在字符 1 处遇到 "INSERT"，但预期为：["DELETE"、"SELECT"、"UPDATE"]

Question

我有一个插入 JPA 命名查询，如下所示。当我尝试使用实体管理器从我的 DAO 执行它时，出现以下错误。我正在使用 Apache OpenJPA，我无法确定此问题的根本原因。由于域对象的复杂性，我无法使用持久化方法。

在字符 1 处遇到 "INSERT"，但预期为：["DELETE"、"SELECT"、"UPDATE"].

@NamedQuery(
 name=IuaPersistenceConstants.QUERY_INSERT_AGREEMENT_ACKNOWLEDGEMENT,
 query="INSERT INTO AgreementAcknowledgement agrackn VALUES agrackn.id.agrmntCntntUrl = :agrmntCntntUrl, agrackn.id.prvsndUserSqn = :prvsndUserSqn, agrackn.id.prvsnUserEffD = :userEffDate, " +
 "agrackn.id.agrmntacknEffD = :agrmntacknEffD, agrackn.acknExpD = :acknExpD, agrackn.crtTs = :crtTs, agrackn.crtUidC = :crtUidC, agrackn.lstUpdtTs = :lstUpdtTs, agrackn.lstUpdtUidC = :lstUpdtUidC")


Query ackQuery =getEntityManager().createNamedQuery(IuaPersistenceConstants.QUERY_INSERT_AGREEMENT_ACKNOWLEDGEMENT);
 ackQuery.setParameter("agrmntCntntUrl", agreementDO.getAgreementURL());
 ackQuery.setParameter("agrmntacknEffD", agreementDO.getAgreementEffDate());
 ackQuery.setParameter("acknExpD", agreementDO.getAgreementExpDate());
 ackQuery.setParameter("prvsndUserSqn", userDO.getUserSequence());
 ackQuery.setParameter("userEffDate", userDO.getUserEffDate());
 ackQuery.setParameter("crtTs", new Date());
 ackQuery.setParameter("crtUidC", "WS");
 ackQuery.setParameter("lstUpdtTs", new Date());
 ackQuery.setParameter("lstUpdtUidC", "WS");
 ackQuery.executeUpdate();

Answer 1

OpenJPA doesn't seem to support JPQL "INSERT" queries。但这并不奇怪，因为 JPA 没有定义 INSERT 查询。它定义了 SELECT、UPDATE、DELETE 查询，仅此而已。请参阅 JPA 规范。这不是 SQL。

在字符 1 处遇到 "INSERT"，但预期为：["DELETE"、"SELECT"、"UPDATE"]

Encountered "INSERT" at character 1, but expected: ["DELETE", "SELECT", "UPDATE"]

java

oracle

hibernate

jpa

openjpa