使用 Swift,如何使用 SHA1 创建 OpenSSL HMAC 摘要,然后使用严格的 encode64 进行编码
Using Swift, how can I create an OpenSSL HMAC digest using SHA1 and then encode with strict encode64
我需要使用 SHA1 创建 OpenSSL HMAC 摘要的 Base64 严格编码表示。我有 Ruby
中的代码,但我需要 Swift
中的类似代码。有人有那么简单吗?
Ruby
中的代码是:
digest = OpenSSL::Digest.new('sha1')
hmac_digest = OpenSSL::HMAC.digest(digest, secret_key, canonical_string)
Base64.strict_encode64(hmac_digest)
正如您在上面看到的,我的输入是 2 个字符串(secret_key
和 canonical_string
),我首先创建摘要然后对其进行编码。
那么,Swift
中对相同输入给出相同结果的正确代码是什么?
我创建了一个用于导入的桥接头 CommonCrypto.h
。
然后我用以下函数扩展了字符串:
enum HMACAlgorithm {
case MD5, SHA1, SHA224, SHA256, SHA384, SHA512
func toCCHmacAlgorithm() -> CCHmacAlgorithm {
var result: Int = 0
switch self {
case .MD5:
result = kCCHmacAlgMD5
case .SHA1:
result = kCCHmacAlgSHA1
case .SHA224:
result = kCCHmacAlgSHA224
case .SHA256:
result = kCCHmacAlgSHA256
case .SHA384:
result = kCCHmacAlgSHA384
case .SHA512:
result = kCCHmacAlgSHA512
}
return CCHmacAlgorithm(result)
}
func digestLength() -> Int {
var result: CInt = 0
switch self {
case .MD5:
result = CC_MD5_DIGEST_LENGTH
case .SHA1:
result = CC_SHA1_DIGEST_LENGTH
case .SHA224:
result = CC_SHA224_DIGEST_LENGTH
case .SHA256:
result = CC_SHA256_DIGEST_LENGTH
case .SHA384:
result = CC_SHA384_DIGEST_LENGTH
case .SHA512:
result = CC_SHA512_DIGEST_LENGTH
}
return Int(result)
}
}
extension String {
func hmac(algorithm: HMACAlgorithm, key: String) -> String {
let cKey = key.cStringUsingEncoding(NSUTF8StringEncoding)
let cData = self.cStringUsingEncoding(NSUTF8StringEncoding)
var result = [CUnsignedChar](count: Int(algorithm.digestLength()), repeatedValue: 0)
CCHmac(algorithm.toCCHmacAlgorithm(), cKey!, Int(strlen(cKey!)), cData!, Int(strlen(cData!)), &result)
let hmacData:NSData = NSData(bytes: result, length: (Int(algorithm.digestLength())))
let hmacBase64 = hmacData.base64EncodedStringWithOptions(NSDataBase64EncodingOptions.Encoding76CharacterLineLength)
return String(hmacBase64)
}
}
我需要使用 SHA1 创建 OpenSSL HMAC 摘要的 Base64 严格编码表示。我有 Ruby
中的代码,但我需要 Swift
中的类似代码。有人有那么简单吗?
Ruby
中的代码是:
digest = OpenSSL::Digest.new('sha1')
hmac_digest = OpenSSL::HMAC.digest(digest, secret_key, canonical_string)
Base64.strict_encode64(hmac_digest)
正如您在上面看到的,我的输入是 2 个字符串(secret_key
和 canonical_string
),我首先创建摘要然后对其进行编码。
那么,Swift
中对相同输入给出相同结果的正确代码是什么?
我创建了一个用于导入的桥接头 CommonCrypto.h
。
然后我用以下函数扩展了字符串:
enum HMACAlgorithm {
case MD5, SHA1, SHA224, SHA256, SHA384, SHA512
func toCCHmacAlgorithm() -> CCHmacAlgorithm {
var result: Int = 0
switch self {
case .MD5:
result = kCCHmacAlgMD5
case .SHA1:
result = kCCHmacAlgSHA1
case .SHA224:
result = kCCHmacAlgSHA224
case .SHA256:
result = kCCHmacAlgSHA256
case .SHA384:
result = kCCHmacAlgSHA384
case .SHA512:
result = kCCHmacAlgSHA512
}
return CCHmacAlgorithm(result)
}
func digestLength() -> Int {
var result: CInt = 0
switch self {
case .MD5:
result = CC_MD5_DIGEST_LENGTH
case .SHA1:
result = CC_SHA1_DIGEST_LENGTH
case .SHA224:
result = CC_SHA224_DIGEST_LENGTH
case .SHA256:
result = CC_SHA256_DIGEST_LENGTH
case .SHA384:
result = CC_SHA384_DIGEST_LENGTH
case .SHA512:
result = CC_SHA512_DIGEST_LENGTH
}
return Int(result)
}
}
extension String {
func hmac(algorithm: HMACAlgorithm, key: String) -> String {
let cKey = key.cStringUsingEncoding(NSUTF8StringEncoding)
let cData = self.cStringUsingEncoding(NSUTF8StringEncoding)
var result = [CUnsignedChar](count: Int(algorithm.digestLength()), repeatedValue: 0)
CCHmac(algorithm.toCCHmacAlgorithm(), cKey!, Int(strlen(cKey!)), cData!, Int(strlen(cData!)), &result)
let hmacData:NSData = NSData(bytes: result, length: (Int(algorithm.digestLength())))
let hmacBase64 = hmacData.base64EncodedStringWithOptions(NSDataBase64EncodingOptions.Encoding76CharacterLineLength)
return String(hmacBase64)
}
}