Python 列表列表比较

Question

我有两个以下类型的列表：

A=[[a1,b1,c1],[d1,e1,f1]]
B=[[a2,b1,c2],[d2,e1,f2]]

我希望能够生成这样的列表 C:

C=[[a1,b1,c1,a2,c2],[d1,e1,f1,d2,f2]]

有什么想法吗？

Answer 1

您可以使用 zip() 函数获取列，然后使用 collections.OrderedDict 保留具有先前顺序的唯一元素：

>>> from collections import OrderedDict
>>> d=OrderedDict()
>>> [d.fromkeys(i+j).keys() for i,j in zip(A,B)]
[['a1', 'b1', 'c1', 'a2', 'c2'], ['d1', 'e1', 'f1', 'd2', 'f2']]

Answer 2

作为列表理解：

import operator
c = [sorted(list(set(a + b)), key=operator.itemgetter(1, 0)) for a, b in zip(A, B)]

或者作为一个循环：

import operator
results = []
for a, b in zip(A, B):
    uniques = list(set(a + b))
    # Here we do two sorts in one call:
    results.append(sorted(uniques, key=operator.itemgetter(1, 0)))

print(results)

[['a1', 'b1', 'c1', 'a2', 'c2'], ['d1', 'e1', 'f1', 'd2', 'f2']]

Answer 3

这个解决方案不需要排序也不需要索引

C = [ea+[e for e in eb if e not in ea] for ea,eb in zip(A,B)]

它产生

[['a1', 'b1', 'c1', 'a2', 'c2'], ['d1', 'e1', 'f1', 'd2', 'f2']]

Answer 4

C = []
# zip the lists to be able to loop through both
# at the same time.
# make from A and B sets to be able to make a union of 
# A and B. Convert the union set to list to sort it and
# to append to the main list
for i, (m, n) in enumerate(zip(A,B)):
  C.append(sorted(list(set(A[i]) | set(B[i]))))

 print(C)

**output**

[['a1', 'a2', 'b1', 'c1', 'c2'], ['d1', 'd2', 'e1', 'f1', 'f2']]

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