在 swift 2 中发送 POST 请求

Question

我正在制作一个登录应用程序，当我找到一种方法将 POST 请求发送到 php 并尝试时，要么出现错误，要么没有错误，但没有运行我的 php 脚本。提前致谢。我正在使用带有 OS X El Capitan 的 mac 以及 XCODE 7 和 Swift 2。我的服务器是带有 WAMPServer 的旧 windows 电脑。

    import UIKit
 class Login: UIViewController {
@IBOutlet weak var UserName: UITextField!
@IBOutlet weak var PassWord: UITextField!
override func viewDidLoad() {
    super.viewDidLoad()

    // Do any additional setup after loading the view.
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}


override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?){
      UserName.resignFirstResponder()
    view.endEditing(true)
    super.touchesBegan(touches, withEvent: event)
}
   @IBAction func LoginTapped(sender: AnyObject) {
    var UserNameEntered = UserName.text
    var PassWordEntered = PassWord.text
    let ClientUserNameStored = NSUserDefaults.standardUserDefaults().stringForKey("UserName");
    let ClientPassWordStored = NSUserDefaults.standardUserDefaults().stringForKey("PassWord");
    if(ClientUserNameStored != UserNameEntered && PassWordEntered != ClientPassWordStored || ClientUserNameStored != UserNameEntered && PassWordEntered == ClientPassWordStored || ClientUserNameStored == UserNameEntered && ClientPassWordStored != PassWordEntered){
        print("Not equal")
        var Alert = UIAlertController(title: "Warning", message: "Invalid username or password!", preferredStyle: UIAlertControllerStyle.Alert)

        Alert.addAction(UIAlertAction(title: "OK", style: .Default, handler: { (action: UIAlertAction!) in UserNameEntered = ""; PassWordEntered = "";
        }))
        presentViewController(Alert, animated: true, completion: nil)
    }else{
        let request = NSMutableURLRequest(URL: NSURL(string: "http://host/my/file.php")!)
        request.HTTPMethod = "POST"
        let postString = "username=\(UserNameEntered)&password=\(PassWordEntered)"
        request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
        let task = NSURLSession.sharedSession().dataTaskWithRequest(request) {
            data, response, error in

            if error != nil {
                print("error=\(error)")
                return
            }

            print("response = \(response)")

            let responseString = NSString(data: data!, encoding: NSUTF8StringEncoding)
            print("responseString = \(responseString)")
        }
        task.resume()

                  self.performSegueWithIdentifier("GoToHome", sender: self)

    }
}

}

我的 PHP 代码如下。

<?php
$postVar = $_POST['username'];
$postVartwo = $_POST['password'];
$file = fopen("test.txt", "a");
echo fwrite($file, $postVar."pass".$postVartwo);
fclose($file);
?>

Answer 1

在你运行任务之后你执行一个序列。这意味着您离开控制器，控制器将不再存在。没有强引用，这就是为什么你的响应块不会被调用的原因。

删除 performSeque 并重试。

Answer 2

我不允许我的应用程序使用 HTTP。我通过添加

更改了我的 info.plist

<key>NSAppTransportSecurity</key>
    <dict>
        <key>NSAllowsArbitraryLoads</key>
        <true/>
    </dict>

在 swift 2 中发送 POST 请求

Sending POST request in swift 2

post

xcode7

swift2