boost dynamic_bitset 从 uint16 复制位

Question

我需要创建 24 位集。第一个 (0) 位必须由 bool 设置。和其他 (1 - 23) 我需要从 uint32 值

复制第一位

可以用dynamic_bitset吗？

我试过但错误的代码：

typedef boost::dynamic_bitset<unsigned char> DataType;
DataType bs(24, intValue);
bs.set(0, booleanValue);

Answer 1

左移：

    DataType bs(24, intValue);
    bs <<= 1;
    bs.set(0, boolValue);

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#include <boost/dynamic_bitset.hpp>
#include <iostream>
typedef boost::dynamic_bitset<unsigned char> DataType;

int main() {
    using namespace std; // for readability on SO
    cout << hex << showbase;

    uint32_t intValue = 0x666;
    cout << "input: " << intValue;

    DataType bs(24, intValue);

    cout << "\n#1: " << bs << " " << bs.to_ulong();

    bs <<= 1;
    cout << "\n#2: " << bs << " " << bs.to_ulong();

    bs.set(0, true);

    cout << "\n#3: " << bs << " " << bs.to_ulong();
}

打印：

input: 0x666
#1: 000000000000011001100110 0x666
#2: 000000000000110011001100 0xccc
#3: 000000000000110011001101 0xccd

Answer 2

所以，我设法用这种方式做到了，没有提升位集：

uint32_t buffer(0xAAAAAAAA);
buffer = buffer << 1;
buffer |= true << 0;

unsigned char newRecord[3];

newRecord[0] = buffer;
newRecord[1] = buffer << 8;
newRecord[2] = buffer << 16;

boost dynamic_bitset 从 uint16 复制位

boost dynamic_bitset copy bits from uint16

c++

boost

boost-dynamic-bitset