C# 相当于 IEEE 754 余数 ()？

Question

在 C# 中，是否存在与 C99/IEEE 754 的 remainder() 函数完全等效的函数？

operator %(double x, double y)是"analogous to that used for integer operands, but differs from the IEEE 754 definition (in which n is the integer closest to x / y)"的C# language specification says。

作为差异的示例，此 C# 程序输出两个 1：

using System;

public class Test
{
    public static void Main()
    {
        Console.WriteLine(5.0 % 2.0);
        Console.WriteLine(3.0 % 2.0);
    }
}

http://ideone.com/GBITYq

而类似的 C 程序输出 1 和 -1：

#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main(void) {
    printf("%f\n", remainder(5.0, 2.0));
    printf("%f\n", remainder(3.0, 2.0));
    return EXIT_SUCCESS;
}

http://ideone.com/HpuIVr

Answer 1

此方法实现了 IEEE 754 余数算法：

Math.IEEERemainder(double, double)

public class Test
{
    public static void Main()
    {
        Console.WriteLine(Math.IEEERemainder(5.0, 2.0));
        Console.WriteLine(Math.IEEERemainder(3.0, 2.0));
    }
}

// Output: 1, -1

http://ideone.com/b2Lvfx

C# 相当于 IEEE 754 余数 ()？

C# equivalent of IEEE 754 remainder()?

.net

c#

c99

ieee-754

modulus