如何在 while 循环中只打印最后一行

Question

count = 0

while count ** 2 < snum_:
    print "Using search with increment 1, the root lies between", count,"and", count + 1
    count = count + 1

如何让循环只打印最后一行？

Answer 1

您可以保存要打印的字符串并在循环后打印它：

count = 0
result = ''

while count ** 2 < snum_:
    result = "Using search with increment 1, the root lies between %d and %d" % count, count + 1
    count = count + 1

print result

Answer 2

使用 for 循环和 itertools.count():

import itertools
for count in itertools.count(1):
    if count**2 >= snum_:
        print "Using search with increment 1, the root lies between %d and %d" % count-1, count
        break

但总体思路也可以应用于您的 while 循环：当 count**2 不再小于 snum_ 时，打印并中断。

Answer 3

你可以试试这个：

count = 0

while count < 4:
    print('hi')
    count += 1
else:
    # Replace below string with what you wish.
    print('end')

+=表示count + 1。 else 在 while 完成后达到（不会打印，如果你 break 循环而不是让它正常完成）。

如何在 while 循环中只打印最后一行

How to print only last line in a while loop

while-loop

python-2.7