非聚合多数据透视 - 卡住 MS SQL 查询

Question

我几乎已经使用多数据透视非聚合函数完成了我的 MS SQL 查询，但无法生成所需的结果。任何人都可以帮助我，不确定我错过了什么吗？另外，如果有更简单的解决方案，请随时分享。

任何帮助将不胜感激！

SQL Fiddle

http://www.sqlfiddle.com/#!3/0103d/1/0

Answer 1

您的查询已硬编码 PIVOT，最多包含 10 列。我将您的查询重写为我认为更具可读性的形式。

WITH cte AS
(
  SELECT *, rn = ROW_NUMBER() OVER(PARTITION BY policyID ORDER BY policyID)
  FROM #tbl_policy_client_details
)
SELECT policyID
  ,[No of travellers]    = COUNT(*)
  ,[Traveller 1 - Age]  = MAX(CASE WHEN rn = 1 THEN Age END)
  ,[Name 1]              = MAX(CASE WHEN rn = 1 THEN FirstName END)
  ,[Surname 1]           = MAX(CASE WHEN rn = 1 THEN Surname END)
  ,[Type Condition 1]    = MAX(CASE WHEN rn = 1 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 2 - Age]  = MAX(CASE WHEN rn = 2 THEN Age END)
  ,[Name 2]              = MAX(CASE WHEN rn = 2 THEN FirstName END)
  ,[Surname 2]           = MAX(CASE WHEN rn = 2 THEN Surname END)
  ,[Type Condition 2]    = MAX(CASE WHEN rn = 2 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 3 - Age]  = MAX(CASE WHEN rn = 3 THEN Age END)
  ,[Name 3]              = MAX(CASE WHEN rn = 3 THEN FirstName END)
  ,[Surname 3]           = MAX(CASE WHEN rn = 3 THEN Surname END)
  ,[Type Condition 3]    = MAX(CASE WHEN rn = 3 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 4 - Age]  = MAX(CASE WHEN rn = 4 THEN Age END)
  ,[Name 4]              = MAX(CASE WHEN rn = 4 THEN FirstName END)
  ,[Surname 4]           = MAX(CASE WHEN rn = 4 THEN Surname END)
  ,[Type Condition 4]    = MAX(CASE WHEN rn = 4 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 5 - Age]  = MAX(CASE WHEN rn = 5 THEN Age END)
  ,[Name 5]              = MAX(CASE WHEN rn = 5 THEN FirstName END)
  ,[Surname 5]           = MAX(CASE WHEN rn = 5 THEN Surname END)
  ,[Type Condition 5]    = MAX(CASE WHEN rn = 5 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller6 - Age]   = MAX(CASE WHEN rn = 6 THEN Age END)
  ,[Name 6]              = MAX(CASE WHEN rn = 6 THEN FirstName END)
  ,[Surname 6]           = MAX(CASE WHEN rn = 6 THEN Surname END)
  ,[Type Condition 6]    = MAX(CASE WHEN rn = 6 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 7 - Age]  = MAX(CASE WHEN rn = 7 THEN Age END)
  ,[Name 7]              = MAX(CASE WHEN rn = 7 THEN FirstName END)
  ,[Surname 7]           = MAX(CASE WHEN rn = 7 THEN Surname END)
  ,[Type Condition 7]    = MAX(CASE WHEN rn = 7 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 8 - Age]  = MAX(CASE WHEN rn = 8 THEN Age END)
  ,[Name 8]              = MAX(CASE WHEN rn = 8 THEN FirstName END)
  ,[Surname 8]           = MAX(CASE WHEN rn = 8 THEN Surname END)
  ,[Type Condition 8]    = MAX(CASE WHEN rn = 8 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 9 - Age]  = MAX(CASE WHEN rn = 9 THEN Age END)
  ,[Name 9]              = MAX(CASE WHEN rn = 9 THEN FirstName END)
  ,[Surname 9]           = MAX(CASE WHEN rn = 9 THEN Surname END)
  ,[Type Condition 9]    = MAX(CASE WHEN rn = 9 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)

  ,[Traveller 10 - Age]  = MAX(CASE WHEN rn = 10 THEN Age END)
  ,[Name 10]              = MAX(CASE WHEN rn = 10 THEN FirstName END)
  ,[Surname 10]           = MAX(CASE WHEN rn = 10 THEN Surname END)
  ,[Type Condition 10]    = MAX(CASE WHEN rn = 10 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)
FROM cte
GROUP BY policyID

工作原理：

非常简单GROUP BY，每组最多可容纳 10 位客户。就像你的 PIVOT.

