为什么我的 do-while 循环不继续循环?

Why won't my do-while loop continue looping?

我正在努力创建一个带有错误检查的菜单,这是我想出的,但我似乎无法让它工作。

#include <iostream>
using namespace std;

int main() 
{

char option; // user's entered option will be saved in this variable
int error1 = 0;

 //Displaying Options for the menu
cout << "There are three packages available." << endl;
cout << "Monthly Price - Price per MB for overages (excluding C)" << endl;
cout << "A)  - $.06 for each MB after 200 MB." << endl;
cout << "B)  - $.02 for each MB after 2,000 MB ( approx. 2 GB)." << endl;
cout << "C)  - Unlimited data." << endl;

do //do-while loop starts here
{ 

 //Prompting user to enter an option according to menu
 cout << "Please enter which plan you currently have : ";
 cin >> option;  // taking option value as input and saving in variable "option"

 if(option == 'A' || option == 'a') // Checking if user selected option 1
 {
    cout << "You chose a" << endl;
    error1 = 1;
 }
 else if(option == 'B' || option == 'b') // Checking if user selected option 2
 {
    cout << "You chose b" << endl;
    error1 = 1;
 }
 else if(option == 'C' || option == 'c') // Checking if user selected option 3
 {
    cout << "You chose c" << endl;
    error1 = 1;
 }
 else //if user has entered invalid choice 
 {
   //Displaying error message
   error1 = 0;
   cout << "Invalid Option entered";
 }
 }
while(error1 = 0);  //condition of do-while loop
return 0;
}

当输入错误的值时,输出将是 Invalid Option entered;但是,它不会循环回到开头并再次提示用户输入。

为什么要这样做?

改变

while(error1 = 0);  //condition of do-while loop

进入这个

while(error1 == 0);  //condition of do-while loop

在第一个选项中,您只需将 0 分配给 error1,然后 error1 被测试为布尔值,这意味着 0 为 FALSE,非 0 为 TRUE。因此,一旦 while 中的条件被评估为 FALSE,循环就结束了。

您正在将 0 分配给 while 中的 error1,这始终为 false,因此循环不会重复。将 while(error1=0); 更改为 while(error1==0);

作为补码:考虑这样反转表达式:

while (0 = error1);

通过这种方式,如果您忘记了额外的 = 或将赋值与等于运算符混淆

,编译器将阻止您