将某些参数的方法模拟为 return 并为所有其他参数抛出异常

Question

我正在使用 Moq 来模拟一个方法：

public class DbService : IDbService
{
    public Record GetRecord(Guid Id)
    {
        // Returns the record if exists.
        // Throws exception if record not found.
    }
}

我想模拟这个，如果我传递这三个 guid，它 returns 记录并且 所有其他 Guid 抛出异常。

Guid id = Guid.NewGuid();
Guid id2 = Guid.NewGuid();
Guid id3 = Guid.NwGuid();

var mock = new Mock<IDbService>();
mock.Setup(t => t.GetRecord(id)).Returns(record1);
mock.Setup(t => t.GetRecord(id2)).Returns(record2);
mock.Setup(t => t.GetRecord(id3)).Returns(record3);
// Throw exception for all other guids...

我该怎么做？

Answer 1

下面的代码应该可以解决问题：

mock.Setup(t => t.GetRecord(It.Is<Guid>(q => q != id && q != id2 && q != id3)))
.Throws(new Exception("Bad Guid"));

Answer 2

您可以为此使用 MockBehavior.Strict：

Guid id = Guid.NewGuid();
Guid id2 = Guid.NewGuid();
Guid id3 = Guid.NwGuid();

var mock = new Mock<IDbService>(MockBehavior.Strict);

mock.Setup(t => t.GetRecord(id)).Returns(record1);
mock.Setup(t => t.GetRecord(id2)).Returns(record2);
mock.Setup(t => t.GetRecord(id3)).Returns(record3);

// do stuff

// will throw if GetRecord was called with arguments
// that don't match to any configured setup.
mock.VerifyAll();

Answer 3

原来这么简单:

mock.Setup(t => t.GetRecord(It.IsAny<Guid>())).Throws(new MyException());
mock.Setup(t => t.GetRecord(id)).Returns(record1);
mock.Setup(t => t.GetRecord(id2)).Returns(record2);
mock.Setup(t => t.GetRecord(id3)).Returns(record3);

将某些参数的方法模拟为 return 并为所有其他参数抛出异常

Mocking a method to return for some parameters and throws exception for all other parameters

c#

moq