使用 WITH 关系不存在错误

Question

非常感谢我的帮助。我认为这是让我无法完成为期一周的项目的最后一个挑战。

我的错误：亚马逊无效操作：关系 "rentdotcomonly" 不存在；

我的代码：

WITH 
RentDotComOnly AS
(
  SELECT 
    distinct concat(DATE_PART(mm,archived_apartments.week),clean_zip) AS "monthlyzip",
    COUNT(distinct apt_unique_id) AS "rent_count_clean_zip", 
    -- AVG((low_price+high_price)/2) AS "rent_avg_price", 
    0.85*min(low_price) AS "rent_lower_bound", 
    1.15*max(high_price) AS "rent_upper_bound"
  FROM 
    archived_apartments 
  WHERE 
    source_type in (29,36,316) 
    AND week between '2015-07-06' and '2015-10-12' 
    AND is_house <> 1  
    AND archived_apartments.high_price <> 0 
  GROUP BY monthlyzip
),
AllRJData AS
(
  SELECT
    distinct concat(DATE_PART(mm,archived_apartments.week),clean_zip) AS "monthlyzip",
    COUNT(distinct apt_unique_id) AS "all_count_clean_zip"
    --, AVG((low_price+high_price)/2) AS "all_avg_price"
  FROM 
    archived_apartments 
  WHERE 
    week between '2015-07-06' and '2015-10-12' 
    AND is_house <> 1  
  GROUP BY monthlyzip
),
TrueComps AS
(
  SELECT
    distinct concat(DATE_PART(mm,archived_apartments.week),clean_zip) AS "monthlyzip",
    COUNT(distinct apt_unique_id) AS "true_comps"
   FROM
    archived_apartments
   WHERE
    week between '2015-07-06' and '2015-10-12' 
    AND is_house <> 1 
    AND archived_apartments.high_price <> 0 
    AND archived_apartments.low_price > RentDotComOnly.rent_lower_bound
    AND archived_apartments.low_price < RentDotComOnly.rent_upper_bound
    OR
    week between '2015-07-06' and '2015-10-12' 
    AND is_house <> 1 
    AND archived_apartments.high_price <> 0 
    AND archived_apartments.high_price > RentDotComOnly.rent_lower_bound
    AND archived_apartments.high_price < RentDotComOnly.rent_upper_bound
)

SELECT 
  distinct concat(DATE_PART(mm,archived_apartments.week),clean_zip) AS "monthlyzip",
  RentDotComOnly.rent_count_clean_zip AS "RentComOnly",
  AllRJData.all_count_clean_zip AS "Total",
  TrueComps.true_comps AS "TrueComps"
FROM
  archived_apartments 
JOIN AllRJData 
ON concat(DATE_PART(mm,archived_apartments.week),archived_apartments.clean_zip) = AllRJData.monthlyzip
JOIN RentDotComOnly
ON concat(DATE_PART(mm,archived_apartments.week),archived_apartments.clean_zip) = RentDotComOnly.monthlyzip
JOIN TrueComps
ON concat(DATE_PART(mm,archived_apartments.week),archived_apartments.clean_zip) = TrueComps.monthlyzip

GROUP BY AllRJData.monthlyzip
ORDER BY AllRJData.monthlyzip

Answer 1

变异问题

问题发生了变化。我还不清楚修改后的问题是什么

原题

原来的错误是：

 [Amazon](500310) Invalid operation: relation "rentdotcomonly" does not exist;

在 TrueComps 的原始定义中，您有：

TrueComps AS
(
  SELECT
    distinct concat(DATE_PART(mm,archived_apartments.week),clean_zip) AS "monthlyzip",
    COUNT(distinct apt_unique_id) AS "true_comps"
   FROM
    archived_apartments
   WHERE
    week between '2015-07-06' and '2015-10-12' 
    AND is_house <> 1 
    AND archived_apartments.high_price <> 0 
    AND archived_apartments.low_price > RentDotComOnly.rent_lower_bound
    AND archived_apartments.low_price < RentDotComOnly.rent_upper_bound

您没有在 FROM 子句中使用 RentDotComOnly。您需要列出它才能在此 CTE 中定义它。

使用 WITH 关系不存在错误

Relation does not exist error using WITH

sql

amazon-redshift

变异问题

原题