C ++打印链表，分段错误

Question

void Print(Node *head)
{

    if (head = NULL)
    {
        cout << "NULL";
    }
    else
    {
        cout << head->data << endl;
        head = head->next;
        while (head->next != NULL)
        {
            cout << head->data << endl;
            head = head->next;
        }
        cout << "NULL";
    }
}

Answer 1

我看到的一个问题是您将 NULL 分配给了 head

if (head = NULL) 必须是 if (head == NULL)

Answer 2

我假设这条线

if ( head = NULL )

转录您的代码时出错，您的工作代码使用

if ( head == NULL )

我看到的真正错误是您正在使用

    cout << head->data << endl;
    head = head->next;
    while (head->next != NULL)  // This line is not good
    {
        cout << head->data << endl;
        head = head->next;
    }
    cout << "NULL";

那条线永远是个问题。在某些时候，head 将等于 NULL，您将尝试访问 NULL 指针。

将该代码块更改为：

while (head != NULL)
{
    cout << head->data << endl;
    head = head->next;
}
cout << "NULL";

其实整个函数可以是：

void Print(Node* head)
{
    while (head != NULL)
    {
        cout << head->data << endl;
        head = head->next;
    }
    cout << "NULL";
}

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