Sequelize 使用 ROW_NUMBER() 而不是 OFFSET 和 FETCH

Question

我注意到使用 (offset, fetch) 和 rownumber 时的不同行为。

当我使用行号时 returns 我期望的结果。

所以我的 sequelize 查询如下所示：

 ClanModel.findAll({
    order: [["Wins", "DESC"]],
    offset: page * 5,
    limit: 5
 })

SQL 从第一行开始查询

SELECT 
    [clid] AS [ClanId], [Name], [Wins], [Losses], 
    [totalPoint] AS [TotalPoints] 
FROM 
    [Clan] AS [Clan] 
ORDER BY 
    [Clan].[Wins] DESC 
    OFFSET 0 ROWS FETCH NEXT 5 ROWS ONLY;

结果：

[ { Name: 'Test6'},
  { Name: 'Test5'},
  { Name: 'Test4'},
  { Name: 'Test3'},
  { Name: 'Test2'} ]

SQL查询第5个结果后：

SELECT 
    [clid] AS [ClanId], [Name], [Wins], [Losses],
    [totalPoint] AS [TotalPoints] 
FROM 
    [Clan] AS [Clan] 
ORDER BY 
    [Clan].[Wins] DESC 
    OFFSET 5 ROWS FETCH NEXT 5 ROWS ONLY;

结果：

[ { Name: 'Test5'},
  { Name: 'Test4'},
  { Name: 'Test3'},
  { Name: 'Test2'},
  { Name: 'Test1'} ]

行号查询：

 SELECT 
     [Name], [Wins], [Losses], [TotalPoints] AS [TotalPoints]
 FROM 
     (SELECT
          [clid] AS [ClanId], [Name], [Wins], [Losses],
          [totalPoint] AS [TotalPoints], 
          ROW_NUMBER() OVER (ORDER BY [Wins]) AS RowNum
      FROM 
          [Clan]) as Clan
 WHERE 
     Clan.RowNum BETWEEN 5 AND 10

Returns我期望的结果：

Test5
Test6
Test7
Test8
Test9
Test10

我的数据库记录：

Test1
Test2
Test3
Test4
Test5
Test6
Test7
Test8
Test9
Test10

我想使用我的 sequelize 模型来获取我的数据，而不是使用普通的 sql 查询。但是我找不到在 sequelize 中使用行号的方法。

有没有办法仍然使用 sequelize 来获取我的数据？

Answer 1

您没有显示完整的数据。所以，这有点猜测：您在 wins 列中有联系。 order by 的排序不稳定，甚至不一致，这意味着平局可以以任何顺序返回。因此，通过包含名称来解决此问题：

SELECT [clid] AS [ClanId], [Name], [Wins], [Losses], [totalPoint] AS [TotalPoints]
FROM [Clan] AS [Clan]
ORDER BY [Clan].[Wins] DESC, Clan.Name
OFFSET 5 ROWS FETCH NEXT 5 ROWS ONLY;

假设Name是唯一的，这将使排序保持一致。如果这在 SQL 中有效，那么在 sequelize 中应该很容易实现。

Sequelize 使用 ROW_NUMBER() 而不是 OFFSET 和 FETCH

Sequelize use ROW_NUMBER() instead of OFFSET and FETCH

sql

sql-server

node.js

sequelize.js