如何将嵌套的命名元组转换为字典？

Question

我正在尝试将下面提到的嵌套 namedtuple 转换为字典。

我正在使用 Python 3.4.2 和 psd-tools-1.2

TypeToolObjectSetting(version=1, xx=0.0, xy=-1.55729984301413, yx=1.6070307595731337, yy=0.0, tx=628.1016949152543, ty=516.5, text_version=50, descriptor1_version=16, text_data=Descriptor(name='', classID=b'TxLr', items=[(b'Txt ', String(value='34px')), (b'textGridding', Enum(type=b'textGridding', value=b'None')), (b'Ornt', Enum(type=b'Ornt', value=b'Hrzn')), (b'AntA', Enum(type=b'Annt', value=b'Anno')), (b'bounds', Descriptor(name='', classID=b'bounds', items=[(b'Left', UnitFloat(unit='POINTS', value=-10.0)), (b'Top ', UnitFloat(unit='POINTS', value=-6.908203125)), (b'Rght', UnitFloat(unit='POINTS', value=10.0)), (b'Btom', UnitFloat(unit='POINTS', value=2.42578125))])), (b'boundingBox', Descriptor(name='', classID=b'boundingBox', items=[(b'Left', UnitFloat(unit='POINTS', value=-9.34375)), (b'Top ', UnitFloat(unit='POINTS', value=-5.9375)), (b'Rght', UnitFloat(unit='POINTS', value=9.5)), (b'Btom', UnitFloat(unit='POINTS', value=1.609375))])), (b'TextIndex', Integer(value=0)), (b'EngineData', RawData(value=b'\n\n<<\n\t/EngineDict\n\t<<\n\t\t/Edito ... =8205'))]), warp_version=1, descriptor2_version=16, warp_data=Descriptor(name='', classID=b'warp', items=[(b'warpStyle', Enum(type=b'warpStyle', value=b'warpNone')), (b'warpValue', Double(value=0.0)), (b'warpPerspective', Double(value=0.0)), (b'warpPerspectiveOther', Double(value=0.0)), (b'warpRotate', Enum(type=b'Ornt', value=b'Hrzn'))]), left=0, top=0, right=0, bottom=0)

我试过 _asdict() 但它没有用，因为数据正在流式传输，我不想更改库本身的任何内容。

Answer 1

您可以通过递归解包 ._asdict().items() 来解嵌命名元组，检查值类型的实例并相应地解包嵌套值。 instance checking of a namedtuple 需要一些额外的努力来确保解包器不会将嵌套的命名元组视为纯元组。

def isnamedtupleinstance(x):
    _type = type(x)
    bases = _type.__bases__
    if len(bases) != 1 or bases[0] != tuple:
        return False
    fields = getattr(_type, '_fields', None)
    if not isinstance(fields, tuple):
        return False
    return all(type(i)==str for i in fields)

def unpack(obj):
    if isinstance(obj, dict):
        return {key: unpack(value) for key, value in obj.items()}
    elif isinstance(obj, list):
        return [unpack(value) for value in obj]
    elif isnamedtupleinstance(obj):
        return {key: unpack(value) for key, value in obj._asdict().items()}
    elif isinstance(obj, tuple):
        return tuple(unpack(value) for value in obj)
    else:
        return obj

# data = TypeToolObjectSetting(version=1, xx=0.0, ..
unpacked_data = unpack(data)

如何将嵌套的命名元组转换为字典？

How to convert a nested namedtuple to a dict?

python

python-3.4

namedtuple