SQL 按字母数字顺序排序

SQL Sort by Alphanumerical Order

所以我在这里查看了几个不同的例子,但是 none 似乎对我有用。

这是我需要排序的示例:

Alpha #1
Beta #3
Charlie #2
Alpha #2
Charlie #1
Beta #2
Beta #1
Alpha #10

排序后我想要

Alpha #1
Alpha #2
Alpha #10
Beta #1
Beta #2
Beta #3
Charlie #1
Charlie #2

然而,当我使用以下查询时,Alpha #10 没有遵循所需的规则。

ORDER BY 
Case When IsNumeric(LEFT(MachineName,1)) = 1 
     Then CASE When IsNumeric(MachineName) = 1 
               Then Right(Replicate('0',20) + MachineName + '0', 20)
               Else Right(Replicate('0',20) + MachineName, 20) 
          END
     When IsNumeric(LEFT(MachineName,1)) = 0 
     Then Left(MachineName + Replicate('',21), 20)
End

我得到这个:

Alpha #1
Alpha #10
Alpha #2
...

我是 LEFTRIGHT 的新手,所以我可能做错了什么,所以非常感谢任何指导!

DECLARE @t TABLE(v VARCHAR(100))

INSERT INTO @t VALUES
('Alpha #1'),
('Beta #3'),
('Charlie #2'),
('Alpha #2'),
('Charlie #1'),
('Beta #2'),
('Beta #1'),
('Alpha #10'),
('Alpha #')

SELECT * FROM @t
ORDER BY CASE WHEN PATINDEX('%[0-9]%', v) > 1 THEN SUBSTRING(v, 1, PATINDEX('%[0-9]%', v) - 1) END, 
         CASE WHEN PATINDEX('%[0-9]%', v) > 1 THEN CAST(SUBSTRING(v, PATINDEX('%[0-9]%', v), LEN(v)) AS INT) END

输出:

Alpha #
Alpha #1
Alpha #2
Alpha #10
Beta #1
Beta #2
Beta #3
Charlie #1
Charlie #2