如何通过浏览器访问Spark core？

Question

我希望核心像网络服务器一样在通过网络浏览器访问时显示文本使用此命令 >>>(client.println("Sorry");) 它应该在浏览器中显示 "sorry" 对吗？但是当我在浏览器中输入内核的 IP 时。它说 "This webpage is not available"

感谢阅读。

TCPServer server = TCPServer(80);
    TCPClient client;

    void setup()
    {
      // start listening for clients
      server.begin();

      // Make sure your Serial Terminal app is closed before powering your Core
      Serial.begin(9600);
      // Now open your Serial Terminal, and hit any key to continue!
      while(!Serial.available()) SPARK_WLAN_Loop();

      Serial.println(WiFi.localIP());
      Serial.println(WiFi.subnetMask());
      Serial.println(WiFi.gatewayIP());
      Serial.println(WiFi.SSID());
    }

    void loop()
    {
      if (client.connected()) {
        // echo all available bytes back to the client
        while (client.available()) {
          server.write(client.read());
          server.write("Hello world!");
          client.println("Sorry"); //<<<<<<<<<<<<<<should show this
        }
      } else {
        // if no client is yet connected, check for a new connection
        client = server.available();
      }
    }

这是我在 arduino 和以太网 sheild 中使用的代码，它工作正常

#include <SPI.h>
#include <Ethernet.h>

//Enter a new MAC address from your computer MAC plus one.
byte mac[] = { 0x00, 0xAA, 0xBB, 0xCC, 0xDE, 0x02 };
EthernetServer server(80); // Create new server object at selected port

void setup() {

  Serial.begin(9600);
  Serial.println("Requesting ip address ...");
  Ethernet.begin(mac,ip,gateway,subnet);
  Serial.print("My IP address: ");
  Serial.print(Ethernet.localIP());
  server.begin(); // begin listening
}

void loop() {
  EthernetClient client = server.available(); // Get connection
  if(server.available()){ // check if there are connection
    Serial.println("new client connection");
    while (client.connected()) { // check if the client still alive
      if (client.available()) { // check if the connection are still alive
        char c = client.read(); // read data from Ethernet buffer
        if(c=='='){ p = client.read(); }
        Serial.write(c);
        if(c == '\n'){ // check if there are terminate character
          client.println("sorry");
          break;
        }
      }
    }
    client.stop(); // disconnect from client
    Serial.println("client disconnected");
  }
  delay(1000);
}///// credit P'O ITE

Answer 1

浏览器不会对您所做的很满意。您向浏览器 return 发送的任何内容都不符合 HTTP 协议规范。您应该使用 telnet 客户端在端口 80 上打开到核心 IP 地址的连接。然后你会看到更接近你预期的东西。

使用 SparkCore 及其适度的工具来 return 网页是可能的，但您必须限制大小。要return一个网页，浏览器会很高兴，你可以忽略请求并始终return这个：

HTTP/1.1 200 OK
Date: Tue, 31 Mar 2015 22:38:34 GMT
Server: SparkCore
Content-Type: text/html; charset=UTF-8
Content-Length: 138
Accept-Ranges: bytes
Connection: close

<html>
<head>
  <title>An Example Page</title>
</head>
<body>
  Hello World, this is a very simple HTML document.
</body>
</html>

这是一个最小的 HTTP 响应。我还没有测试过它，但我非常有信心它会起作用。要了解有关 HTTP 的更多信息以及您需要做什么，请查看维基百科：

http://en.wikipedia.org/wiki/Hypertext_Transfer_Protocol

我还在 community.spark.io 上找到了一个很好的帖子：

http://community.spark.io/t/spark-core-web-server-solved/10110/4

祝你好运！

如何通过浏览器访问Spark core？

How to access the Spark core via we browser?

c++

arduino

sparkcore