将退出代码从 Java 返回到 PL/SQL
Getting exit code from Java back to PL/SQL
我正在尝试将 Java 方法的退出代码返回到 PL/SQL。似乎总是有例外。我怎样才能找出异常
n是。我在 12c 运行。
SQL> CREATE OR REPLACE JAVA SOURCE NAMED UTLCMD AS
2 import java.lang.Runtime;
3 public class UTLCMD
4 {
5 public static int execute(String command)
6 {
7 int exitCode = 0;
8
9 try
10 {
11 Runtime rt = java.lang.Runtime.getRuntime();
12 Process proc = rt.exec(command);
13 exitCode = proc.waitFor();
14 }
15 catch(Exception e)
16 {
17 System.out.println(e.getMessage());
18 exitCode = 12;
19 }
20
21 return exitCode;
22 }
23 }
24 /
Java created.
SQL> CREATE OR REPLACE FUNCTION JavaRunShellCommand(
2 command IN VARCHAR2)
3 RETURN NUMBER
4 AS LANGUAGE JAVA
5 NAME 'UTLCMD.execute(java.lang.String) return oracle.sql.NUMBER';
6 /
Function created.
以下是尝试调用该方法的结果。
SQL> VARIABLE n NUMBER;
SQL> CALL JavaRunShellCommand('cmd.exe /C CALL C:\Users\pwatson\src\java\my.bat') INTO :n;
Call completed.
SQL> PRINT n
N
----------
12
SQL> CALL JavaRunShellCommand('cmd.exe /C EXIT /B 3') INTO :n;
Call completed.
SQL> PRINT n
N
----------
12
SQL> SELECT JavaRunShellCommand('cmd.exe /C CALL C:\Users\pwatson\src\java\my.bat') AS R FROM DUAL;
R
----------
12
SQL> SELECT JavaRunShellCommand('cmd.exe /C EXIT /B 3') AS R FROM DUAL;
R
----------
12
你得到了一个异常,因为你得到了 12 返回,但是你捕获了所有异常并且只用 System.out.println()
显示它们,并且 Java 控制台输出进入一个跟踪文件 - 你(或您的 DBA)将需要找到正确的文件并提取实际故障。
让异常抛出会更简单:
CREATE OR REPLACE JAVA SOURCE NAMED UTLCMD AS
import java.lang.Runtime;
public class UTLCMD
{
public static int execute(String command)
throws java.lang.InterruptedException, java.io.IOException
{
int exitCode = 0;
Runtime rt = java.lang.Runtime.getRuntime();
Process proc = rt.exec(command);
exitCode = proc.waitFor();
return exitCode;
}
}
/
如果我 运行 使用命令(在我的例子中是 Unix-y),那么我会看到真正的问题:
exec :n := JavaRunShellCommand('/bin/ls /tmp');
ORA-29532: Java call terminated by uncaught Java exception: java.security.AccessControlException: the Permission (java.io.FilePermission /bin/ls execute) has not been granted to Whosebug. The PL/SQL to grant this is dbms_java.grant_permission( 'Whosebug', 'SYS:java.io.FilePermission', '/bin/ls', 'execute' )
ORA-06512: at "Whosebug.JAVARUNSHELLCOMMAND", line 1
ORA-06512: at line 1
29532. 00000 - "Java call terminated by uncaught Java exception: %s"
*Cause: A Java exception or error was signaled and could not be
resolved by the Java code.
*Action: Modify Java code, if this behavior is not intended.
