Java 制作字符串 shorthand/No replace() 函数 allowed/static 方法

Question

我一直遇到某个代码问题，我必须创建一个接收字符串的方法并将 returns 字符串转换为 shorthand。我不被允许使用替换函数，我还不知道如何使用数组。

我必须按照这些标准来适应：

A.replace these four words: "and" with "&", "to" with "2", "you" with "u", and "for" with "4" whenever they appear as separate words within a sentence.

B.remove all vowels ('a', 'e', 'i', 'o', 'u'), whether lowercase or uppercase, unless the vowel appears by itself.

例如For I shall love you forever变成4 I shll lv u frvr

这是我正在编写的代码，我还没有开始，因为我不知道如何解决这个问题。

public static String shortHand(String str){
        /* strategy: 
         * take string length. do a for loop for each individual letter and then search for letters and, replace
         * with &, look for to, replace with 2, replace you w/ u, and then take out any vowels.
         */ 
      
      for(int i = str.length(); i < str.length(); i++){
           
           str.toLowerCase();
           
            
        }
       return "";
    }

如果我能找到一个使用辅助方法但不是强制性方法的解决方案，那将会很有帮助。

Answer 1

尝试使用 HashMap 来存储键值对。在您的问题中，将要替换的词存储为键，即 "and"，值应为“&”。

创建一组元音来检查它是否是元音。 试试下面的程序。

import java.util.HashMap;
import java.util.HashSet;
import java.util.Map;
import java.util.Set;

public class Test {

private static final Map<String, Character> keyMap = new HashMap<String, Character>(); // store key and value
private static final Set<Character> vowelSet = new HashSet<Character>(); // store vowel in set

static {
    keyMap.put("and", '&');
    keyMap.put("to", '2');
    keyMap.put("you", 'u');
    keyMap.put("for", '4');

    vowelSet.add('a');
    vowelSet.add('e');
    vowelSet.add('i');
    vowelSet.add('o');
    vowelSet.add('u');
}

public static void main(String[] args) {
    System.out.println(shortHand("For I shall love you forever"));
}

public static String shortHand(String str) {
    StringBuffer result = new StringBuffer();
    String[] strArr = str.split(" "); //seperate string  by the space
    for (int i = 0; i < strArr.length; i++) {
        String temp = strArr[i].toLowerCase();
        if (keyMap.containsKey(temp)) {//check in map eg. does it contains in the map then replace it with shorthand word.
            result.append(keyMap.get(temp));
            result.append(" ");
        } else {
            if (temp.length() == 1 && vowelSet.contains(temp.charAt(0))) {//if it is only a vowel
                result.append(temp);
                result.append(" ");
            } else {
                for (int j = 0; j < temp.length(); j++) {//check in every character if its vowel or not
                    if (!vowelSet.contains(temp.charAt(j))) {
                        result.append(temp.charAt(j));
                    }
                }
                result.append(" ");
            }
        }

    }
    return result.toString();
}
}

Java 制作字符串 shorthand/No replace() 函数 allowed/static 方法

Java Making a string shorthand/No replace() function allowed/static method

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static

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