OrmLite 执行 sql 语句
OrmLite execute sql statement
我在 OrmLite
中有一个数据库。
这里是 table 之一 — Field
:
@DatabaseTable
public class Field {
@DatabaseField(generatedId = true)
private long id;
@DatabaseField
private String type;
@ForeignCollectionField(eager = true)
private Collection<FieldListValue> listValue;
...
}
我想像这样从 table 中删除一些值:
List<Field> fields = fieldDao.queryForAll();
for (Field field : fields) {
if (field.getType().equals("list") && field.getListValue().size() == 0) {
fieldDao.delete(field);
}
}
但是如何使用 DeleteBuilder
执行此查询?
这段代码的问题...(SELECT COUNT(listValue) FROM Field) = 0
你可以这样做
//get instance of DeleteBuilder
DeleteBuilder<Field, Integer> deleteBuilder = fieldDao.deleteBuilder();
//construct yours WHERE
//in this exampe we select fields with "id"=0
deleteBuilder.where().eq("id", 0);
//call delete
deleteBuilder.delete();
如果你想删除行,你想要在你的代码条件之后,你可以形成一个要删除的对象的 ArrayList,然后将它们的 id 传递给 deleteBuilder where 语句,就像这样
List<Integer> ids= new ArrayList<Integer>();
List<Field> fields = fieldDao.queryForAll();
List<Field> fieldsToDelete = new ArrayList<Field>();
for (Field field : fields)
{
if (field.getType().equals("list") && field.getListValue().size() == 0)
{
ids.add(field.getId);
fieldsToDelete.add(field);
}
}
fieldDao.delete(ids);
//or
fieldDao.delete(fieldsToDelete);
//or
//get instance of DeleteBuilder
DeleteBuilder<Field, Integer> deleteBuilder = fieldDao.deleteBuilder();
//construct yours WHERE
//in this exampe we select fields with "id"=0
deleteBuilder.where().in("id", ids);
//call delete
deleteBuilder.delete();
But how can I execute this query with DeleteBuilder ?
没有直接的方法可以使用 DeleteBuilder
来执行此操作,因为外来对象实际上在 Field
class.
中没有任何信息
但是,这里有一种方法可以使用原始查询然后 DeleteBuilder
.
来完成此操作
近似代码:
qb = fieldListValueDao.queryBuilder();
// raw query for the field_ids in the fieldListValue table
rawResults = qb.queryRaw("SELECT field_id FROM fieldListValue GROUP BY field_id",
new RawRowMapper<Integer>() {
// each result row is a single integer in the 0th column
public Integer mapRow(String[] columnNames, String[] resultColumns) {
return Integer.parseInt(resultColumns[0]);
}
});
有关原始查询的帮助,请参阅:http://ormlite.com/docs/raw-queries
获得 field_id
值的原始结果后,您可以执行以下操作:
deleteBuilder = fieldDao.deleteBuilder();
// delete any rows that are not in the raw-results -- who have no fieldListValue entries
deleteBuilder.where().notIn("id", rawResults);
deleteBuilder.delete();
您也可以使用 notIn("id", queryBuilder)
方法:
qb = fieldListValueDao.queryBuilder();
qb.selectColumns("field_id");
qb.groupBy("field_id");
...
deleteBuilder = fieldDao.deleteBuilder();
deleteBuilder.where().notIn("id", qb);
deleteBuilder.delete();
但是我需要检查一下以确保。
希望这对您有所帮助。
我在 OrmLite
中有一个数据库。
这里是 table 之一 — Field
:
@DatabaseTable
public class Field {
@DatabaseField(generatedId = true)
private long id;
@DatabaseField
private String type;
@ForeignCollectionField(eager = true)
private Collection<FieldListValue> listValue;
...
}
我想像这样从 table 中删除一些值:
List<Field> fields = fieldDao.queryForAll();
for (Field field : fields) {
if (field.getType().equals("list") && field.getListValue().size() == 0) {
fieldDao.delete(field);
}
}
但是如何使用 DeleteBuilder
执行此查询?
这段代码的问题...(SELECT COUNT(listValue) FROM Field) = 0
你可以这样做
//get instance of DeleteBuilder
DeleteBuilder<Field, Integer> deleteBuilder = fieldDao.deleteBuilder();
//construct yours WHERE
//in this exampe we select fields with "id"=0
deleteBuilder.where().eq("id", 0);
//call delete
deleteBuilder.delete();
如果你想删除行,你想要在你的代码条件之后,你可以形成一个要删除的对象的 ArrayList,然后将它们的 id 传递给 deleteBuilder where 语句,就像这样
List<Integer> ids= new ArrayList<Integer>();
List<Field> fields = fieldDao.queryForAll();
List<Field> fieldsToDelete = new ArrayList<Field>();
for (Field field : fields)
{
if (field.getType().equals("list") && field.getListValue().size() == 0)
{
ids.add(field.getId);
fieldsToDelete.add(field);
}
}
fieldDao.delete(ids);
//or
fieldDao.delete(fieldsToDelete);
//or
//get instance of DeleteBuilder
DeleteBuilder<Field, Integer> deleteBuilder = fieldDao.deleteBuilder();
//construct yours WHERE
//in this exampe we select fields with "id"=0
deleteBuilder.where().in("id", ids);
//call delete
deleteBuilder.delete();
But how can I execute this query with DeleteBuilder ?
没有直接的方法可以使用 DeleteBuilder
来执行此操作,因为外来对象实际上在 Field
class.
但是,这里有一种方法可以使用原始查询然后 DeleteBuilder
.
近似代码:
qb = fieldListValueDao.queryBuilder();
// raw query for the field_ids in the fieldListValue table
rawResults = qb.queryRaw("SELECT field_id FROM fieldListValue GROUP BY field_id",
new RawRowMapper<Integer>() {
// each result row is a single integer in the 0th column
public Integer mapRow(String[] columnNames, String[] resultColumns) {
return Integer.parseInt(resultColumns[0]);
}
});
有关原始查询的帮助,请参阅:http://ormlite.com/docs/raw-queries
获得 field_id
值的原始结果后,您可以执行以下操作:
deleteBuilder = fieldDao.deleteBuilder();
// delete any rows that are not in the raw-results -- who have no fieldListValue entries
deleteBuilder.where().notIn("id", rawResults);
deleteBuilder.delete();
您也可以使用 notIn("id", queryBuilder)
方法:
qb = fieldListValueDao.queryBuilder();
qb.selectColumns("field_id");
qb.groupBy("field_id");
...
deleteBuilder = fieldDao.deleteBuilder();
deleteBuilder.where().notIn("id", qb);
deleteBuilder.delete();
但是我需要检查一下以确保。
希望这对您有所帮助。