这与我按照您的方式尝试时在跟踪文件中看到的相同,但更容易访问。
如果我通过发出 dbms_java.grant_permission()
调用(作为 DBA)来解决我的问题,因为错误告诉我这样做并重新连接,它现在可以工作了:
exec :n := JavaRunShellCommand('/bin/ls /tmp');
anonymous block completed
print n
N
-
0
当然,您可能会遇到不同的异常,但在开始解决真正的问题之前,您需要找出它是什么。
问题是 oracle.exe 是 运行 作为 machine\oracle 用户并且在我的目录中没有权限。当我将所有内容移动到 C:\app\oracle\product.1.0\dbhome_1\BIN 时,它开始按预期工作。该解决方案来自 Oracle 社区站点。 https://community.oracle.com/thread/3669270
非常感谢所有提出建议的人。
我正在尝试将 Java 方法的退出代码返回到 PL/SQL。似乎总是有例外。我怎样才能找出异常 n是。我在 12c 运行。
SQL> CREATE OR REPLACE JAVA SOURCE NAMED UTLCMD AS
2 import java.lang.Runtime;
3 public class UTLCMD
4 {
5 public static int execute(String command)
6 {
7 int exitCode = 0;
8
9 try
10 {
11 Runtime rt = java.lang.Runtime.getRuntime();
12 Process proc = rt.exec(command);
13 exitCode = proc.waitFor();
14 }
15 catch(Exception e)
16 {
17 System.out.println(e.getMessage());
18 exitCode = 12;
19 }
20
21 return exitCode;
22 }
23 }
24 /
Java created.
SQL> CREATE OR REPLACE FUNCTION JavaRunShellCommand(
2 command IN VARCHAR2)
3 RETURN NUMBER
4 AS LANGUAGE JAVA
5 NAME 'UTLCMD.execute(java.lang.String) return oracle.sql.NUMBER';
6 /
Function created.
以下是尝试调用该方法的结果。
SQL> VARIABLE n NUMBER;
SQL> CALL JavaRunShellCommand('cmd.exe /C CALL C:\Users\pwatson\src\java\my.bat') INTO :n;
Call completed.
SQL> PRINT n
N
----------
12
SQL> CALL JavaRunShellCommand('cmd.exe /C EXIT /B 3') INTO :n;
Call completed.
SQL> PRINT n
N
----------
12
SQL> SELECT JavaRunShellCommand('cmd.exe /C CALL C:\Users\pwatson\src\java\my.bat') AS R FROM DUAL;
R
----------
12
SQL> SELECT JavaRunShellCommand('cmd.exe /C EXIT /B 3') AS R FROM DUAL;
R
----------
12
你得到了一个异常,因为你得到了 12 返回,但是你捕获了所有异常并且只用 System.out.println()
显示它们,并且 Java 控制台输出进入一个跟踪文件 - 你(或您的 DBA)将需要找到正确的文件并提取实际故障。
让异常抛出会更简单:
CREATE OR REPLACE JAVA SOURCE NAMED UTLCMD AS
import java.lang.Runtime;
public class UTLCMD
{
public static int execute(String command)
throws java.lang.InterruptedException, java.io.IOException
{
int exitCode = 0;
Runtime rt = java.lang.Runtime.getRuntime();
Process proc = rt.exec(command);
exitCode = proc.waitFor();
return exitCode;
}
}
/
如果我 运行 使用命令(在我的例子中是 Unix-y),那么我会看到真正的问题:
exec :n := JavaRunShellCommand('/bin/ls /tmp');
ORA-29532: Java call terminated by uncaught Java exception: java.security.AccessControlException: the Permission (java.io.FilePermission /bin/ls execute) has not been granted to Whosebug. The PL/SQL to grant this is dbms_java.grant_permission( 'Whosebug', 'SYS:java.io.FilePermission', '/bin/ls', 'execute' )
ORA-06512: at "Whosebug.JAVARUNSHELLCOMMAND", line 1
ORA-06512: at line 1
29532. 00000 - "Java call terminated by uncaught Java exception: %s"
*Cause: A Java exception or error was signaled and could not be
resolved by the Java code.
*Action: Modify Java code, if this behavior is not intended.
这与我按照您的方式尝试时在跟踪文件中看到的相同,但更容易访问。
如果我通过发出 dbms_java.grant_permission()
调用(作为 DBA)来解决我的问题,因为错误告诉我这样做并重新连接,它现在可以工作了:
exec :n := JavaRunShellCommand('/bin/ls /tmp');
anonymous block completed
print n
N
-
0
当然,您可能会遇到不同的异常,但在开始解决真正的问题之前,您需要找出它是什么。
问题是 oracle.exe 是 运行 作为 machine\oracle 用户并且在我的目录中没有权限。当我将所有内容移动到 C:\app\oracle\product.1.0\dbhome_1\BIN 时,它开始按预期工作。该解决方案来自 Oracle 社区站点。 https://community.oracle.com/thread/3669270
非常感谢所有提出建议的人。