在使用 java 解析特定节点的 xml 后,尝试获取节点的下一个和前一个兄弟节点
Attempt to get next and previous sibling of a node after parsing xml for a specific node using java
我有一个 xml 包含 1000 个事件的日志,其中每个事件都有一个密钥,
我的 objective 是当用户搜索事件键时,我应该向他显示具有此键的事件节点的 xml 并准备上一个和下一个兄弟的信息。
xml结构如下:
<LOG>
<EVENT_SET>
<DOCGET system="T610_00" fingerPrint="NO_SIGNATURE">
<event>
<key>382</key>
<date>2015-01-28T09:15:15.350+0000</date>
<service>CORE</service>
<class>APPLICATION</class>
</event>
<document>
<docuri>getdocs:///DocMapCSDOCS.dPortal/1</docuri>
<sign_info>
<signature>VqtR9Gpny/MPE43/5o4hJXp8bR7gbsVUJqHlTI+VfztMSQecTpZwAQpxmorrdBJKvmn+h7eZzV1geVodkVECvOjQMRmRbnpT6mrpbiXxjDOsZsQRDNemTYUKETrQFIBRtXcjoP61une1LOsS5C749ehwbZ1jEaNH6fPjH4n+OH4=</signature>
</sign_info>
</document>
</DOCGET>
<DOCGET system="T610_00" fingerPrint="NO_SIGNATURE">
<event>
<key>383</key>
<date>2015-01-28T09:15:18.310+0000</date>
<service>CORE</service>
<class>APPLICATION</class>
</event>
<document>
<docuri>getdocs:///DocMapCSDOCS.dPortal/2</docuri>
<sign_info>
<signature>VqtR9Gpny/MPE43/5o4hJXp8bR7gbsVUJqHlTI+VfztMSQecTpZwAQpxmorrdBJKvmn+h7eZzV1geVodkVECvOjQMRmRbnpT6mrpbiXxjDOsZsQRDNemTYUKETrQFIBRtXcjoP61une1LOsS5C749ehwbZ1jEaNH6fPjH4n+OH4=</signature>
</sign_info>
</document>
</DOCGET>
.......
</EVENT_SET>
</LOG>
到目前为止,我获取密钥节点的代码是:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(false);
DocumentBuilder builder = factory.newDocumentBuilder();
//parsing the xml file
journaldoc = builder.parse(journalFile);
XPathFactory xpathfactory = XPathFactory.newInstance();
XPath xpath = xpathfactory.newXPath();
//xpath to search for the event having the key requated by the user
String sXpath = "//DOCGET[event/key='"+eventkey+"']";
XPathExpression expr = xpath.compile(sXpath);
Object result = expr.evaluate(journaldoc, XPathConstants.NODE);
Node eventnode = (Node) result;
//return to the user the xml part with root DOCGET, and having the key requested
Document document = DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument();
Node copyNode = document.importNode(eventNode, true);
document.appendChild(copyNode);
DOMImplementationLS domImplementationLS = (DOMImplementationLS) document.getImplementation();
LSSerializer lsSerializer = domImplementationLS.createLSSerializer();
String xmlNode = lsSerializer.writeToString(document);
现在我需要获取此节点的前一个和下一个兄弟节点并获取它们的键以便将它们保存在 HashMap 中。
问题是在执行 eventnode.getPreviousSibling 和 eventnode.getNextSibling 时,我的信息已损坏,我无法获取这些事件的密钥。
有没有人对此有更好的想法?
谢谢,
卡琳
我认为您正在寻找 XPath 轴 preceding-sibling
和 following-sibling
。这些select所有节点都在同一级别,所以如果你只想要下一个邻居,你需要添加一个谓词到select只是第一个:following-sibling::*[1]
。但是您只需要事件节点,并且事件节点不是直接的兄弟姐妹,但是 <DOCGET>
元素是。因此,您需要从一个事件节点向上,找到 next/previous 兄弟并再次向下。这归结为这个表达式:../preceding-sibling::*[1]/event
将在事件节点上进行评估。
您可以使用 data projection(披露:我隶属于该项目)以面向对象访问事件来简化任务,但仍然将 Java 代码结构与XML 结构:
public class ReadEvents {
public interface Event {
@XBRead("./key")
String getKey();
@XBRead("./date using yyyy-MM-dd'T'HH:mm:ss.SSSZ")
Date getDate();
@XBRead("../document/docuri")
String getDocumentURI();
@XBRead("../preceding-sibling::*[1]/event")
Event getPreviousEvent();
@XBRead("../following-sibling::*[1]/event")
Event getNextEvent();
}
public static void main(String... args) {
List<Event> allEvents = new XBProjector().io().url("res://log.xml").evalXPath("//event").asListOf(Event.class);
for (Event event : allEvents) {
System.out.print(event.getDate()+ ": Event " + event.getKey());
if (event.getPreviousEvent() != null) {
System.out.print(" previous event has key " + event.getPreviousEvent().getKey());
}
if (event.getNextEvent() != null) {
System.out.print(" next event has key " + event.getNextEvent().getKey());
}
System.out.println();
}
}
}
对于您的示例,此程序打印出:
Wed Jan 28 10:15:15 CET 2015: Event 382 next event has key 383
