如何使用 Google 地图 API 和 PHP 将邮政编码转换为 lat/long？
How to converting postcode to lat/long using Google Maps API with PHP?
我正在使用 PHP 将邮政编码 + 县的列表转换为纬度和经度。我试过像这样使用 google 映射 api 和 simplexml_load_file() 函数：
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print"<pre>";
print_r($result);
现在这工作正常，因为我能够得到以下内容：
SimpleXMLElement Object
(
[status] => OK
[result] => SimpleXMLElement Object
(
[type] => postal_code
[formatted_address] => Walsall, Walsall, West Midlands WS9 8NS, UK
[address_component] => Array
(
[0] => SimpleXMLElement Object
(
[long_name] => WS9 8NS
[short_name] => WS9 8NS
[type] => postal_code
)
[1] => SimpleXMLElement Object
(
[long_name] => Walsall
[short_name] => Walsall
[type] => Array
(
[0] => locality
[1] => political
)
)
[2] => SimpleXMLElement Object
(
[long_name] => Walsall
[short_name] => Walsall
[type] => postal_town
)
[3] => SimpleXMLElement Object
(
[long_name] => West Midlands
[short_name] => West Mids
[type] => Array
(
[0] => administrative_area_level_2
[1] => political
)
)
[4] => SimpleXMLElement Object
(
[long_name] => United Kingdom
[short_name] => GB
[type] => Array
(
[0] => country
[1] => political
)
)
)
[geometry] => SimpleXMLElement Object
(
[location] => SimpleXMLElement Object
(
[lat] => 52.6030230
[lng] => -1.9175368
)
[location_type] => APPROXIMATE
[viewport] => SimpleXMLElement Object
(
[southwest] => SimpleXMLElement Object
(
[lat] => 52.6013713
[lng] => -1.9188871
)
[northeast] => SimpleXMLElement Object
(
[lat] => 52.6040692
[lng] => -1.9161892
)
)
[bounds] => SimpleXMLElement Object
(
[southwest] => SimpleXMLElement Object
(
[lat] => 52.6020654
[lng] => -1.9182516
)
[northeast] => SimpleXMLElement Object
(
[lat] => 52.6033751
[lng] => -1.9168247
)
)
)
)
)
现在的问题是，我应该如何取出第一个纬度/经度而不是整个东西，我只需要这两个值。
请注意，lat/long 是动态的，因为每次搜索的地址都会发生变化。
最好使用他们的 JSON API。
$url ="http://maps.googleapis.com/maps/api/geocode/json?address=WS9+8NS,+West+Midlands&sensor=false";
$result = file_get_contents($url);
print"<pre>";
$resultArray = json_decode($result, true);
print_r($result);
那就像数组一样访问吧！
例如
$resultArray['results']['geometry']['location']['lat']
$resultArray['results']['geometry']['location']['lng']
我会使用 cURL 而不是文件获取内容，因为它提供了更多控制。但这很好用。
在尝试对 $resultArray 执行任何操作之前，我还会检查它。
从print_r可以看出内容的结构。那么，就是跟风了。[=14=]
这包含值：
$result->result->geometry->location
所以要分别打印它们，你可以说：
print "lat: " . $result->result->geometry->location->lat;
print "lng: " . $result->result->geometry->location->lng;
总计：
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print "lat: " . $result->result->geometry->location->lat . " <br/>";
print "lng: " . $result->result->geometry->location->lng . " <br/>";
我正在使用 PHP 将邮政编码 + 县的列表转换为纬度和经度。我试过像这样使用 google 映射 api 和 simplexml_load_file() 函数：
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print"<pre>";
print_r($result);
现在这工作正常，因为我能够得到以下内容：
SimpleXMLElement Object
(
[status] => OK
[result] => SimpleXMLElement Object
(
[type] => postal_code
[formatted_address] => Walsall, Walsall, West Midlands WS9 8NS, UK
[address_component] => Array
(
[0] => SimpleXMLElement Object
(
[long_name] => WS9 8NS
[short_name] => WS9 8NS
[type] => postal_code
)
[1] => SimpleXMLElement Object
(
[long_name] => Walsall
[short_name] => Walsall
[type] => Array
(
[0] => locality
[1] => political
)
)
[2] => SimpleXMLElement Object
(
[long_name] => Walsall
[short_name] => Walsall
[type] => postal_town
)
[3] => SimpleXMLElement Object
(
[long_name] => West Midlands
[short_name] => West Mids
[type] => Array
(
[0] => administrative_area_level_2
[1] => political
)
)
[4] => SimpleXMLElement Object
(
[long_name] => United Kingdom
[short_name] => GB
[type] => Array
(
[0] => country
[1] => political
)
)
)
[geometry] => SimpleXMLElement Object
(
[location] => SimpleXMLElement Object
(
[lat] => 52.6030230
[lng] => -1.9175368
)
[location_type] => APPROXIMATE
[viewport] => SimpleXMLElement Object
(
[southwest] => SimpleXMLElement Object
(
[lat] => 52.6013713
[lng] => -1.9188871
)
[northeast] => SimpleXMLElement Object
(
[lat] => 52.6040692
[lng] => -1.9161892
)
)
[bounds] => SimpleXMLElement Object
(
[southwest] => SimpleXMLElement Object
(
[lat] => 52.6020654
[lng] => -1.9182516
)
[northeast] => SimpleXMLElement Object
(
[lat] => 52.6033751
[lng] => -1.9168247
)
)
)
)
)
现在的问题是，我应该如何取出第一个纬度/经度而不是整个东西，我只需要这两个值。
请注意，lat/long 是动态的，因为每次搜索的地址都会发生变化。
最好使用他们的 JSON API。
$url ="http://maps.googleapis.com/maps/api/geocode/json?address=WS9+8NS,+West+Midlands&sensor=false";
$result = file_get_contents($url);
print"<pre>";
$resultArray = json_decode($result, true);
print_r($result);
那就像数组一样访问吧！
例如
$resultArray['results']['geometry']['location']['lat']
$resultArray['results']['geometry']['location']['lng']
我会使用 cURL 而不是文件获取内容，因为它提供了更多控制。但这很好用。
在尝试对 $resultArray 执行任何操作之前，我还会检查它。
从print_r可以看出内容的结构。那么，就是跟风了。[=14=]
这包含值：
$result->result->geometry->location
所以要分别打印它们，你可以说：
print "lat: " . $result->result->geometry->location->lat;
print "lng: " . $result->result->geometry->location->lng;
总计：
$url ="http://maps.googleapis.com/maps/api/geocode/xml?address=WS9+8NS,+West+Midlands&sensor=false";
$result = simplexml_load_file($url);
print "lat: " . $result->result->geometry->location->lat . " <br/>";
print "lng: " . $result->result->geometry->location->lng . " <br/>";