分区超过 2 列 SQL 服务器

Question

我做了我以前的一个练习，并增加了一些复杂性。您可以在以下位置找到我的原始问题：

场景：（使用SQL Server 2012）

 create table #testing (b varchar (20), a date, c int, e int)

 insert into #testing (b,a,c,e)
 values
    ('xf_1m','2015-03-02','1','3'),
    ('xf_3m','2015-03-02','2','5'),
    ('xf_5y','2015-03-02','4','2'),
    ('xf_10y','2015-03-02','3','6'),
    ('ay_10y','2015-03-02','7','2'),
    ('adfe_1m','2015-03-02','2','5'),
    ('xm_1m','2013-02-01','7','2'),
    ('xf_15y','2013-02-01','1','8'),
    ('xf_20y','2013-02-01','10','1')

使用此查询后：

select
    b, a, c, e,
    substring (b, 1, CHARINDEX ('_', b) - 1) rnc,
    substring(b, CHARINDEX('_', b) + 1, LEN (b)) rnb,
    case 
        when b like 'xf%' then -- 
            (sum(c * e) over (partition by a )) end as sumProduct
into #testing2
from #testing

select 
    *,
    case 
        when b like 'xf%' then -- 
        (sum(c * e) over (partition by a )) end as sumProduct
into #testing3
from #testing2

select * 
from #testing3

我得到这个：

只是现在我想计算按 rnc 和日期（a 列）划分的 sumProduct。这该怎么做？我尝试使用分组依据，但我遇到了来自 select 的不相等数字和我分组依据的项目数的问题。

所以，我想像这样重写:

 (sum(c * e) over (partition by a and partition by rnc )) as sumProduct

Answer 1

我不确定你为什么要使用临时表，但你可以通过将它们包含在 partition by 列表中来按多个列进行分区：

select *,
       (case when b like 'xf%' 
             then sum(c * e) over (partition by a, rnd )
        end) as sumProduct
into #testing3
from #testing2;

分区超过 2 列 SQL 服务器

Over partition by 2 columns SQL Server

sql

sql-server

sql-server-2008

window-functions

sql-server-2012