SQL 查找原始数据，其中 fielda+1 = fieldb 的值

Question

我还在学习 - 感谢您的耐心等待...

让我们从数据集开始。

TRANID              CODE1                   CODE2
1232                1                       NULL
1233                NULL                    DR
1234                1                       NULL
1235                NULL                    SR

基本上，我需要一个查询，说明当 tranID 的代码 1 = 1 时，查找 TranID + 1（紧接的下一个 tranID）的代码 2 为 'SR'

此查询应返回以下内容：

TRANID, CODE1 (TRANID), CODE2(TRANID), TRANID+1, CODE1 (TRANID+1), CODE2 (TRANID+1) 上面的数据集看起来像：

1234, 1, NULL, 1235, NULL, SR

提前感谢您的帮助，如果您需要更多信息，请告诉我！

Answer 1

只需要在第一个 tranId 添加 1 的 tranId 上将您的 table 自身连接到自身。然后为每个连接添加 where 条件

SELECT * 
FROM MyTable A
JOIN MyTable B ON (A.TranID + 1) = B.TranID
WHERE A.Code1 = 1 AND B.Code2 = 'SR'

Answer 2

除了 JamieD77 的连接解决方案，您还可以尝试使用 OLAP 函数，根据实际数据，这可能更有效：

SELECT t.*,
   TRANID + 1 AS next_TRANID,
--   if there might be a gap between TRANIDs you can switch to this instead:
--   MIN(TRANID) OVER (ORDER BY TRANID ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING) AS next_TRANID,

   MIN(CODE1)  OVER (ORDER BY TRANID ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING) AS next_CODE1,
   MIN(CODE2)  OVER (ORDER BY TRANID ROWS BETWEEN 1 FOLLOWING AND 1 FOLLOWING) AS next_CODE2
FROM MyTable AS t
QUALIFY CODE1 = 1
    AND next_CODE2 = 'SR'

 -- if there might be a gap between TRANIDs 
 -- AND nextTRANID = TRANID + 1

SQL 查找原始数据，其中 fielda+1 = fieldb 的值

SQL Find original data and where fielda+1 = value of a fieldb

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