Java

Question

我是新手 Java，我正在尝试使用星号打印未填充的钻石。菱形的高度必须基于用户输入。我的代码目前根据用户输入打印出一个填充钻石，但我不知道如何打印一个未填充的钻石。每次我更改其中一个循环时，它都会搞砸其他事情。感谢所有帮助！

public static void diamond(){
   int i = 0;
   int j = 0;
   int k = 0;
   int height = 0;

   Scanner in = new Scanner(System.in);
   System.out.println("How tall do you want the diamond to be: ");
   height = in.nextInt();

   for (k = 1; k <= (height + 1) / 2; k++) {
       for (i = 0; i < height - k; i++) {
           System.out.print(" ");
       }
       for (j = 0; j < k; j++) {
           System.out.print("* ");
       }
       System.out.println("");
   }

   for (k = ((height + 1) / 2); k < height; k++) {
       for (i = 1; i < k; i++) { 
           System.out.print(" "); 
       }
       for (j = 0; j < height - k; j++) { 
           System.out.print(" *");
       }
       System.out.println("");
    }
}

Answer 1

这是打印未填充钻石的修改方法。一个 if 条件已添加到内部循环。

public static void diamond() {
    int i = 0;
    int j = 0;
    int k = 0;
    int height = 0;

    Scanner in = new Scanner(System.in);
    System.out.println("How tall do you want the diamond to be: ");
    height = in.nextInt();

    for (k = 1; k <= (height + 1) / 2; k++) {
        for (i = 0; i < height - k; i++) {
            System.out.print(" ");
        }
        for (j = 0; j < k; j++) {
            if (j == 0 || j == (k - 1)) {
                System.out.print("* ");
            } else {
                System.out.print("  ");
            }
        }
        System.out.println("");
    }

    for (k = ((height + 1) / 2); k < height; k++) {
        for (i = 1; i < k; i++) {
            System.out.print(" ");
        }
        for (j = 0; j < height - k; j++) {
            if (j == 0 || j == (height - k - 1)) {
                System.out.print(" *");
            } else {
                System.out.print("  ");
            }
        }
        System.out.println("");
    }
}

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