将文件上传到网络服务器 Delphi + php
Upload a file to web server Delphi + php
我正在开发一个程序,我需要将 'log.txt' 上传到网络服务器.. 通过 http
我已经搜索并找到了这个:-
Delphi 谢:
procedure TForm1.Button1Click(Sender: TObject);
begin
idhttp1.Post('http://127.0.0.1/GET2.php', 'C:\Users\Someone\Desktop\log.txt')
end;
php :-
<?php
$uploaddir = "uploads/";
$uploadfile = $uploaddir . basename( $_FILES['file']['name']);
if(move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile))
{
echo "The file has been uploaded successfully";
}
else
{
echo "There was an error uploading the file";
}
?>
但是没有文件上传
感谢您的帮助
阅读 PHP 文档。
您的 PHP 代码正在使用 $_FILES
,它希望客户端 post MIME multipart/form-data
格式的 HTML 网络表单:
Handling file uploads > POST method uploads
PHP is capable of receiving file uploads from any RFC-1867 compliant browser.
但是该格式并不是您的应用程序实际 posting 的格式。它只是 post 按原样处理原始文件内容,没有 MIME 元数据来描述文件。这就是为什么您的 PHP 代码不起作用。
要使用 TIdHTTP.Post()
post multipart/form-data
HTML 网络表单,您必须使用 TIdMultipartFormDataStream
class,例如:
uses
..., IdHTTP, IdMultipartFormDataStream;
procedure TForm1.Button1Click(Sender: TObject);
var
PostData: TIdMultipartFormDataStream;
begin
PostData := TIdMultipartFormDataStream.Create;
try
PostData.AddFile('file', 'C:\Users\Someone\Desktop\log.txt');
idhttp1.Post('http://127.0.0.1/GET2.php', PostData)
finally
PostData.Free;
end;
end;
另外,PHP 也支持 HTTP PUT
文件上传请求:
Handling file uploads > PUT method support
procedure TForm1.Button1Click(Sender: TObject);
var
FS: TFileStream;
begin
FS := TFileStream.Create('C:\Users\Someone\Desktop\log.txt', fmOpenRead or fmShareDenyWrite);
try
idhttp1.Put('http://127.0.0.1/log.txt', FS);
finally
FS.Free;
end;
end;
<?php
/* PUT data comes in on the stdin stream */
$putdata = fopen("php://input", "r");
/* Open a file for writing */
$fp = fopen("log.txt", "w");
/* Read the data 1 KB at a time
and write to the file */
while ($data = fread($putdata, 1024))
fwrite($fp, $data);
/* Close the streams */
fclose($fp);
fclose($putdata);
?>
我正在开发一个程序,我需要将 'log.txt' 上传到网络服务器.. 通过 http
我已经搜索并找到了这个:-
Delphi 谢:
procedure TForm1.Button1Click(Sender: TObject);
begin
idhttp1.Post('http://127.0.0.1/GET2.php', 'C:\Users\Someone\Desktop\log.txt')
end;
php :-
<?php
$uploaddir = "uploads/";
$uploadfile = $uploaddir . basename( $_FILES['file']['name']);
if(move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile))
{
echo "The file has been uploaded successfully";
}
else
{
echo "There was an error uploading the file";
}
?>
但是没有文件上传
感谢您的帮助
阅读 PHP 文档。
您的 PHP 代码正在使用 $_FILES
,它希望客户端 post MIME multipart/form-data
格式的 HTML 网络表单:
Handling file uploads > POST method uploads
PHP is capable of receiving file uploads from any RFC-1867 compliant browser.
但是该格式并不是您的应用程序实际 posting 的格式。它只是 post 按原样处理原始文件内容,没有 MIME 元数据来描述文件。这就是为什么您的 PHP 代码不起作用。
要使用 TIdHTTP.Post()
post multipart/form-data
HTML 网络表单,您必须使用 TIdMultipartFormDataStream
class,例如:
uses
..., IdHTTP, IdMultipartFormDataStream;
procedure TForm1.Button1Click(Sender: TObject);
var
PostData: TIdMultipartFormDataStream;
begin
PostData := TIdMultipartFormDataStream.Create;
try
PostData.AddFile('file', 'C:\Users\Someone\Desktop\log.txt');
idhttp1.Post('http://127.0.0.1/GET2.php', PostData)
finally
PostData.Free;
end;
end;
另外,PHP 也支持 HTTP PUT
文件上传请求:
Handling file uploads > PUT method support
procedure TForm1.Button1Click(Sender: TObject);
var
FS: TFileStream;
begin
FS := TFileStream.Create('C:\Users\Someone\Desktop\log.txt', fmOpenRead or fmShareDenyWrite);
try
idhttp1.Put('http://127.0.0.1/log.txt', FS);
finally
FS.Free;
end;
end;
<?php
/* PUT data comes in on the stdin stream */
$putdata = fopen("php://input", "r");
/* Open a file for writing */
$fp = fopen("log.txt", "w");
/* Read the data 1 KB at a time
and write to the file */
while ($data = fread($putdata, 1024))
fwrite($fp, $data);
/* Close the streams */
fclose($fp);
fclose($putdata);
?>