 在android.support.v4.app.Fragment时,你应该简单地使用requestPermissions(这是一个实例方法android.support.v4.app.Fragment)
如果您在片段中调用 ActivityCompat.requestPermissions,onRequestPermissionsResult 回调将在 activity 而不是片段中调用。
这个问题实际上是由 NestedFragments 引起的。 基本上,我们扩展了 HostedFragment 的大多数片段又扩展了 CompatFragment。这些嵌套片段导致的问题最终由该项目的另一位开发人员解决。
他正在做一些低级的事情,比如位切换来让它工作,所以我不太确定实际的最终解决方案
如果 activity 和片段中都有 onRequestPermissionsResult
,请确保在 activity 中调用 super.onRequestPermissionsResult
。片段中不需要,但在 activity.
如果您在片段中使用 requestPermissions,它接受 2 个参数而不是 3 个。
你应该使用requestPermissions(permissions, PERMISSIONS_CODE);
如果出于某种原因您扩展了位于某些不调用超级库的外部库中的自定义 Activity,您将需要在您的 [=14= 中手动调用片段 super.onRequestPermissionsResult ] onRequestPermissionsResult.
YourActivity extends SomeActivityNotCallingSuperOnRequestPermissionsResult{
Fragment requestingFragment;//the fragment requesting the permission
...
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
if(requestingFragment!=null)
requestingFragment.onRequestPermissionsResult(requestCode, permissions, grantResults);
}
...
这会起作用..
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
}
我发现你调用 android.support.v4.app.Fragment.requestPermissions
的地方很重要。
如果您在 onCreate()
中执行此操作,则永远不会调用 onRequestPermissionsResult()
。
解决方法:在onActivityCreated()
;
@Override
public void onActivityCreated(Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);
if (ContextCompat.checkSelfPermission(context, Manifest.permission.READ_CONTACTS) == PackageManager.PERMISSION_DENIED)
requestPermissions(new String[]{Manifest.permission.READ_CONTACTS}, 0);
}
/* use the object of your fragment to call the
* onRequestPermissionsResult in fragment after
* in activity and use different request Code for
* both Activity and Fragment */
if (isFragment)
mFragment.requestPermissions(permissions.toArray(new
String[permissions.size()]),requestPermission);
else
ActivityCompat.requestPermissions(mActivity,permissions.toArray(new
String[permissions.size()]),requestPermission);
我也遇到了这个问题。如果您想要 activity 处理不在 history/recents 中的权限,那么您将很想更改您的 AndroidManifest.xml
条目。
如果您设置 activity 调用 requestPermissions
或 AppCompatActivity.requestPermissions
与
android:noHistory="true"
android:excludeFromRecents="true"
在你的 AndroidManifest.xml
中 onRequestPermissionsResult()
将不会被调用。如果您的 Activity 派生自 Activity
或 AppCompatActivity
,则为真。
这可以通过从 'AndroidManifest.xml' 中删除两个标志并用 finishAndRemoveTask()
完成 activity 来解决。
答案已弃用请参考: https://developer.android.com/training/permissions/requesting
片段内部,需要调用:
FragmentCompat.requestPermissions(permissionsList, RequestCode)
不是:
ActivityCompat.requestPermissions(Activity, permissionsList, RequestCode);
在您根据上述答案检查所有内容之前,请确保您的请求代码不是 0!!!
查看FragmentActivity.java中onRequestPermissionsResult()的代码:
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions,
@NonNull int[] grantResults) {
int index = (requestCode>>16)&0xffff;
if (index != 0) {
index--;
String who = mPendingFragmentActivityResults.get(index);
mPendingFragmentActivityResults.remove(index);
if (who == null) {
Log.w(TAG, "Activity result delivered for unknown Fragment.");
return;
}
Fragment frag = mFragments.findFragmentByWho(who);
if (frag == null) {
Log.w(TAG, "Activity result no fragment exists for who: " + who);
} else {
frag.onRequestPermissionsResult(requestCode&0xffff, permissions, grantResults);
}
}
}
private void showContacts() {
if (getActivity().checkSelfPermission(Manifest.permission.READ_CONTACTS)
!= PackageManager.PERMISSION_GRANTED) {
requestPermissions(new String[]{Manifest.permission.READ_CONTACTS}, PERMISSIONS_REQUEST_READ_CONTACTS);
} else {
doShowContacts();
}
}
@Override
public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
if (requestCode == PERMISSIONS_REQUEST_READ_CONTACTS && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
doShowContacts();
}
}
希望一切顺利
对于Activity:
ActivityCompat.requestPermissions(this,permissionsList,REQUEST_CODE);
对于片段:
requestPermissions(permissionsList,REQUEST_CODE);
您可以使用 requestPermissions(PERMISSIONS, MULTIPLE_PERMISSIONS_CODE);
。如果您使用的是 v4,请不要使用 FragmentCompat。
如果您从片段调用此代码,它有自己的 requestPermissions 方法。
所以基本概念是,如果您在 Activity 中,则调用
ActivityCompat.requestPermissions(this,
permissionsList,
permissionscode);
如果在片段中,只需调用
requestPermissions(permissionsList,
permissionscode);
基于
myFragment.this.requestPermissions(....)
