JQuery 数据table 在同一数据集中具有父子关系。如何在 table 中将其显示为父子行？

Question

我有一个嵌套数据集。数据集中很少有记录是同一数据集中其他记录的子记录。父项为 null 的记录没有任何子元素，但具有与 is 相关联的值的记录将指示其在同一数据集中的父项。我如何在 jQuery 具有父子关系的数据表中表示这一点。

我刚刚操作了公共数据集来解释我的要求。在下面的数据集示例中，名称记录 - Tiger Nixon 有两个子记录，它们在同一数据集中作为单独的记录。

如何实现的例子会有很大帮助。

{
  "data": [
    {
      "name": "Tiger Nixon",
      "parent": "null",
      "position": "System Architect",
      "salary": "0,800",
      "start_date": "2011/04/25",
      "office": "Edinburgh",
      "extn": "5421"
    },
    {
      "name": "Garrett Winters",
      "parent": "Tiger Nixon",
      "position": "Accountant",
      "salary": "0,750",
      "start_date": "2011/07/25",
      "office": "Tokyo",
      "extn": "8422"
    },
    {
      "name": "Ashton Cox",
      "parent": "null",
      "position": "Junior Technical Author",
      "salary": ",000",
      "start_date": "2009/01/12",
      "office": "San Francisco",
      "extn": "1562"
    },
    {
      "name": "Cedric Kelly",
      "parent": "Tiger Nixon",
      "position": "Senior Javascript Developer",
      "salary": "3,060",
      "start_date": "2012/03/29",
      "office": "Edinburgh",
      "extn": "6224"
    }
]
}

Answer 1

SOLUTION

您可以使用 ajax.dataSrc 将原始数据存储在 g_dataFull 中，并过滤和 return 包含 parents 的数据仅显示在主 table 中.

当 child 行在 format() 函数中时，您需要迭代整个数据集 g_dataFull 并查找并显示包含 children (this.parent === d.name ).

DEMO

var g_dataFull = [];

/* Formatting function for row details - modify as you need */
function format ( d ) {
    var html = '<table cellpadding="5" cellspacing="0" border="0" style="padding-left:50px;" width="100%">';
      
    var dataChild = [];
    var hasChildren = false;
    $.each(g_dataFull, function(){
       if(this.parent === d.name){
          html += 
            '<tr><td>' + $('<div>').text(this.name).html() + '</td>' + 
            '<td>' +  $('<div>').text(this.position).html() + '</td>' + 
            '<td>' +  $('<div>').text(this.office).html() +'</td>' + 
            '<td>' +  $('<div>').text(this.salary).html() + '</td></tr>';
         
          hasChildren = true;
       }
    });
  
    if(!hasChildren){
        html += '<tr><td>There are no items in this view.</td></tr>';
     
    }
  
 
    html += '</table>';
    return html;
}
 
$(document).ready(function() {
    var table = $('#example').DataTable( {
        "ajax": {
          "url": "https://api.myjson.com/bins/3mbye",
          "dataSrc": function(d){
            
             g_dataFull = d.data;
             var dataParent = []
             $.each(d.data, function(){
                if(this.parent === "null"){
                   dataParent.push(this);  
                }
             });
            
             return dataParent;
          }
        },
         
        "columns": [
            {
                "className":      'details-control',
                "orderable":      false,
                "data":           null,
                "defaultContent": ''
            },
            { "data": "name" },
            { "data": "position" },
            { "data": "office" },
            { "data": "salary" }
        ],
        "order": [[1, 'asc']]
    } );
     
    // Add event listener for opening and closing details
    $('#example tbody').on('click', 'td.details-control', function () {
        var tr = $(this).closest('tr');
        var row = table.row( tr );
 
        if ( row.child.isShown() ) {
            // This row is already open - close it
            row.child.hide();
            tr.removeClass('shown');
        }
        else {
            // Open this row
            row.child( format(row.data()) ).show();
            tr.addClass('shown');
        }
    } );
} );

td.details-control {
    background: url('https://raw.githubusercontent.com/DataTables/DataTables/1.10.7/examples/resources/details_open.png') no-repeat center center;
    cursor: pointer;
}
tr.shown td.details-control {
    background: url('https://raw.githubusercontent.com/DataTables/DataTables/1.10.7/examples/resources/details_close.png') no-repeat center center;
}

<link href="//cdn.datatables.net/1.10.7/css/jquery.dataTables.min.css" rel="stylesheet" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script> 
<script src="//cdn.datatables.net/1.10.7/js/jquery.dataTables.min.js"></script>

<table id="example" class="display">
<thead>
    <tr>
        <th></th>
        <th>Name</th>
        <th>Position</th>
        <th>Office</th>
        <th>Salary</th>
    </tr>
</thead>

<tfoot>
    <tr>
        <th></th>
        <th>Name</th>
        <th>Position</th>
        <th>Office</th>
        <th>Salary</th>
    </tr>
</tfoot>
</table>

JQuery 数据table 在同一数据集中具有父子关系。如何在 table 中将其显示为父子行？

JQuery Datatable with parent child relationship in same dataset. How to display it as parent child rows in the table?

datatable

jquery

parent

datatables