cakephp 3.x 保存多个实体 - newEntities
cakephp 3.x saving multiple entities - newEntities
我在保存多条记录方面遇到了困难。我已经尝试了一百万件事,但最终遇到了同样的问题:我的记录没有保存,我也看不到任何错误。请记住,我是 cakephp 的新手和新手编码员。
我是否遗漏了一些明显而重要的东西?
Table:
$this->table('splits');
$this->displayField('id');
$this->primaryKey('id');
$this->belongsTo('Transactions', [
'foreignKey' => 'transaction_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Accounts', [
'foreignKey' => 'account_credit_id',
'joinType' => 'INNER'
]);
控制器:
$splits = $this->Splits->newEntity();
if ($this->request->is('post')) {
$splits = $this->Splits->newEntities($this->request->data());
debug($splits);
foreach ($splits as $split){
$this->Splits->save($split);
}
}
$transactions = $this->Splits->Transactions->find('list', ['limit' => 200]);
$accounts = $this->Splits->Accounts->find('list', ['limit' => 200]);
$this->set(compact('split', 'transactions', 'accounts'));
$this->set('_serialize', ['split']);
模板:
echo $this->Form->input('Splits.1.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.1.amount', ['type' => 'float']);
echo $this->Form->input('Splits.1.account_id', ['options' => $accounts]);
echo $this->Form->input('Splits.2.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.2.amount', ['type' => 'float']);
echo $this->Form->input('Splits.2.account_id', ['options' => $accounts]);
echo $this->Form->input('Splits.3.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.3.amount', ['type' => 'float']);
echo $this->Form->input('Splits.3.account_id', ['options' => $accounts]);
调试 $splits:
[
(int) 0 => object(App\Model\Entity\Split) {
(int) 1 => [
'transaction_id' => '108',
'amount' => '100.33',
'account_id' => '2'
],
(int) 2 => [
'transaction_id' => '108',
'amount' => '50.22',
'account_id' => '4'
],
(int) 3 => [
'transaction_id' => '108',
'amount' => '65.22',
'account_id' => '5'
],
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
(int) 1 => true,
(int) 2 => true,
(int) 3 => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'Splits'
}
]
试试这个例子在cakephp中插入多条记录3.x
$passwords = $this->request->data('password_id');
foreach ($passwords as $password) {
$data = [
'event_id' => $this->request->data('event_id'),
'password_id' => $password
];
$eventPasswordAll = $this->EventPasswordAll->newEntity();
$this->EventPasswordAll->patchEntity($eventPasswordAll, $data);
$this->EventPasswordAll->save($eventPasswordAll );}
希望对你的问题有用
请重温,谢谢!
试试这个:
$splits = TableRegistry::get('splits');
$entities = $splits->newEntities($this->request->data());
foreach ($entities as $entity) {
$splits->save($entity);
}
您是否曾在某处看到这种 Table.index.field
样式被使用,或者您只是尝试了一些东西并希望它能奏效?
当保存多条记录分别创建多条实体时,预期格式是一个数字索引数组,用于保存各个记录的数据,如文档中所示
Cookbook > Database Access & ORM > Saving Data > Converting Multiple Records
When creating forms that create/update multiple records at once you
can use newEntities():
[...]
In this situation, the request data for multiple articles should look
like:
$data = [
[
'title' => 'First post',
'published' => 1
],
[
'title' => 'Second post',
'published' => 1
],
];
因此您的输入不应使用 table 名称,而应仅使用索引和字段名称,如
echo $this->Form->input('0.transaction_id', /* ... */);
echo $this->Form->input('0.amount', /* ... */);
echo $this->Form->input('0.account_id', /* ... */);
echo $this->Form->input('1.transaction_id', /* ... */);
echo $this->Form->input('1.amount', /* ... */);
echo $this->Form->input('1.account_id', /* ... */);
echo $this->Form->input('2.transaction_id', /* ... */);
echo $this->Form->input('2.amount', /* ... */);
echo $this->Form->input('3.account_id', /* ... */);
如果您想将所有实体作为单个事务处理,您可以使用 transactional()
:
虽然使用循环,"transations" 避免了 "save" 不起作用时的错误。
// In a controller.
$articles->getConnection()->transactional(function () use ($articles, $entities) {
foreach ($entities as $entity) {
$articles->save($entity, ['atomic' => false]);
}
});
我在保存多条记录方面遇到了困难。我已经尝试了一百万件事,但最终遇到了同样的问题:我的记录没有保存,我也看不到任何错误。请记住,我是 cakephp 的新手和新手编码员。
我是否遗漏了一些明显而重要的东西?