Wed Jan 28 10:15:18 CET 2015: Event 383 previous event has key 382
我有一个 xml 包含 1000 个事件的日志,其中每个事件都有一个密钥, 我的 objective 是当用户搜索事件键时,我应该向他显示具有此键的事件节点的 xml 并准备上一个和下一个兄弟的信息。
xml结构如下:
<LOG>
<EVENT_SET>
<DOCGET system="T610_00" fingerPrint="NO_SIGNATURE">
<event>
<key>382</key>
<date>2015-01-28T09:15:15.350+0000</date>
<service>CORE</service>
<class>APPLICATION</class>
</event>
<document>
<docuri>getdocs:///DocMapCSDOCS.dPortal/1</docuri>
<sign_info>
<signature>VqtR9Gpny/MPE43/5o4hJXp8bR7gbsVUJqHlTI+VfztMSQecTpZwAQpxmorrdBJKvmn+h7eZzV1geVodkVECvOjQMRmRbnpT6mrpbiXxjDOsZsQRDNemTYUKETrQFIBRtXcjoP61une1LOsS5C749ehwbZ1jEaNH6fPjH4n+OH4=</signature>
</sign_info>
</document>
</DOCGET>
<DOCGET system="T610_00" fingerPrint="NO_SIGNATURE">
<event>
<key>383</key>
<date>2015-01-28T09:15:18.310+0000</date>
<service>CORE</service>
<class>APPLICATION</class>
</event>
<document>
<docuri>getdocs:///DocMapCSDOCS.dPortal/2</docuri>
<sign_info>
<signature>VqtR9Gpny/MPE43/5o4hJXp8bR7gbsVUJqHlTI+VfztMSQecTpZwAQpxmorrdBJKvmn+h7eZzV1geVodkVECvOjQMRmRbnpT6mrpbiXxjDOsZsQRDNemTYUKETrQFIBRtXcjoP61une1LOsS5C749ehwbZ1jEaNH6fPjH4n+OH4=</signature>
</sign_info>
</document>
</DOCGET>
.......
</EVENT_SET>
</LOG>
到目前为止,我获取密钥节点的代码是:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(false);
DocumentBuilder builder = factory.newDocumentBuilder();
//parsing the xml file
journaldoc = builder.parse(journalFile);
XPathFactory xpathfactory = XPathFactory.newInstance();
XPath xpath = xpathfactory.newXPath();
//xpath to search for the event having the key requated by the user
String sXpath = "//DOCGET[event/key='"+eventkey+"']";
XPathExpression expr = xpath.compile(sXpath);
Object result = expr.evaluate(journaldoc, XPathConstants.NODE);
Node eventnode = (Node) result;
//return to the user the xml part with root DOCGET, and having the key requested
Document document = DocumentBuilderFactory.newInstance().newDocumentBuilder().newDocument();
Node copyNode = document.importNode(eventNode, true);
document.appendChild(copyNode);
DOMImplementationLS domImplementationLS = (DOMImplementationLS) document.getImplementation();
LSSerializer lsSerializer = domImplementationLS.createLSSerializer();
String xmlNode = lsSerializer.writeToString(document);
现在我需要获取此节点的前一个和下一个兄弟节点并获取它们的键以便将它们保存在 HashMap 中。
问题是在执行 eventnode.getPreviousSibling 和 eventnode.getNextSibling 时,我的信息已损坏,我无法获取这些事件的密钥。
有没有人对此有更好的想法?
谢谢, 卡琳
我认为您正在寻找 XPath 轴 preceding-sibling
和 following-sibling
。这些select所有节点都在同一级别,所以如果你只想要下一个邻居,你需要添加一个谓词到select只是第一个:following-sibling::*[1]
。但是您只需要事件节点,并且事件节点不是直接的兄弟姐妹,但是 <DOCGET>
元素是。因此,您需要从一个事件节点向上,找到 next/previous 兄弟并再次向下。这归结为这个表达式:../preceding-sibling::*[1]/event
将在事件节点上进行评估。
您可以使用 data projection(披露:我隶属于该项目)以面向对象访问事件来简化任务,但仍然将 Java 代码结构与XML 结构:
public class ReadEvents {
public interface Event {
@XBRead("./key")
String getKey();
@XBRead("./date using yyyy-MM-dd'T'HH:mm:ss.SSSZ")
Date getDate();
@XBRead("../document/docuri")
String getDocumentURI();
@XBRead("../preceding-sibling::*[1]/event")
Event getPreviousEvent();
@XBRead("../following-sibling::*[1]/event")
Event getNextEvent();
}
public static void main(String... args) {
List<Event> allEvents = new XBProjector().io().url("res://log.xml").evalXPath("//event").asListOf(Event.class);
for (Event event : allEvents) {
System.out.print(event.getDate()+ ": Event " + event.getKey());
if (event.getPreviousEvent() != null) {
System.out.print(" previous event has key " + event.getPreviousEvent().getKey());
}
if (event.getNextEvent() != null) {
System.out.print(" next event has key " + event.getNextEvent().getKey());
}
System.out.println();
}
}
}
对于您的示例,此程序打印出:
Wed Jan 28 10:15:15 CET 2015: Event 382 next event has key 383
Wed Jan 28 10:15:18 CET 2015: Event 383 previous event has key 382