声音回声功能Python

Question

我需要编写 echo 函数，它接受一个文件名和一个浮点值 time_delay，表示 seconds.Then 的数量，echo 应该处理声音，用原始声音被自身的副本覆盖，时间向前移动 time_delay。

这是我目前拥有的：

def add_scale_2(L, M, L_scale, M_scale):
""" add_scale_2 has as intput list L and list M and rertuns a new list LC, 
    with a linear sum of the two lists times their scale respectively. LC will use the length of the 
    shortest list
"""       
    if len(L) >= len (M):
        N = len(M)
    else:
        N = len(L)

    LC = [L[i]*L_scale + M[i]*M_scale for i in range(N)]
    return LC

并且：

def echo(filename, time_delay):
    print "Playing filename1 ..."
    play(filename)

    print "Reading in the sound data..."
    samps1, sr = readwav(filename)
    samps2 = [0]*float(samps1*time_delay) + samps1

    print "Computing new sound..."
    newsamps = add_scale_2(samps1, samps2, 0.5, 0.5)
    newsr = sr # no change to the sr

    writewav( newsamps, newsr, "out.wav" )
    print "Playing new sound..."
    play( 'out.wav' )

谁能帮帮我，因为我想不通！

    samps2 = [0]*int(samps1*time_delay) + samps1
TypeError: can't multiply sequence by non-int of type 'float'

Answer 1

您的线路：

[0]*float(samps1*time_delay) + samps1

尝试将序列 [0] 乘以 float。导致错误 TypeError: can't multiply sequence by non-int of type 'float'

您可以改为转换为 int：

[0]*int(len(samps1)*time_delay) + samps1

声音回声功能Python

Sound echo function Python

python

audio

function

delay

echo