Table:
$this->table('splits');
$this->displayField('id');
$this->primaryKey('id');
$this->belongsTo('Transactions', [
'foreignKey' => 'transaction_id',
'joinType' => 'INNER'
]);
$this->belongsTo('Accounts', [
'foreignKey' => 'account_credit_id',
'joinType' => 'INNER'
]);
控制器:
$splits = $this->Splits->newEntity();
if ($this->request->is('post')) {
$splits = $this->Splits->newEntities($this->request->data());
debug($splits);
foreach ($splits as $split){
$this->Splits->save($split);
}
}
$transactions = $this->Splits->Transactions->find('list', ['limit' => 200]);
$accounts = $this->Splits->Accounts->find('list', ['limit' => 200]);
$this->set(compact('split', 'transactions', 'accounts'));
$this->set('_serialize', ['split']);
模板:
echo $this->Form->input('Splits.1.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.1.amount', ['type' => 'float']);
echo $this->Form->input('Splits.1.account_id', ['options' => $accounts]);
echo $this->Form->input('Splits.2.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.2.amount', ['type' => 'float']);
echo $this->Form->input('Splits.2.account_id', ['options' => $accounts]);
echo $this->Form->input('Splits.3.transaction_id', ['options' => $transactions]);
echo $this->Form->input('Splits.3.amount', ['type' => 'float']);
echo $this->Form->input('Splits.3.account_id', ['options' => $accounts]);
调试 $splits:
[
(int) 0 => object(App\Model\Entity\Split) {
(int) 1 => [
'transaction_id' => '108',
'amount' => '100.33',
'account_id' => '2'
],
(int) 2 => [
'transaction_id' => '108',
'amount' => '50.22',
'account_id' => '4'
],
(int) 3 => [
'transaction_id' => '108',
'amount' => '65.22',
'account_id' => '5'
],
'[new]' => true,
'[accessible]' => [
'*' => true
],
'[dirty]' => [
(int) 1 => true,
(int) 2 => true,
(int) 3 => true
],
'[original]' => [],
'[virtual]' => [],
'[errors]' => [],
'[repository]' => 'Splits'
}
]
试试这个例子在cakephp中插入多条记录3.x
$passwords = $this->request->data('password_id');
foreach ($passwords as $password) {
$data = [
'event_id' => $this->request->data('event_id'),
'password_id' => $password
];
$eventPasswordAll = $this->EventPasswordAll->newEntity();
$this->EventPasswordAll->patchEntity($eventPasswordAll, $data);
$this->EventPasswordAll->save($eventPasswordAll );}
希望对你的问题有用
请重温,谢谢!
试试这个:
$splits = TableRegistry::get('splits');
$entities = $splits->newEntities($this->request->data());
foreach ($entities as $entity) {
$splits->save($entity);
}
您是否曾在某处看到这种 Table.index.field
样式被使用,或者您只是尝试了一些东西并希望它能奏效?
当保存多条记录分别创建多条实体时,预期格式是一个数字索引数组,用于保存各个记录的数据,如文档中所示
Cookbook > Database Access & ORM > Saving Data > Converting Multiple Records
When creating forms that create/update multiple records at once you can use newEntities():
[...]
In this situation, the request data for multiple articles should look like:
$data = [ [ 'title' => 'First post', 'published' => 1 ], [ 'title' => 'Second post', 'published' => 1 ], ];
因此您的输入不应使用 table 名称,而应仅使用索引和字段名称,如
echo $this->Form->input('0.transaction_id', /* ... */);
echo $this->Form->input('0.amount', /* ... */);
echo $this->Form->input('0.account_id', /* ... */);
echo $this->Form->input('1.transaction_id', /* ... */);
echo $this->Form->input('1.amount', /* ... */);
echo $this->Form->input('1.account_id', /* ... */);
echo $this->Form->input('2.transaction_id', /* ... */);
echo $this->Form->input('2.amount', /* ... */);
echo $this->Form->input('3.account_id', /* ... */);
如果您想将所有实体作为单个事务处理,您可以使用 transactional()
:
虽然使用循环,"transations" 避免了 "save" 不起作用时的错误。
// In a controller. $articles->getConnection()->transactional(function () use ($articles, $entities) { foreach ($entities as $entity) { $articles->save($entity, ['atomic' => false]); } });