Android base64 编码的字符串无效？
Android base64 encoded string invalid?
我在解码 Base64 编码图像时遇到问题。
例如我从服务器得到以下字符串：
data:image\/jpg; base64,\/9j\/4AAQSkZJRgABAQEAYABgAAD\/2wBDAAIBAQIBAQICAgICAgICAwUDAwMDAwYEBAMFBwYHBwcGBwcICQ
sJCAgKCAcHCg0KCgsMDAwMBwkODw0MDgsMDAz\/2wBDAQICAgMDAwYDAwYMCAcIDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDA
wMDAwMDAwMDAwMDAwMDAz\/wAARCABFAOIDASIAAhEBAxEB\/8QAHwAAAQUBAQEBAQEAAAAAAAAAAAECAwQFBgcICQoL\/8QAtRAAAgEDAwIE
AwUFBAQAAAF9AQIDAAQRBRIhMUEGE1FhByJxFDKBkaEII0KxwRVS0fAkM2JyggkKFhcYGRolJicoKSo0NTY3ODk6Q0RFRkdISUpTVFVWV1hZW
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我在这里找到的 Online Tool 正确解码了该字符串，但代码
我在这里使用：
byte[] imageAsBytes = Base64.decode(imageString.getBytes(), Base64.DEFAULT);
Bitmap bitmap = BitmapFactory.decodeByteArray(imageAsBytes, 0, imageAsBytes.length);
产生错误：
02-02 19:16:56.460: E/AndroidRuntime(18237): java.lang.IllegalArgumentException: bad base-64
那么问题出在哪里呢？我想如果它不是有效的 Base64 编码字符串，我提供的 link 中的在线工具也无法解码它。
编辑
找到另一个 Online Tool 它告诉：
The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or an illegal character among the padding characters.
但它没有说明位置。我删除了填充 '=' 但它没有改变。
我不知道这是正确的解决方案，但就我而言，我从上面的响应中删除了 data:image\/jpg; base64, 的起始部分，它对我有用。这是不是编码数据部分的数据。
我在解码 Base64 编码图像时遇到问题。 例如我从服务器得到以下字符串：
data:image\/jpg; base64,\/9j\/4AAQSkZJRgABAQEAYABgAAD\/2wBDAAIBAQIBAQICAgICAgICAwUDAwMDAwYEBAMFBwYHBwcGBwcICQ
sJCAgKCAcHCg0KCgsMDAwMBwkODw0MDgsMDAz\/2wBDAQICAgMDAwYDAwYMCAcIDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDAwMDA
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A0Hff8Lx\/6hn\/kz\/8AY0f8Lx\/6hn\/kz\/8AY1wNFH\/Ed+Of+g7\/AMpUf\/lYf8SFeBP\/AEIv\/LrGf\/NB33\/C8f8AqGf+TP8A9j
R\/wvH\/AKhn\/kz\/APY1wNFH\/Ed+Of8AoO\/8pUf\/AJWH\/EhXgT\/0Iv8Ay6xn\/wA0Hff8Lx\/6hn\/kz\/8AY0f8Lx\/6hn\/kz\/8
AY1wNFH\/Ed+Of+g7\/AMpUf\/lYf8SFeBP\/AEIv\/LrGf\/NB33\/C8f8AqGf+TP8A9jR\/wvH\/AKhn\/kz\/APY1wNFH\/Ed+Of8AoO\/
8pUf\/AJWH\/EhXgT\/0Iv8Ay6xn\/wA0Hff8Lx\/6hn\/kz\/8AY1Bqvxi\/tPS7m2\/s7Z9oiaLd9ozt3AjONvvXEUVliPHDjavSlRq428Z
Jpr2dHZ6P\/l2dmX\/Qa8EcDiqWNwuSctSnKM4v6zi3aUWmnZ4hp2a2aa7hRRRX5Of1mFFFFABRRRQAUUUUAFFFFABRRRQAUUUUAFFFFABRRR
QAUUUUAFFFFABRRRQAUUUUAFFFFABRRRQAUUUUAFFFFABRRRQB\/9k=
我在这里找到的 Online Tool 正确解码了该字符串，但代码 我在这里使用：
byte[] imageAsBytes = Base64.decode(imageString.getBytes(), Base64.DEFAULT);
Bitmap bitmap = BitmapFactory.decodeByteArray(imageAsBytes, 0, imageAsBytes.length);
产生错误：
02-02 19:16:56.460: E/AndroidRuntime(18237): java.lang.IllegalArgumentException: bad base-64
那么问题出在哪里呢？我想如果它不是有效的 Base64 编码字符串，我提供的 link 中的在线工具也无法解码它。
编辑
找到另一个 Online Tool 它告诉：
The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or an illegal character among the padding characters.
但它没有说明位置。我删除了填充 '=' 但它没有改变。
我不知道这是正确的解决方案，但就我而言，我从上面的响应中删除了 data:image\/jpg; base64, 的起始部分，它对我有用。这是不是编码数据部分的数据。