C语言打印字符的程序
Program that prints out characters in C
我创建了一个程序,要求用户输入一些文本。然后程序将每个字符输出到一个新行并说明该字母是元音字母还是标点符号。
我遇到的问题是当我 运行 程序时 - 当它输出元音字母或标点符号时,它会将它们打印两次。谁能帮忙?将不胜感激。
代码:
int _tmain(int argc, _TCHAR* argv[])
{
char string[200];
char n1;
printf("Enter some text: \n");
while ((n1 = getchar()) != '\n') {
if (n1 == 'a' || n1 == 'e' || n1 == 'i' || n1 == 'o' || n1 == 'u')
printf("\b%c is a lowercase Vowel\n", n1);
else if (n1 == 'A' || n1 == 'E' || n1 == 'I' || n1 == 'O' || n1 == 'U')
printf("\b%c is a uppercase Vowel\n", n1);
if (ispunct(n1))
printf("%c is punctuation\n", n1);
printf("%c\n", n1);
}
return 0;
}
这个:
if (ispunct(n1))
printf("%c is punctuation\n", n1);
printf("%c\n", n1);
应该是:
else if (ispunct(n1))
printf("%c is punctuation\n", n1);
else
printf("%c\n", n1);
我创建了一个程序,要求用户输入一些文本。然后程序将每个字符输出到一个新行并说明该字母是元音字母还是标点符号。
我遇到的问题是当我 运行 程序时 - 当它输出元音字母或标点符号时,它会将它们打印两次。谁能帮忙?将不胜感激。
代码:
int _tmain(int argc, _TCHAR* argv[])
{
char string[200];
char n1;
printf("Enter some text: \n");
while ((n1 = getchar()) != '\n') {
if (n1 == 'a' || n1 == 'e' || n1 == 'i' || n1 == 'o' || n1 == 'u')
printf("\b%c is a lowercase Vowel\n", n1);
else if (n1 == 'A' || n1 == 'E' || n1 == 'I' || n1 == 'O' || n1 == 'U')
printf("\b%c is a uppercase Vowel\n", n1);
if (ispunct(n1))
printf("%c is punctuation\n", n1);
printf("%c\n", n1);
}
return 0;
}
这个:
if (ispunct(n1))
printf("%c is punctuation\n", n1);
printf("%c\n", n1);
应该是:
else if (ispunct(n1))
printf("%c is punctuation\n", n1);
else
printf("%c\n", n1);