如何从 JSON table 中提取字典

Question

我正在使用机器人框架和请求库测试 REst API API 的 JSON 响应采用 table 的形式。我正在使用机器人框架来测试这个 API 我想把这个 table 分成字典，这样我就可以使用机器人框架关键字来测试响应。

这是我的 JSON 回复的示例：

[
  {
      locale: "fr_FR",
      day: "2015-12-01",
      displayPricePerPerson: 9800,
      displayTotalPrice: 9800,
      promotion: false,
      minLos: 1
},
{
      locale: "fr_FR",
      day: "2015-12-02",
      displayPricePerPerson: 9800,
      displayTotalPrice: 9800,
      promotion: false,
      minLos: 1
 },
[

理想情况下，我想以字典的形式提取整个响应，以便我可以遍历响应并断言键和值。

所以我不会将字典嵌入到 table 中，而是只有字典：

{
      locale: "fr_FR",
      day: "2015-12-01",
      displayPricePerPerson: 9800,
      displayTotalPrice: 9800,
      promotion: false,
      minLos: 1
},
{
      locale: "fr_FR",
      day: "2015-12-02",
      displayPricePerPerson: 9800,
      displayTotalPrice: 9800,
      promotion: false,
      minLos: 1
 },

我已尝试使用集合和请求库，但出现错误：

${JSON}=  To JSON  ${resp.content}
${DICT}=  Convert To List  ${JSON}
 Log  ${DICT}
:FOR  ${KEY}  IN  locale  day  displayPricePerPerson  displayTotalPrice  promotion  minLos
          \   Run Keyword And Continue On Failure  List Should Contain Value  ${JSON}  ${KEY}

Error : ValueError: dictionary update sequence element #0 has length 6; 2 is required

Answer 1

                you have dictionaries in your list already. though badly formed.they are missing quotes around the keys

                    lt = [
                      {
                          "locale": "fr_FR",
                          "day": "2015-12-01",
                          "displayPricePerPerson": 9800,
                          "displayTotalPrice": 9800,
                          "promotion": False,
                          "minLos": 1
                    },
                    {
                          "locale": "fr_FR",
                          "day": "2015-12-02",
                          "displayPricePerPerson": 9800,
                          "displayTotalPrice": 9800,
                          "promotion": False,
                          "minLos": 1
                     },
                    ]

                    for el in lt:
                        print(type(el))

                    <class 'dict'>
                    <class 'dict'>

                    d1 = lt[0]
                    d2 =lt[1]

                    print(d1.items())
                    dict_items([('day', '2015-12-01'), ('locale', 'fr_FR'), ('displayPricePerPerson', 9800), ('minLos', 1), ('promotion', False), ('displayTotalPrice', 9800)])

                    print(d2.items())
                    dict_items([('day', '2015-12-02'), ('locale', 'fr_FR'), ('displayPricePerPerson', 9800), ('minLos', 1), ('promotion', False), ('displayTotalPrice', 9800)])

                to convert to list of dicts this:
lt2 = '''[
    {
        locale: "fr_FR",
        day: "2015-12-01",
        displayPricePerPerson: 9800,
        displayTotalPrice: 9800,
        promotion: false,
        minLos: 1
    },
    {
        locale: "fr_FR",
        day: "2015-12-02",
        displayPricePerPerson: 9800,
        displayTotalPrice: 9800,
        promotion: false,
        minLos: 1
    },
]
'''

    def convert_ECMA_Javascript(st):
        # convert badly formed strings to json format
        import json

        result = re.sub(r'(\w+):',r'"":',st)
        result= re.sub(r'false',r'"False"',result)
        result= re.sub(r'true',r'"True"',result)
        result= re.sub(r'\[|\]',r'',result)
        result= re.sub(r'\b(\d+)\b(?!"|-)',r'""',result)
        result= re.sub(r'\n|\t',r'',result)
        li = re.findall(r'{.*?}', result)

        result = []
        for s in li:
            result.append(json.loads(s))

        return result

    pp(convert_ECMA_Javascript(lt2))

    [{'day': '2015-12-01',
      'displayPricePerPerson': '9800',
      'displayTotalPrice': '9800',
      'locale': 'fr_FR',
      'minLos': '1',
      'promotion': 'False'},
     {'day': '2015-12-02',
      'displayPricePerPerson': '9800',
      'displayTotalPrice': '9800',
      'locale': 'fr_FR',
      'minLos': '1',
      'promotion': 'False'}]

    for el in convert_ECMA_Javascript(lt2):
        for k,v in el.items():
            print(k,":", v)

    day : 2015-12-01
    displayPricePerPerson : 9800
    minLos : 1
    promotion : False
    displayTotalPrice : 9800
    locale : fr_FR
    day : 2015-12-02
    displayPricePerPerson : 9800
    minLos : 1
    promotion : False
    displayTotalPrice : 9800
    locale : fr_FR

Answer 2

假设实际数据有效JSON（问题中的数据无效），一旦您调用To JSON，返回的数据是一个字典列表，可以是迭代了。您应该能够在不进行任何进一步转换的情况下遍历它们。

例如：

${JSON}=    To JSON    ${resp.content}
:FOR    ${item}    IN    @{JSON}
    \  log    locale: ${item["locale"]}

以上将为 JSON 数据中的每个字典记录一行。

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