Python 根据音频长度批量重命名目录中的 .WAV 文件的脚本

Python script to batch-rename .WAV files in a directory, based on audio length

我正在编写一个 Python 脚本来重命名目录中的一堆 .WAV 文件,并重命名它们,将音频文件的长度添加到文件名的开头。

到目前为止我得到的是:

import wave
import contextlib
import os


for file_name in os.listdir(os.getcwd()):
    if file_name.endswith(".wav") or file_name.endswith(".aiff"):
        with contextlib.closing(wave.open(file_name, 'r')) as f:
            frames = f.getnframes()
            rate = f.getframerate()
            duration = frames / float(rate)
            duration = int(duration)
            duration = str(duration)
            new_file_name = duration + " " + file_name
            print(file_name)
            os.rename(file_name, new_file_name)
    else:
        continue

但是我得到了这个错误:

PermissionError: [WinError 32] The process cannot access the file because it is being used by another process: 'TEMFX01-RisingLong001.wav' -> '15 TEMFX01-RisingLong001.wav'

如何让进程停止使用它以便重命名它?

谢谢!

编辑:真的很傻,只需要在 print(file_name).

之前添加 f.close()

不确定我是应该删除这个主题还是回答我自己的问题?

重命名前关闭wave。

import wave
import contextlib
import os


for file_name in os.listdir(os.getcwd()):
    if file_name.endswith(".wav") or file_name.endswith(".aiff"):
        with contextlib.closing(wave.open(file_name, 'r')) as f:
            frames = f.getnframes()
            rate = f.getframerate()
            duration = frames / float(rate)
            duration = int(duration)
            duration = str(duration)
            new_file_name = duration + " " + file_name
            print(file_name)
            wave.close()
            os.rename(file_name, new_file_name)
    else:
import wave
import contextlib
import os
count = 0

for file_name in os.listdir(os.getcwd()):
    if file_name.endswith(".wav") or file_name.endswith(".aiff"):
        count += 1
        with contextlib.closing(wave.open(file_name, 'r')) as f:
            frames = f.getnframes()
            rate = f.getframerate()
            duration = frames / float(rate)
            duration = int(duration)
            duration = str(duration)
            new_file_name = "audio" + str(count) + '.wav'
            print(file_name)
        os.rename(file_name, new_file_name)
    else:
        continue

此代码将解决问题