Json.Net 中的强类型 Object[]

Question

我有一个问题一直困扰着我。我使用 JSON.Net 到 serialize/deserialize 个对象。我使用此代码通过参数类型调用方法。

如果我运行下面的代码我得到一个对象[] {int, int}

然后我 serialize/deserialize 和 Json.Net 并且在这个过程之后它变成 object[] {long, long}

现在我的问题是：如何更改以下代码以保留类型和值？

 static class Program
{
    static byte[] ObjectAsByteArray(object data)
    {
        string text = JsonConvert.SerializeObject(data, Formatting.None, new JsonSerializerSettings()
        {
            Formatting=Formatting.Indented,
            TypeNameHandling = TypeNameHandling.All,
            TypeNameAssemblyFormat = System.Runtime.Serialization.Formatters.FormatterAssemblyStyle.Simple
        });

        return Encoding.UTF8.GetBytes(text);
    }

    static T ByteArrayAsObject<T>(byte[] data)
    {
        Object answer = JsonConvert.DeserializeObject(Encoding.UTF8.GetString(data), typeof(T), new JsonSerializerSettings()
        {
            Formatting = Formatting.Indented,
            TypeNameHandling = TypeNameHandling.All,
            TypeNameAssemblyFormat = System.Runtime.Serialization.Formatters.FormatterAssemblyStyle.Simple
        });
        return (T)answer;
    }

    static int Multiply(int a, int b)
    {
        return a * b;
    }


    static object[] ArgumentsOf(Expression<Action> expression)
    {
        MethodCallExpression outermostExpression = expression.Body as MethodCallExpression;
        object[] Params = outermostExpression.Arguments.Cast<ConstantExpression>().Select(x => x.Value).ToArray();

        return Params;
    }


    [STAThread]
    static void Main()
    {
        object[] Arguments = ArgumentsOf(() => Multiply(5, 100));
        byte[] ArgAsByte = ObjectAsByteArray(Arguments);

        object[] DeserializedArguments = ByteArrayAsObject<object[]>(ArgAsByte);

    }




}

Answer 1

您需要将 ArgumentsOf 更改为泛型，否则 return 类型是序列化为

的 System.Object 数组

"$type": "System.Object[], mscorlib",

但是，如果您指定特定类型的 int，它将序列化为：

"$type": "System.Int32[], mscorlib",

像这样：

static T[] ArgumentsOf<T>(Expression<Func<T>> expression)
{
    MethodCallExpression outermostExpression = expression.Body as MethodCallExpression;
    var Params = outermostExpression.Arguments.Cast<ConstantExpression>().Select(x => (T)x.Value).ToArray();
    return Params;
}

然后你的整个样本看起来是这样的：

static class Program
{
static byte[] ObjectAsByteArray(object data)
{
    string text = JsonConvert.SerializeObject(data, Newtonsoft.Json.Formatting.None, new JsonSerializerSettings()
    {
        Formatting=Newtonsoft.Json.Formatting.Indented,
        TypeNameHandling = TypeNameHandling.All,
        TypeNameAssemblyFormat = System.Runtime.Serialization.Formatters.FormatterAssemblyStyle.Simple
    });

    return Encoding.UTF8.GetBytes(text);
}

static T ByteArrayAsObject<T>(byte[] data)
{
    var answer = JsonConvert.DeserializeObject(Encoding.UTF8.GetString(data), typeof(T), new JsonSerializerSettings()
    {
        Formatting = Newtonsoft.Json.Formatting.Indented,
        TypeNameHandling = TypeNameHandling.All,
        TypeNameAssemblyFormat = System.Runtime.Serialization.Formatters.FormatterAssemblyStyle.Simple
    });
    return (T)answer;
}

static int Multiply(int a, int b)
{
    return a * b;
}


static T[] ArgumentsOf<T>(Expression<Func<T>> expression)
{
    MethodCallExpression outermostExpression = expression.Body as MethodCallExpression;
    var Params = outermostExpression.Arguments.Cast<ConstantExpression>().Select(x => (T)x.Value).ToArray();
    return Params;
}


[STAThread]
static void Main()
{
    var Arguments = ArgumentsOf(() => Multiply(5, 100));
    byte[] ArgAsByte = ObjectAsByteArray(Arguments);

    var DeserializedArguments = ByteArrayAsObject<int[]>(ArgAsByte);
}

}

Json.Net 中的强类型 Object[]

Strongly typed Object[] in Json.Net

c#

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types

object