更新: 看到其他人关于在 Activity 中调用 super.onRequestPermissionResult()
的回答并且修复了我提到的请求代码问题并调用 片段的onRequestPermissionResult.
忽略这个东西:
对我来说,尽管我调用了 fragment.requestPermission(...)
,它还是调用了 Activity 的 onRequestPermissionResult
,但它返回的结果不正确(111 变成了 65647,为什么???我永远不会知道)。
幸运的是,这是我们在该屏幕上请求的唯一权限,所以我忽略了请求代码(现在没有时间弄清楚为什么它不正确)
我有一个很棒的解决方案来实现这个,制作一个像这样的 BaseActivity。
public class BaseActivity extends AppCompatActivity {
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
// Thread.setDefaultUncaughtExceptionHandler(new MyExceptionHandler(this));
}
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String permissions[], @NonNull int[] grantResults) {
switch (requestCode) {
case 1: {
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED) {
CustomToast.getInstance().setCustomToast("Now you can share the Hack.");
} else {
Toast.makeText(this, "Permission denied to read your External storage", Toast.LENGTH_SHORT).show();
}
}
}
}
}
现在你可以像这样调用代码请求权限
ActivityCompat.requestPermissions(getActivity(), new String[]{Manifest.permission.WRITE_EXTERNAL_STORAGE}, 1);
现在每次发生这种情况时,无论是在您的片段中还是在任何 activity 中,都会调用基 activity。
谢谢
详情
- 科特林 1.2.70
- 签入 minSdkVersion 19
- Android 工作室 3.1.4
算法
模块 - 摄像头,位置,....
- 检查是否有系统特征(如果模块存在于phone)
- 检查用户是否有权访问 模块
- 发送权限请求(要求用户允许模块使用)
特点
- 使用 Activity 和 Fragments
- 只有一个结果响应
- 可以在一个请求中检查多个模块
解决方案
class PermissionType(val manifest_permission: String, val packageManager: String) {
object Defined {
val camera = PermissionType(Manifest.permission.CAMERA, PackageManager.FEATURE_CAMERA)
val currentLocation = PermissionType(Manifest.permission.ACCESS_FINE_LOCATION, PackageManager.FEATURE_LOCATION_GPS)
}
}
class Permission {
enum class PermissionResult {
ACCESS_ALLOWED, ACCESS_DENIED, NO_SYSTEM_FEATURE;
}
interface ManagerDelegate {
fun permissionManagerDelegate(result: Array<Pair<String, PermissionResult>>)
}
class Manager internal constructor(private val delegate: ManagerDelegate?) {
private var context: Context? = null
private var fragment: Fragment? = null
private var activity: AppCompatActivity? = null
private var permissionTypes: Array<PermissionType> = arrayOf()
private val REQUEST_CODE = 999
private val semaphore = Semaphore(1, true)
private var result: Array<Pair<String, PermissionResult>> = arrayOf()
constructor(permissionType: PermissionType, delegate: ManagerDelegate?): this(delegate) {
permissionTypes = arrayOf(permissionType)
}
constructor(permissionTypes: Array<PermissionType>, delegate: ManagerDelegate?): this(delegate) {
this.permissionTypes = permissionTypes
}
init {
when (delegate) {
is Fragment -> {
this.fragment = delegate
this.context = delegate.context
}
is AppCompatActivity -> {
this.activity = delegate
this.context = delegate
}
}
}
private fun hasSystemFeature(permissionType: PermissionType) : Boolean {
return context?.packageManager?.hasSystemFeature(permissionType.packageManager) ?: false
}
private fun hasAccess(permissionType: PermissionType) : Boolean {
return if (Build.VERSION.SDK_INT < 23) true else {
context?.checkSelfPermission(permissionType.manifest_permission) == PackageManager.PERMISSION_GRANTED
}
}
private fun sendRequest(permissionTypes: Array<String>) {
if (fragment != null) {
fragment?.requestPermissions(permissionTypes, REQUEST_CODE)
return
}
if (activity != null){
ActivityCompat.requestPermissions(activity!!, permissionTypes, REQUEST_CODE)
}
}
fun check() {
semaphore.acquire()
AsyncTask.execute {
var permissionsForSendingRequest: Array<String> = arrayOf()
this.result = arrayOf()
for (it in permissionTypes) {
if (!hasSystemFeature(it)) {
result += Pair(it.manifest_permission, PermissionResult.NO_SYSTEM_FEATURE)
continue
}
if (hasAccess(it)) {
result += Pair(it.manifest_permission, PermissionResult.ACCESS_ALLOWED)
} else {
permissionsForSendingRequest += it.manifest_permission
}
}
if (permissionsForSendingRequest.isNotEmpty()) {
sendRequest(permissionsForSendingRequest)
} else {
delegate?.permissionManagerDelegate(result)
}
}
}
fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
when (requestCode) {
REQUEST_CODE -> {
if (grantResults.isEmpty()) {
return
}
for ((i,permission) in permissions.withIndex()) {
for (item in this.permissionTypes) {
if (permission == item.manifest_permission && i < grantResults.size) {
