2x2 矩阵乘法

Question

我正在尝试编写一个程序来计算两个矩阵的和与乘积，但我无法让它工作。总和很好。我正在使用 Visual Studio.

这是我的程序：

#include <stdio.h>
#include <stdlib.h>

int main()
{
    float a[2][2], b[2][2], c[2][2], d[2][2], sum;
    int i,j,k;

    for(i = 0; i < 2; i++) {  
      for(j = 0; j < 2; j++) {  
        d[i][j] = 0;
      }
    }

    printf("Enter the elements of 1st matrix\n");
    /*
     * Reading two dimensional Array with the help of two for loop. If there
     * was an array of 'n' dimension, 'n' numbers of loops are needed for
     * inserting data to array.
     */   
    for (i = 0; i < 2; ++i)      
      for (j = 0; j < 2; ++j) {
        printf("Enter a%d%d: ", i + 1, j + 1);
        scanf("%f", &a[i][j]);
      }

    printf("\nEnter the elements of 2nd matrix\n");
    for (i = 0; i < 2; ++i)
      for (j = 0; j < 2; ++j) {
        printf("Enter b%d%d: ", i + 1, j + 1);
        scanf("%f", &b[i][j]);
      }

    printf("\nMatrix 1:\n");
    for (i = 0; i < 2; ++i)
      for(j = 0; j < 2; ++j) {
        printf("%.1f\t", a[i][j]);  
        if (j == 1)             /* To display matrix sum in order. */
          printf("\n");
      }
    printf("\nMatrix 2:\n");

    for(i = 0; i < 2; ++i)
      for(j = 0; j < 2; ++j) {
        printf("%.1f\t", b[i][j]);  
        if (j == 1)             /* To display matrix sum in order. */
           printf("\n");
      }

    for (i = 0; i < 2; ++i)
      for(j = 0; j < 2; ++j) {
        /* Writing the elements of multidimensional array using loop. */
        c[i][j]=a[i][j]+b[i][j];  /* Sum of corresponding elements of two arrays. */
      }
    printf("\nSum Of Matrix:\n");
    for (i = 0; i < 2; ++i)
      for(j = 0; j < 2; ++j) {
        printf("%.1f\t",c[i][j]);  
        if (j == 1)             /* To display matrix sum in order. */
          printf("\n");
      }

    for(i = 0 ; i < 2 ; i++) {  
      for(j = 0 ; j < 2 ; j++) {  
        sum = 0 ;  
        for(k = 0 ; k < 2 ; k++) {  
          sum = sum + a[i][k] * b[k][j];
          printf("a: %d; b: %d\n", a[i][k], b[k][j]);
          printf("%d", sum);
        }
        d[i][j]=sum;
      }  
    }  
    printf("\nThe multiplication matrix is : \n\n") ;  
    for(i = 0; i < 2; i++) {  
      for(j = 0; j < 2; j++) {  
        printf("%d \t", d[i][j]) ;  
      }  
      printf("\n") ;  
    } 

    system("PAUSE");
    return 0;
}

这是输出：

Matrix 1:
1.0     2.0
3.0     4.0

Matrix 2:
5.0     6.0
7.0     8.0

Sum Of Matrix:
6.0     8.0
10.0    12.0
a: 0; b: 1072693248
0a: 0; b: 1073741824
0a: 0; b: 1072693248
0a: 0; b: 1073741824
0a: 0; b: 1074266112
0a: 0; b: 1074790400
0a: 0; b: 1074266112
0a: 0; b: 1074790400
0
The multiplication matrix is :

0       0
0       0

我看不出矩阵 A 和 B 的问题出在哪里。

Answer 1

首先，我不会将 for 循环的终止硬编码为常量，而是硬编码为 sizeof(a)/sizeof(a[0])，例如。其次，问题是您正在尝试将浮点数打印为整数 - 第 68 行显示：

printf("a: %d; b: %d\n",a[i][k],b[k][j]);

但应该是

printf("a: %.1f; b: %.1f\n",a[i][k],b[k][j]);

这些问题存在于第 68、69 和 79 行。如果将 %d 更改为 %f 应该没问题。

2x2 矩阵乘法

2x2 Matrix Multiplication

c

matrix

visual-studio

matrix-multiplication