Android SQLite 找不到存在的列
Android SQLite can't find column that exists
我正在创建一个 table 并在本地数据库 android 中使用插入或替换 sql 但它给我 error :
*
table employeeTable has no column named activationCode (code 1): , while compiling: insert or replace into
employeeTable(activationCode,userName,userType,lastSeen)VALUES
('6131313313' , 'testingcheck' , 'Employer' , 'Tue Oct 27 10:04:36
GMT+05:30 2015');
*
我的创建 table 代码:
sql = "CREATE TABLE " + EMPLOYEE_TABLE + "(" + COMMON_ID_COLUMN + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ ACTIVATION_CODE_COLUMN + "TEXT ," + USER_NAME_COLUMN + "TEXT ," + USER_TYPE_COLUMN + "TEXT,"+LAST_SEE_COLUMN + "Text);";
db.execSQL(sql);
}
我的插入或替换代码:
public void insertEmployeeDetails(String activationCode1 , String userName , String userType , String lastSeen) {
String sql1 = "insert or replace into " + EMPLOYEE_TABLE + "(" + ACTIVATION_CODE_COLUMN + " , " + USER_NAME_COLUMN + " , " +
USER_TYPE_COLUMN +" , "+ LAST_SEE_COLUMN + ")" + "VALUES ('" +activationCode1 +"' , '" + userName + "' , '" + userType + "' , '"+ lastSeen + "');";
getWritableDatabase().execSQL(sql1);
}
和回调代码:
myDbHelper.insertEmployeeDetails(employerConstants.activationCode,employerConstants.userName,
employerConstants.userType , employerConstants.lastSeenon);
列激活码存在但无法找出导致问题的原因?
让你的 sqliteHelperClass 扩展 SQLiteOpenHelper。
例子
public SqliteHelper extends SQLiteOpenHelper {
public static final int VERSION = 1;
public static final String NAME = "your db name";
public SqliteHelper(Context context) {
super(context, NAME, null, VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
// your db creates here
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// your db upgrade here
// ex) drop & create
}
}
有了这个帮手 class,
如果您需要升级数据库,只需更改 Version
值 + 1
希望对您有所帮助。
使用以下代码插入数据。
dataBase = getWritableDatabase();
cValues = new ContentValues();
cValues.put(ACTIVATION_CODE_COLUMN, activationCode1);
cValues.put(USER_NAME_COLUMN, userName);
cValues.put(USER_TYPE_COLUMN, userType);
cValues.put( LAST_SEE_COLUMN, lastSeen);
dataBase.insert(EMPLOYEE_TABLE, null, cValues);
dataBase.close();
您的创建查询也包含错误
sql = "CREATE TABLE " + EMPLOYEE_TABLE + "(" + COMMON_ID_COLUMN + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ ACTIVATION_CODE_COLUMN + " TEXT, " + USER_NAME_COLUMN + " TEXT , " + USER_TYPE_COLUMN + " TEXT, "+LAST_SEE_COLUMN + " Text);";
复制以上查询并替换为您的查询
欢迎评论
我认为问题出在您的创建查询中。试试这个 SQL 创建查询 Table
sql = "CREATE TABLE " + EMPLOYEE_TABLE + " ("
+ COMMON_ID_COLUMN + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ ACTIVATION_CODE_COLUMN + " TEXT, "
+ USER_NAME_COLUMN + " TEXT, "
+ USER_TYPE_COLUMN + " TEXT, "
+ LAST_SEE_COLUMN + " TEXT);";
然后卸载并安装该应用程序。它应该可以工作。
确保你在查询中也有适当的空格,你可以从你的模拟器中获取整个数据并检查哪里出了问题,我遇到了同样的问题然后我搜索并能够从我的模拟器中导出数据库之后我才知道由于查询中的空格,我的字段名称不正确,我使用的是 genymotion。需要的话我可以贴出模拟器导出数据的过程