result += if (grantResults[i] == PackageManager.PERMISSION_GRANTED) {
Pair(item.manifest_permission, PermissionResult.ACCESS_ALLOWED)
} else {
Pair(item.manifest_permission, PermissionResult.ACCESS_DENIED)
}
break
}
}
}
delegate?.permissionManagerDelegate(result)
}
}
semaphore.release()
}
}
}
Activity中的用法(在片段中相同)
class BaseActivity : AppCompatActivity(), Permission.ManagerDelegate {
private lateinit var permissionManager: Permission.Manager
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.base_activity)
permissionManager = Permission.Manager(arrayOf(PermissionType.Defined.camera, PermissionType.Defined.currentLocation), this)
permissionManager.check()
}
override fun onRequestPermissionsResult(requestCode: Int, permissions: Array<out String>, grantResults: IntArray) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults)
permissionManager.onRequestPermissionsResult(requestCode, permissions, grantResults)
}
override fun permissionManagerDelegate(result: Array<Pair<String, Permission.PermissionResult>>) {
result.forEach {
println("!!! ${it.first} ${it.second}")
// when (it.second) {
// Permission.PermissionResult.NO_SYSTEM_FEATURE -> {
// }
//
// Permission.PermissionResult.ACCESS_DENIED -> {
// }
//
// Permission.PermissionResult.ACCESS_ALLOWED -> {
// }
// }
}
}
}
我有一个类似的问题,除了我按下一个按钮来拨打电话,这会触发 callIntent。我先检查权限,如果没有被授予我请求权限和 onRequestPermissionResult 我调用检查权限并再次调用。
@Override
public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
switch (requestCode) {
case Constants.PERMISSIONS_REQUEST_CALL_PHONE: {
if ( grantResults[0] == PackageManager.PERMISSION_GRANTED) {
checkPermissionsAndCall();
}
}
}
}
public void checkPermissionsAndCall(){
if (Build.VERSION.SDK_INT > 22) {
if(ContextCompat.checkSelfPermission(getContext(),
Manifest.permission.CALL_PHONE)
!= PackageManager.PERMISSION_GRANTED){
requestPermissions( new String[]{Manifest.permission.CALL_PHONE}, Constants.PERMISSIONS_REQUEST_CALL_PHONE);
}
else{
callIntent();
}
}
}
在这里,我想展示我的代码是如何做到这一点的。
public class CheckPermission {
public Context context;
public static final int PERMISSION_REQUEST_CODE = 200;
public CheckPermission(Context context){
this.context = context;
}
public boolean isPermissionGranted(){
int read_contact = ContextCompat.checkSelfPermission(context.getApplicationContext() , READ_CONTACTS);
int phone = ContextCompat.checkSelfPermission(context.getApplicationContext() , CALL_PHONE);
return read_contact == PackageManager.PERMISSION_GRANTED && phone == PackageManager.PERMISSION_GRANTED;
}
}
在此 class 我想检查是否授予权限。不是那么我会从我的 MainActivity 中调用许可,比如
public void requestForPermission() {
ActivityCompat.requestPermissions(MainActivity.this, new String[] {READ_CONTACTS, CALL_PHONE}, PERMISSION_REQUEST_CODE);
}
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
super.onRequestPermissionsResult(requestCode, permissions, grantResults);
switch (requestCode) {
case PERMISSION_REQUEST_CODE:
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
if (shouldShowRequestPermissionRationale(ACCESS_FINE_LOCATION)) {
showMessageOKCancel("You need to allow access to both the permissions",
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
requestPermissions(new String[]{Manifest.permission.READ_CONTACTS, Manifest.permission.CALL_PHONE},
PERMISSION_REQUEST_CODE);
}
}
});
return;
}
}
}
}
现在您需要在 onCreate 方法中调用 requestForPermission() 函数。
那是 it.Also 您可以一次请求多个权限。
我也遇到了一个问题,即使你调用了正确的requestPermissions,你仍然会遇到这个问题。问题是父 activity 可能会在不调用 super 的情况下覆盖此方法。加super就可以解决了
对于 kotlin 用户,这里是我的扩展程序,用于检查和验证权限而不覆盖 onRequestPermissionResult
* @param permissionToValidate (request and check currently permission)
*
* @return recursive boolean validation callback (no need OnRequestPermissionResult)
*
* */
internal fun Activity.validatePermission(
permissionToValidate: String,
recursiveCall: (() -> Boolean) = { false }
): Boolean {
val permission = ContextCompat.checkSelfPermission(
this,
permissionToValidate
)
if (permission != PackageManager.PERMISSION_GRANTED) {
if (recursiveCall()) {
return false
}
ActivityCompat.requestPermissions(
this,
arrayOf(permissionToValidate),
110
)
return this.validatePermission(permissionToValidate) { true }
}
return true
}