如何从 objective c 中的今天开始计算一周中的天数
How to get days in a week from today in objective c
我正在尝试根据他们的日期获取一周中的几天。
例如:10 月 14 日是星期三。
我正在创建一个集合视图单元格并按如下方式显示日期。
在第 14 个单元格中,它将显示星期三,但如何将第二天显示为星期四,然后是星期五...等等。
我得到了今天的日期,具体是哪一天,
day = [components day];
week = [components month];
year = [components year];
weekday = [components weekday];
NSString *string = [NSString stringWithFormat:@"%ld.%ld.%ld", (long)day, (long)week, (long)year];
NSLog(@"%@",string);
NSDate *todayDate = [NSDate date]; // get today date
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"EEEE"];
NSString *convertedDateString = [dateFormatter stringFromDate:todayDate];// here convert date in
NSLog(@"Today formatted date is %@",convertedDateString);
而且我在网上找到了这个方法,returns 当你传递整数时字符串中的天数,但我在这方面也遇到了麻烦,不明白每次传递哪个整数所以我得到不同的字符串。
static inline NSString *stringFromWeekday(int weekday){
static NSString *strings[] = {
@"Sunday",
@"Monday",
@"Tuesday",
@"Wednesday",
@"Thursday",
@"Friday",
@"Saturday",
};
return strings[weekday];
}
你已经准备好了一切。您应该在 convertedDateString
字符串中获得正确的日期名称。您只需将 24 小时添加到您的 todayDate
对象并再次使用 dateformatter
获得第二天。
NSDate *todayDate = [NSDate date]; // get today date
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"EEEE"];
NSString *convertedDateString = [dateFormatter stringFromDate:todayDate];// here convert date in
你可以这样得到第二天
NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:(NSDayCalendarUnit | NSMonthCalenderUnit | NSYearCalenderUnit | NSWeekdayCalendarUnit) fromDate:today];
[dateComponents setDay:dateComponents.day+1];
NSDate *nextDay = [dateComponents date];
// Get the day by following same approach in the top
使用以下代码,您将从今天开始获得一周中的几天。
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents =
[gregorian components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
NSInteger day = [weekdayComponents day];
NSInteger weekday = [weekdayComponents weekday];
我正在尝试根据他们的日期获取一周中的几天。
例如:10 月 14 日是星期三。
我正在创建一个集合视图单元格并按如下方式显示日期。
在第 14 个单元格中,它将显示星期三,但如何将第二天显示为星期四,然后是星期五...等等。
我得到了今天的日期,具体是哪一天,
day = [components day];
week = [components month];
year = [components year];
weekday = [components weekday];
NSString *string = [NSString stringWithFormat:@"%ld.%ld.%ld", (long)day, (long)week, (long)year];
NSLog(@"%@",string);
NSDate *todayDate = [NSDate date]; // get today date
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"EEEE"];
NSString *convertedDateString = [dateFormatter stringFromDate:todayDate];// here convert date in
NSLog(@"Today formatted date is %@",convertedDateString);
而且我在网上找到了这个方法,returns 当你传递整数时字符串中的天数,但我在这方面也遇到了麻烦,不明白每次传递哪个整数所以我得到不同的字符串。
static inline NSString *stringFromWeekday(int weekday){
static NSString *strings[] = {
@"Sunday",
@"Monday",
@"Tuesday",
@"Wednesday",
@"Thursday",
@"Friday",
@"Saturday",
};
return strings[weekday];
}
你已经准备好了一切。您应该在 convertedDateString
字符串中获得正确的日期名称。您只需将 24 小时添加到您的 todayDate
对象并再次使用 dateformatter
获得第二天。
NSDate *todayDate = [NSDate date]; // get today date
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"EEEE"];
NSString *convertedDateString = [dateFormatter stringFromDate:todayDate];// here convert date in
你可以这样得到第二天
NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:(NSDayCalendarUnit | NSMonthCalenderUnit | NSYearCalenderUnit | NSWeekdayCalendarUnit) fromDate:today];
[dateComponents setDay:dateComponents.day+1];
NSDate *nextDay = [dateComponents date];
// Get the day by following same approach in the top
使用以下代码,您将从今天开始获得一周中的几天。
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc]
initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents =
[gregorian components:(NSDayCalendarUnit | NSWeekdayCalendarUnit) fromDate:today];
NSInteger day = [weekdayComponents day];
NSInteger weekday = [weekdayComponents weekday];