表单的视图数据应该是另一个实例 class 创建另一个实体的表单实例时出错

Question

尝试从另一个实体创建表单以传递到我的视图时出现以下错误。

在此上下文中我有两个实体 CourseGuide 和 CourseGuideRow，我想将 CourseGuideRowType 的表单视图传递到我的视图 - 我该怎么做？

The form's view data is expected to be an instance of class CRMPicco\CourseBundle\Entity\CourseGuide, but is an instance of class CRMPicco\CourseBundle\Entity\CourseGuideRow. You can avoid this error by setting the "data_class" option to null or by adding a view transformer that transforms an instance of class CRMPicco\CourseBundle\Entity\CourseGuideRow to an instance of CRMPicco\CourseBundle\Entity\CourseGuide.

这是我的控制器：

// CourseGuideController.php
public function viewAction(Request $request)
{
    if (!$courseId = $request->get('id')) {
        throw new NotFoundHttpException('No Course ID provided in ' . __METHOD__);
    }

    $resource = $this->get('crmpicco.repository.course_guide_row')->createNew();
    $form     = $this->getForm($resource);

    // ...

}

我的 Symfony FormBuilder class:

// CourseGuideRowType.php
use Sylius\Bundle\ResourceBundle\Form\Type\AbstractResourceType;
use Symfony\Component\Form\FormBuilderInterface;

class CourseGuideRowType extends AbstractResourceType
{
    /**
     * {@inheritdoc}
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('channel', 'crmpicco_channel_choice', array('data_class' => null))
            ->add('name', 'text')
            ->add('courses', 'text')
        ;
    }

    /**
     * @return string name
     */
    public function getName()
    {
        return 'crmpicco_course_guide_row';
    }
}

我已经尝试了其他地方提到的data_class => null建议，但这没有效果。

如果我这样通过 data_class：

$form     = $this->getForm($resource, array('data_class' => 'CRMPicco\CourseBundle\Entity\CourseGuideRow'));

然后我得到这个：

Neither the property "translations" nor one of the methods "getTranslations()", "translations()", "isTranslations()", "hasTranslations()", "__get()" exist and have public access in class "CRMPicco\CourseBundle\Entity\CourseGuideRow".

这是为什么？ CourseGuide 实体有翻译，但 CourseGuideRow.

没有

Answer 1

尝试在您的 FormType 中添加此函数：

public function configureOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults(array(
        'data_class' => 'YourBundle\Entity\YourEntity',
    ));
}

还有别忘了具体用途：

use Symfony\Component\OptionsResolver\OptionsResolver;

编辑

在原生 Symfony 中（带有 Form 组件）：

public function showAction()
{
    /.../
    $entity = new YourEntity();
    $form = $this->createForm('name_of_your_form_type', $entity); 

    # And the response:

    return $this->render('your_template.html.twig', ['form' => $form->createView()]);
}

表单的视图数据应该是另一个实例 class 创建另一个实体的表单实例时出错

The form's view data is expected to be an instance of another class error creating form instance of another entity

php

symfony

sylius