组项组合，不重复

Question

我有 3 组项目，我想生成如下例所示的数组：

Group 1 = {m1, m2, m3}
Group 2 = {m4, m5}
Group 3 = {m6, m7, m8, m9}

{m1, m4, m6}
{m2, m5, m7}
{m3, null, m8}
{null, null, m9}

组中的每个元素在生成的数组中只应出现一次。我该如何解决这个问题？

Answer 1

你应该考虑做这样的事情（记住这是伪代码）：

group1 = {m1, m2, m3}
group2 = {m4, m5}
group3 = {m6, m7, m8, m9}

len1 = group1.size
len2 = group2.size
len3 = group3.size

max = max(len1, len2, len3)

combination = {}
for i from 0 to max:

    combination = {}
    if(group1(i) exists)
        combination.add(group1(i))
    else combination.add("null")

    if(group2(i) exists)
        combination.add(group2(i))
    else combination.add("null")            

    if(group3(i) exists)
        combination.add(group3(i))
    else combination.add("null")            

    print combination

Answer 2

我就是这样做的，它的 maxscript 代码分析了 multi-material 可以有其他 multi-materials，并从每个 ID 创建新的 materials。也许我在第一个问题中有点不清楚对此感到抱歉。

    local maxSubID = amax arrayNumSubs --it is the count of the array with highest number of items.


    for maxSubCounter = 1 to maxSubID do
    (
        tmpMat = multimaterial numsubs:mainMatIDs
        for subCounter = 1 to mainMatIDs do
        (
            if (rootMat[subCounter] != undefined) then
            (
                tmpMat[subCounter] = rootMat[subCounter][maxSubCounter]
            )else
            (
                tmpMat[subCounter] = undefined
            )
        )
        append materialsToApply tmpMat
    )

组项组合，不重复

Combinations of group items, no repeating

python

algorithm

combinations

maxscript