Shell 脚本大小写语法错误

Question

当我尝试运行以下内容时，我在 vi 中不断收到以下语法错误“意外标记‘case’附近的语法错误”：

 #!/bin/bash
if [ -z  ]
then
        NAME="Person"
elif [ -n  ]
then
        NAME=
fi

for NAME
case $NAME in
        "Alice") echo "$NAME is a member of the name group.";;
        "Bob") echo "$NAME is a member of the name group.";;
        "Charlie") echo "$NAME is a member of the name group.";;
        "Quan") echo "$NAME is a member of the name group.";;
        "Brandon") echo "$NAME is a member of the name group.";;
        *) echo "Sorry, That $NAME is not a member of the name group.";;
esac

Answer 1

for 循环条件不完整。

以this为例：

The for loop is a little bit different from other programming languages. Basically, it let's you iterate over a series of 'words' within a string.

一个例子：

for i in $( ls ); do
    echo item: $i
done

您需要在脚本中迭代 NAME。

EDIT 实际上，正如评论指出的那样，您甚至根本不需要代码中的 for 循环。你可以把它拿出来。但是如果你需要写一个专有的，请考虑到这一点。

Answer 2

#!/bin/bash
#Will also work with dash (/bin/sh)

#Shorter default-value assignment
#+ no need for an all-cap variable
name="" 
: "${name:=Person}"

#`for name` doesn't belong here
case "$name" in
        "Alice") echo "$name is a member of the name group.";;
        "Bob") echo "$name is a member of the name group.";;
        "Charlie") echo "$name is a member of the name group.";;
        "Quan") echo "$name is a member of the name group.";;
        "Brandon") echo "$name is a member of the name group.";;
        *) echo "Sorry, That $name is not a member of the name group.";;
esac

全大写变量通常用于：

从环境导出或继承的变量
配置 shell

如果两者都不适用，则无需全部大写。

默认情况下引用 "$variables" 是一个很好的做法，除非您特别希望在空白处进行拆分（或更准确地说 $IFS）。

Answer 3

只是语法错误，试试这个

#!/bin/bash
if [ -z  ]
then
        NAME="Person"
elif [ -n  ]
then
        NAME=
fi

case $NAME in
        "Alice") echo "$NAME is a member of the name group.";;
        "Bob") echo "$NAME is a member of the name group.";;
        "Charlie") echo "$NAME is a member of the name group.";;
        "Quan") echo "$NAME is a member of the name group.";;
        "Brandon") echo "$NAME is a member of the name group.";;
        *) echo "Sorry, That $NAME is not a member of the name group.";;
esac

Shell 脚本大小写语法错误

Shell Scripting Case syntax error

linux

bash

vi