使用 NetTopologySuite 从点集合创建多边形
create Polygon from point collection with NetTopologySuite
从点列表创建多边形的最佳方法是什么?
我有一个点数组,如果点数至少为 3 我想加入以创建一个多边形
Dim ClickedPoint As New NetTopologySuite.Geometries.Point(coordinates)
ClickedPointArray.Add(ClickedPoint)
if ClickedPointArray.Count > 2 then
Polygonizer = New Polygonizer()
Polygonizer.Add(ClickedPointArray)
end if
return Polygonizer.GetPolygons
我认为我离解决方案还很远。
你能帮帮我吗?
您可以像这样使用 GeometryFactory 创建一个包含坐标数组的多边形:
Dim coordinatesArray as Coordinate[] = YourMethodToGetCoordinates
Dim geomFactory As New GeometryFactory
Dim poly As geomFactory.CreatePolygon(coordinatesArray) //this returns an IPolygon that you can cast to Polygon
这是 C#
Coordinate[] imageOutlineCoordinates = new Coordinate[]
{
new Coordinate(1, 1),
new Coordinate(2, 1),
new Coordinate(2, 2),
new Coordinate(1, 1)
};
GeometryFactory geometryFactory = new GeometryFactory();
Polygon poly = geometryFactory.CreatePolygon(imageOutlineCoordinates);
这里是使用 nettopologysuite 的 c# 解决方案 (https://github.com/NetTopologySuite/NetTopologySuite)
Polygon GetGeometry(Coordinate[] coordinates)
{
var geometryFactory = new GeometryFactory(new PrecisionModel(), 4326);
var polygon = new Polygon(new LinearRing(coordinates), geometryFactory);
return polygon;
}
注意:这里的4326是坐标系的srid。没有这个几何操作就不会给出正确的结果
-------------------------------- 以上方法的用法
var coordinates = new List<Coordinate>();
for (var index = 0; index < doubleList.Count; index = index + 2)
{
var coordinate = new Coordinate(doubleList[index], doubleList[index + 1]);
coordinates.Add(coordinate);
}
coordinates.Add(new Coordinate(points[0], points[1]));
GetGeometry(coordinates.ToArray())
从点列表创建多边形的最佳方法是什么?
我有一个点数组,如果点数至少为 3 我想加入以创建一个多边形
Dim ClickedPoint As New NetTopologySuite.Geometries.Point(coordinates)
ClickedPointArray.Add(ClickedPoint)
if ClickedPointArray.Count > 2 then
Polygonizer = New Polygonizer()
Polygonizer.Add(ClickedPointArray)
end if
return Polygonizer.GetPolygons
我认为我离解决方案还很远。 你能帮帮我吗?
您可以像这样使用 GeometryFactory 创建一个包含坐标数组的多边形:
Dim coordinatesArray as Coordinate[] = YourMethodToGetCoordinates
Dim geomFactory As New GeometryFactory
Dim poly As geomFactory.CreatePolygon(coordinatesArray) //this returns an IPolygon that you can cast to Polygon
这是 C#
Coordinate[] imageOutlineCoordinates = new Coordinate[] { new Coordinate(1, 1), new Coordinate(2, 1), new Coordinate(2, 2), new Coordinate(1, 1) }; GeometryFactory geometryFactory = new GeometryFactory(); Polygon poly = geometryFactory.CreatePolygon(imageOutlineCoordinates);
这里是使用 nettopologysuite 的 c# 解决方案 (https://github.com/NetTopologySuite/NetTopologySuite)
Polygon GetGeometry(Coordinate[] coordinates)
{
var geometryFactory = new GeometryFactory(new PrecisionModel(), 4326);
var polygon = new Polygon(new LinearRing(coordinates), geometryFactory);
return polygon;
}
注意:这里的4326是坐标系的srid。没有这个几何操作就不会给出正确的结果
-------------------------------- 以上方法的用法
var coordinates = new List<Coordinate>();
for (var index = 0; index < doubleList.Count; index = index + 2)
{
var coordinate = new Coordinate(doubleList[index], doubleList[index + 1]);
coordinates.Add(coordinate);
}
coordinates.Add(new Coordinate(points[0], points[1]));
GetGeometry(coordinates.ToArray())