SELECT switch/replace 列的答案
SELECT switch/replace answer of a column
我是一名程序员,在 SQL 方面经验有限。但本质上我想做的是
SELECT * FROM yesnomaybe_table;
我的输出:
yesnomaybe
----------
0
1
2
1
我想要的输出:
yesnomaybe
----------
45
64
55
64
我像
一样调查过 CASE
SELECT yesnomaybe,
CASE WHEN yesnomaybe = 0 THEN 45
WHEN yesnomaybe = 1 THEN 64
ELSE 55
END
FROM yesnomaybe_table;
但我的输出是这样的:
yesnomaybe | case
-----------+------
0 | 45
1 | 64
2 | 55
1 | 64
我该如何解决这个问题?
你想要这样的东西:
SELECT
CASE WHEN yesnomaybe = 0 THEN 45
WHEN yesnomaybe = 1 THEN 64
ELSE 55
END as yesnomaybe
FROM yesnomaybe_table;
在您的示例中,您选择了 yesnomaybe,然后进行了没有名称的切换。
我是一名程序员,在 SQL 方面经验有限。但本质上我想做的是
SELECT * FROM yesnomaybe_table;
我的输出:
yesnomaybe
----------
0
1
2
1
我想要的输出:
yesnomaybe
----------
45
64
55
64
我像
一样调查过 CASESELECT yesnomaybe,
CASE WHEN yesnomaybe = 0 THEN 45
WHEN yesnomaybe = 1 THEN 64
ELSE 55
END
FROM yesnomaybe_table;
但我的输出是这样的:
yesnomaybe | case
-----------+------
0 | 45
1 | 64
2 | 55
1 | 64
我该如何解决这个问题?
你想要这样的东西:
SELECT
CASE WHEN yesnomaybe = 0 THEN 45
WHEN yesnomaybe = 1 THEN 64
ELSE 55
END as yesnomaybe
FROM yesnomaybe_table;
在您的示例中,您选择了 yesnomaybe,然后进行了没有名称的切换。