Gulp + babelify + browserify 问题

Question

我正在尝试使用 browserify 和 babelify 创建一个 gulp 任务。这是任务：

var gulp = require('gulp');
var browserify = require('gulp-browserify');
var source = require('vinyl-source-stream');
var babelify = require('babelify');

gulp.task('js', function () {
    browserify('./resources/js/*.js')
        .transform(babelify)
        .bundle()
        .pipe(source('*.js'))
        .pipe(gulp.dest('./public/js'));
});

我找了一些示例代码，尝试使用它们，但结果总是一样。

当我运行任务，并保存我的 example.js 文件时，出现以下错误：

TypeError: browserify(...).transform is not a function

我做错了什么？

Answer 1

您混淆了 browserify 和 gulp-browserify 的 API。

从 gulp-browserify docs 开始，您需要执行如下操作：

var gulp = require('gulp')
var browserify = require('gulp-browserify')

gulp.task('js', function () {
  gulp.src('./resources/js/*.js')
    .pipe(browserify({
      transform: ['babelify'],
    }))
    .pipe(gulp.dest('./public/js'))
});

编辑： 由于首次回答了这个问题，gulp-browserify has been abandoned and gulp has evolved a great deal. If you'd like to achieve the same thing with a newer version of gulp, you can follow the guides provided by the gulp team.

您最终会得到如下内容：

var browserify = require('browserify');
var babelify = require('babelify');
var gulp = require('gulp');
var source = require('vinyl-source-stream');
var buffer = require('vinyl-buffer');
var sourcemaps = require('gulp-sourcemaps');
var util = require('gulp-util');

gulp.task('default', function () {
  var b = browserify({
    entries: './resources/test.js',
    debug: true,
    transform: [babelify.configure({
      presets: ['es2015']
    })]
  });

  return b.bundle()
    .pipe(source('./resources/test.js'))
    .pipe(buffer())
    .pipe(sourcemaps.init({ loadMaps: true }))
      // Add other gulp transformations (eg. uglify) to the pipeline here.
      .on('error', util.log)
    .pipe(sourcemaps.write('./'))
    .pipe(gulp.dest('./public/js/'));
});

Gulp + babelify + browserify 问题

Gulp + babelify + browserify issue

javascript

gulp

browserify

babeljs