我正在创建一个 table 并在本地数据库 android 中使用插入或替换 sql 但它给我 error :
*
table employeeTable has no column named activationCode (code 1): , while compiling: insert or replace into employeeTable(activationCode,userName,userType,lastSeen)VALUES ('6131313313' , 'testingcheck' , 'Employer' , 'Tue Oct 27 10:04:36 GMT+05:30 2015');
*
我的创建 table 代码:
sql = "CREATE TABLE " + EMPLOYEE_TABLE + "(" + COMMON_ID_COLUMN + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ ACTIVATION_CODE_COLUMN + "TEXT ," + USER_NAME_COLUMN + "TEXT ," + USER_TYPE_COLUMN + "TEXT,"+LAST_SEE_COLUMN + "Text);";
db.execSQL(sql);
}
我的插入或替换代码:
public void insertEmployeeDetails(String activationCode1 , String userName , String userType , String lastSeen) {
String sql1 = "insert or replace into " + EMPLOYEE_TABLE + "(" + ACTIVATION_CODE_COLUMN + " , " + USER_NAME_COLUMN + " , " +
USER_TYPE_COLUMN +" , "+ LAST_SEE_COLUMN + ")" + "VALUES ('" +activationCode1 +"' , '" + userName + "' , '" + userType + "' , '"+ lastSeen + "');";
getWritableDatabase().execSQL(sql1);
}
和回调代码:
myDbHelper.insertEmployeeDetails(employerConstants.activationCode,employerConstants.userName,
employerConstants.userType , employerConstants.lastSeenon);
列激活码存在但无法找出导致问题的原因?
让你的 sqliteHelperClass 扩展 SQLiteOpenHelper。
例子
public SqliteHelper extends SQLiteOpenHelper {
public static final int VERSION = 1;
public static final String NAME = "your db name";
public SqliteHelper(Context context) {
super(context, NAME, null, VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
// your db creates here
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
// your db upgrade here
// ex) drop & create
}
}
有了这个帮手 class,
如果您需要升级数据库,只需更改 Version
值 + 1
希望对您有所帮助。
使用以下代码插入数据。
dataBase = getWritableDatabase();
cValues = new ContentValues();
cValues.put(ACTIVATION_CODE_COLUMN, activationCode1);
cValues.put(USER_NAME_COLUMN, userName);
cValues.put(USER_TYPE_COLUMN, userType);
cValues.put( LAST_SEE_COLUMN, lastSeen);
dataBase.insert(EMPLOYEE_TABLE, null, cValues);
dataBase.close();
您的创建查询也包含错误
sql = "CREATE TABLE " + EMPLOYEE_TABLE + "(" + COMMON_ID_COLUMN + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ ACTIVATION_CODE_COLUMN + " TEXT, " + USER_NAME_COLUMN + " TEXT , " + USER_TYPE_COLUMN + " TEXT, "+LAST_SEE_COLUMN + " Text);";
复制以上查询并替换为您的查询 欢迎评论
我认为问题出在您的创建查询中。试试这个 SQL 创建查询 Table
sql = "CREATE TABLE " + EMPLOYEE_TABLE + " ("
+ COMMON_ID_COLUMN + " INTEGER PRIMARY KEY AUTOINCREMENT, "
+ ACTIVATION_CODE_COLUMN + " TEXT, "
+ USER_NAME_COLUMN + " TEXT, "
+ USER_TYPE_COLUMN + " TEXT, "
+ LAST_SEE_COLUMN + " TEXT);";
然后卸载并安装该应用程序。它应该可以工作。
确保你在查询中也有适当的空格,你可以从你的模拟器中获取整个数据并检查哪里出了问题,我遇到了同样的问题然后我搜索并能够从我的模拟器中导出数据库之后我才知道由于查询中的空格,我的字段名称不正确,我使用的是 genymotion。需要的话我可以贴出模拟器导出数据的过程