SELECT policyID
  ,[No of travellers]    = COUNT(*)
  ,[Traveller 1 - Age]   = MAX(CASE WHEN rn = 1 THEN Age END)
  ,[Name 1]              = MAX(CASE WHEN rn = 1 THEN FirstName END)
  ,[Surname 1]           = MAX(CASE WHEN rn = 1 THEN Surname END)
  ,[Type Condition 1]    = MAX(CASE WHEN rn = 1 THEN IIF(TypeID IS NULL , 'No', 'Yes') END)
FROM cte
GROUP BY policyID;

编辑：

您的初始查询不起作用的原因是您使用的是字符串文字而不是名称列。改用：

With client_details AS
(
SELECT cd.*,
  CASE WHEN TypeID IS NULL THEN 'No' Else 'Yes' END [TypeResult]
  ,'Age'+CONVERT(VARCHAR(10),ROW_NUMBER()OVER(PARTITION BY cd.PolicyID ORDER BY TravellerID DESC)) AS [Ages] 
  ,'name'+CONVERT(VARCHAR(10),ROW_NUMBER()OVER(PARTITION BY cd.PolicyID ORDER BY TravellerID DESC))AS [Name] 
  ,'surname'+CONVERT(VARCHAR(10),ROW_NUMBER()OVER(PARTITION BY cd.PolicyID ORDER BY TravellerID DESC)) AS [Surnames],
  'Type'+CONVERT(VARCHAR(10),ROW_NUMBER()OVER(PARTITION BY cd.PolicyID ORDER BY TravellerID DESC)) AS [Type] 
FROM tbl_policy_client_details cd
WHERE cd.PolicyID IS not NULL)
SELECT 
  policyID
  ,COUNT(PolicyID)[No of travellers]
  ,MAX(Age1) [Traveller 1 - Age],MAX(Name1) [Name 1],MAX(Surname1) [Surname 1],MAX(Type1) [Type Condition 1]
  ,MAX(Age2) [Traveller 2 - Age],MAX(Name2) [Name 2],MAX(Surname1) [Surname 2],MAX(Type2) [Type Condition 2]
  ,MAX(Age3) [Traveller 3 - Age],MAX(Name3) [Name 3],MAX(Surname1) [Surname 3],MAX(Type3) [Type Condition 3]
  ,MAX(Age4) [Traveller 4 - Age],MAX(Name4) [Name 4],MAX(Surname1) [Surname 4],MAX(Type4) [Type Condition 4]
  ,MAX(Age5) [Traveller 5 - Age],MAX(Name5) [Name 5],MAX(Surname1) [Surname 5],MAX(Type5) [Type Condition 5]
  -- ...
FROM
(SELECT cd.*
FROM client_details cd) p
PIVOT(MAX(Age)FOR Ages IN ([Age1],[Age2],[Age3],[Age4],[Age5],[Age6],[Age7],[Age8],[Age9],[Age10])) AS pvt
PIVOT (MAX(Firstname)
FOR Name IN ([Name1],[Name2],[Name3],[Name4],[Name5],[Name6],[Name7],[Name8],[Name9],[Name10])) AS Pivot1
PIVOT (MAX(Surnames)
FOR Surname IN ([Surname1],[Surname2],[Surname3],[Surname4],[Surname5],[Surname6],[Surname7],[Surname8],[Surname9],[Surname10])) AS Pivot2
PIVOT (MAX(TypeResult)
FOR Type IN ([Type1],[Type2],[Type3],[Type4],[Type5],[Type6],[Type7],[Type8],[Type9],[Type10])) AS Pivot3
GROUP BY Pivot3.policyID;

SqlFiddleDemo

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