scipy.sparse.linalg.eigs 抽象线性运算符失败

Question

当我使用抽象/黑盒线性运算符时，上述函数失败。这是一个最小的例子：

import numpy as np
import scipy.sparse.linalg as la

# Just generate an n X n matrix
n = 9
a = np.random.normal( size = n * n )
a = a.reshape( (n,n) )

# A is a black-box linear operator
def A(v):
    global a   
    return np.dot( a, v )

# If you don't define a shpae for A you get an error
A.shape = ( n,n )

# This works
success = la.eigs( a )

# This throws an error.
failure = la.eigs( A )

这发生在 python 3.2.2 和 scipy 0.13.3 以及 python 2.7.3 和 scipy 0.16.0.

错误信息：

File "/home/daon/.local/lib/python2.7/site-packages/scipy/sparse/linalg/eigen/arpack/arpack.py", line 1227, in eigs
    matvec = _aslinearoperator_with_dtype(A).matvec
  File "/home/daon/.local/lib/python2.7/site-packages/scipy/sparse/linalg/eigen/arpack/arpack.py", line 885, in _aslinearoperator_with_dtype
    m = aslinearoperator(m)
  File "/home/daon/.local/lib/python2.7/site-packages/scipy/sparse/linalg/interface.py", line 682, in aslinearoperator
    raise TypeError('type not understood')
 TypeError: type not understood

Answer 1

好吧，这很尴尬：只是定义 A 不同：

def f(v):
    global a   
    return np.dot( a, v )

A = la.LinearOperator( a.shape, f )

这让一切正常。

scipy.sparse.linalg.eigs 抽象线性运算符失败

scipy.sparse.linalg.eigs fails with abstract linear operator

python

linear-algebra

scipy

eigenvalue